Optimal. Leaf size=605 \[ -\frac {(b d-a e)^3 x}{4 b^3}-\frac {(b d-a e)^2 (b c d+e-a c e) x}{8 b^3 c}-\frac {(b d-a e) (b c d+e-a c e)^2 x}{12 b^3 c^2}-\frac {(b c d+e-a c e)^3 x}{16 b^3 c^3}-\frac {(b d-a e)^2 (d+e x)^2}{16 b^2 e}-\frac {(b d-a e) (b c d+e-a c e) (d+e x)^2}{24 b^2 c e}-\frac {(b c d+e-a c e)^2 (d+e x)^2}{32 b^2 c^2 e}-\frac {(b d-a e) (d+e x)^3}{36 b e}-\frac {(b c d+e-a c e) (d+e x)^3}{48 b c e}-\frac {(d+e x)^4}{64 e}-\frac {(b d-a e)^2 (b c d+e-a c e)^2 \log (1-a c-b c x)}{8 b^4 c^2 e}-\frac {(b d-a e) (b c d+e-a c e)^3 \log (1-a c-b c x)}{12 b^4 c^3 e}-\frac {(b c d+e-a c e)^4 \log (1-a c-b c x)}{16 b^4 c^4 e}-\frac {(b d-a e)^3 (1-a c-b c x) \log (1-a c-b c x)}{4 b^4 c}+\frac {(b d-a e)^2 (d+e x)^2 \log (1-a c-b c x)}{8 b^2 e}+\frac {(b d-a e) (d+e x)^3 \log (1-a c-b c x)}{12 b e}+\frac {(d+e x)^4 \log (1-a c-b c x)}{16 e}-\frac {(b d-a e)^4 \text {PolyLog}(2,c (a+b x))}{4 b^4 e}+\frac {(d+e x)^4 \text {PolyLog}(2,c (a+b x))}{4 e} \]
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Rubi [A]
time = 0.42, antiderivative size = 605, normalized size of antiderivative = 1.00, number of steps
used = 16, number of rules used = 8, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.471, Rules used = {6733, 2465,
2436, 2332, 2440, 2438, 2442, 45} \begin {gather*} -\frac {(-a c e+b c d+e)^4 \log (-a c-b c x+1)}{16 b^4 c^4 e}-\frac {(b d-a e) (-a c e+b c d+e)^3 \log (-a c-b c x+1)}{12 b^4 c^3 e}-\frac {(b d-a e)^2 (-a c e+b c d+e)^2 \log (-a c-b c x+1)}{8 b^4 c^2 e}-\frac {(b d-a e)^4 \text {Li}_2(c (a+b x))}{4 b^4 e}-\frac {(-a c-b c x+1) (b d-a e)^3 \log (-a c-b c x+1)}{4 b^4 c}-\frac {x (-a c e+b c d+e)^3}{16 b^3 c^3}-\frac {x (b d-a e) (-a c e+b c d+e)^2}{12 b^3 c^2}-\frac {x (b d-a e)^2 (-a c e+b c d+e)}{8 b^3 c}-\frac {x (b d-a e)^3}{4 b^3}-\frac {(d+e x)^2 (-a c e+b c d+e)^2}{32 b^2 c^2 e}-\frac {(d+e x)^2 (b d-a e) (-a c e+b c d+e)}{24 b^2 c e}+\frac {(d+e x)^2 (b d-a e)^2 \log (-a c-b c x+1)}{8 b^2 e}-\frac {(d+e x)^2 (b d-a e)^2}{16 b^2 e}+\frac {(d+e x)^4 \text {Li}_2(c (a+b x))}{4 e}-\frac {(d+e x)^3 (-a c e+b c d+e)}{48 b c e}+\frac {(d+e x)^3 (b d-a e) \log (-a c-b c x+1)}{12 b e}+\frac {(d+e x)^4 \log (-a c-b c x+1)}{16 e}-\frac {(d+e x)^3 (b d-a e)}{36 b e}-\frac {(d+e x)^4}{64 e} \end {gather*}
Antiderivative was successfully verified.
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Rule 45
Rule 2332
Rule 2436
Rule 2438
Rule 2440
Rule 2442
Rule 2465
Rule 6733
Rubi steps
\begin {align*} \int (d+e x)^3 \text {Li}_2(c (a+b x)) \, dx &=\frac {(d+e x)^4 \text {Li}_2(c (a+b x))}{4 e}+\frac {b \int \frac {(d+e x)^4 \log (1-a c-b c x)}{a+b x} \, dx}{4 e}\\ &=\frac {(d+e x)^4 \text {Li}_2(c (a+b x))}{4 e}+\frac {b \int \left (\frac {e (b d-a e)^3 \log (1-a c-b c x)}{b^4}+\frac {(b d-a e)^4 \log (1-a c-b c x)}{b^4 (a+b x)}+\frac {e (b d-a e)^2 (d+e x) \log (1-a c-b c x)}{b^3}+\frac {e (b d-a e) (d+e x)^2 \log (1-a c-b c x)}{b^2}+\frac {e (d+e x)^3 \log (1-a c-b c x)}{b}\right ) \, dx}{4 e}\\ &=\frac {(d+e x)^4 \text {Li}_2(c (a+b x))}{4 e}+\frac {1}{4} \int (d+e x)^3 \log (1-a c-b c x) \, dx+\frac {(b d-a e) \int (d+e x)^2 \log (1-a c-b c x) \, dx}{4 b}+\frac {(b d-a e)^2 \int (d+e x) \log (1-a c-b c x) \, dx}{4 b^2}+\frac {(b d-a e)^3 \int \log (1-a c-b c x) \, dx}{4 b^3}+\frac {(b d-a e)^4 \int \frac {\log (1-a c-b c x)}{a+b x} \, dx}{4 b^3 e}\\ &=\frac {(b d-a e)^2 (d+e x)^2 \log (1-a c-b c x)}{8 b^2 e}+\frac {(b d-a e) (d+e x)^3 \log (1-a c-b c x)}{12 b e}+\frac {(d+e x)^4 \log (1-a c-b c x)}{16 e}+\frac {(d+e x)^4 \text {Li}_2(c (a+b x))}{4 e}+\frac {(b c) \int \frac {(d+e x)^4}{1-a c-b c x} \, dx}{16 e}+\frac {(c (b d-a e)) \int \frac {(d+e x)^3}{1-a c-b c x} \, dx}{12 e}+\frac {\left (c (b d-a e)^2\right ) \int \frac {(d+e x)^2}{1-a c-b c x} \, dx}{8 b e}-\frac {(b d-a e)^3 \text {Subst}(\int \log (x) \, dx,x,1-a c-b c x)}{4 b^4 c}+\frac {(b d-a e)^4 \text {Subst}\left (\int \frac {\log (1-c x)}{x} \, dx,x,a+b x\right )}{4 b^4 e}\\ &=-\frac {(b d-a e)^3 x}{4 b^3}-\frac {(b d-a e)^3 (1-a c-b c x) \log (1-a c-b c x)}{4 b^4 c}+\frac {(b d-a e)^2 (d+e x)^2 \log (1-a c-b c x)}{8 b^2 e}+\frac {(b d-a e) (d+e x)^3 \log (1-a c-b c x)}{12 b e}+\frac {(d+e x)^4 \log (1-a c-b c x)}{16 e}-\frac {(b d-a e)^4 \text {Li}_2(c (a+b x))}{4 b^4 e}+\frac {(d+e x)^4 \text {Li}_2(c (a+b x))}{4 e}+\frac {(b c) \int \left (-\frac {e (b c d+e-a c e)^3}{b^4 c^4}+\frac {(b c d+e-a c e)^4}{b^4 c^4 (1-a c-b c x)}-\frac {e (b c d+e-a c e)^2 (d+e x)}{b^3 c^3}-\frac {e (b c d+e-a c e) (d+e x)^2}{b^2 c^2}-\frac {e (d+e x)^3}{b c}\right ) \, dx}{16 e}+\frac {(c (b d-a e)) \int \left (-\frac {e (b c d+e-a c e)^2}{b^3 c^3}+\frac {(b c d+e-a c e)^3}{b^3 c^3 (1-a c-b c x)}-\frac {e (b c d+e-a c e) (d+e x)}{b^2 c^2}-\frac {e (d+e x)^2}{b c}\right ) \, dx}{12 e}+\frac {\left (c (b d-a e)^2\right ) \int \left (-\frac {e (b c d+e-a c e)}{b^2 c^2}+\frac {(b c d+e-a c e)^2}{b^2 c^2 (1-a c-b c x)}-\frac {e (d+e x)}{b c}\right ) \, dx}{8 b e}\\ &=-\frac {(b d-a e)^3 x}{4 b^3}-\frac {(b d-a e)^2 (b c d+e-a c e) x}{8 b^3 c}-\frac {(b d-a e) (b c d+e-a c e)^2 x}{12 b^3 c^2}-\frac {(b c d+e-a c e)^3 x}{16 b^3 c^3}-\frac {(b d-a e)^2 (d+e x)^2}{16 b^2 e}-\frac {(b d-a e) (b c d+e-a c e) (d+e x)^2}{24 b^2 c e}-\frac {(b c d+e-a c e)^2 (d+e x)^2}{32 b^2 c^2 e}-\frac {(b d-a e) (d+e x)^3}{36 b e}-\frac {(b c d+e-a c e) (d+e x)^3}{48 b c e}-\frac {(d+e x)^4}{64 e}-\frac {(b d-a e)^2 (b c d+e-a c e)^2 \log (1-a c-b c x)}{8 b^4 c^2 e}-\frac {(b d-a e) (b c d+e-a c e)^3 \log (1-a c-b c x)}{12 b^4 c^3 e}-\frac {(b c d+e-a c e)^4 \log (1-a c-b c x)}{16 b^4 c^4 e}-\frac {(b d-a e)^3 (1-a c-b c x) \log (1-a c-b c x)}{4 b^4 c}+\frac {(b d-a e)^2 (d+e x)^2 \log (1-a c-b c x)}{8 b^2 e}+\frac {(b d-a e) (d+e x)^3 \log (1-a c-b c x)}{12 b e}+\frac {(d+e x)^4 \log (1-a c-b c x)}{16 e}-\frac {(b d-a e)^4 \text {Li}_2(c (a+b x))}{4 b^4 e}+\frac {(d+e x)^4 \text {Li}_2(c (a+b x))}{4 e}\\ \end {align*}
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Mathematica [A]
time = 0.38, size = 485, normalized size = 0.80 \begin {gather*} \frac {12 e (-1+a c+b c x) \left (\left (3-13 a c+23 a^2 c^2-25 a^3 c^3\right ) e^2+b c e \left (8 \left (2-7 a c+11 a^2 c^2\right ) d+\left (3-10 a c+13 a^2 c^2\right ) e x\right )+b^3 c^3 x \left (36 d^2+16 d e x+3 e^2 x^2\right )+b^2 c^2 \left (-36 (-1+3 a c) d^2-8 (-2+5 a c) d e x+(3-7 a c) e^2 x^2\right )\right ) \log (1-a c-b c x)+b c \left (300 a^3 c^3 e^3 x-6 a^2 c^2 e^2 x (46 e+b c (176 d+13 e x))+4 a c \left (39 e^3 x+3 b c e^2 x (56 d+5 e x)+b^2 c^2 \left (-144 d^3+324 d^2 e x+60 d e^2 x^2+7 e^3 x^3\right )\right )-x \left (36 e^3+6 b c e^2 (32 d+3 e x)+12 b^2 c^2 e \left (36 d^2+8 d e x+e^2 x^2\right )+b^3 c^3 \left (576 d^3+216 d^2 e x+64 d e^2 x^2+9 e^3 x^3\right )\right )+576 b^2 c^2 d^3 (-1+a c+b c x) \log (1-c (a+b x))\right )-144 c^4 \left (-4 a b^3 d^3+6 a^2 b^2 d^2 e-4 a^3 b d e^2+a^4 e^3-b^4 x \left (4 d^3+6 d^2 e x+4 d e^2 x^2+e^3 x^3\right )\right ) \text {PolyLog}(2,c (a+b x))}{576 b^4 c^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(1145\) vs.
\(2(567)=1134\).
time = 0.80, size = 1146, normalized size = 1.89 Too large to display
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.28, size = 696, normalized size = 1.15 \begin {gather*} -\frac {{\left (4 \, a b^{3} d^{3} - 6 \, a^{2} b^{2} d^{2} e + 4 \, a^{3} b d e^{2} - a^{4} e^{3}\right )} {\left (\log \left (b c x + a c\right ) \log \left (-b c x - a c + 1\right ) + {\rm Li}_2\left (-b c x - a c + 1\right )\right )}}{4 \, b^{4}} - \frac {9 \, b^{4} c^{4} x^{4} e^{3} + 4 \, {\left (16 \, b^{4} c^{4} d e^{2} - 7 \, a b^{3} c^{4} e^{3} + 3 \, b^{3} c^{3} e^{3}\right )} x^{3} + 6 \, {\left (36 \, b^{4} c^{4} d^{2} e + 13 \, a^{2} b^{2} c^{4} e^{3} - 10 \, a b^{2} c^{3} e^{3} + 3 \, b^{2} c^{2} e^{3} - 8 \, {\left (5 \, a b^{3} c^{4} e^{2} - 2 \, b^{3} c^{3} e^{2}\right )} d\right )} x^{2} + 12 \, {\left (48 \, b^{4} c^{4} d^{3} - 25 \, a^{3} b c^{4} e^{3} + 23 \, a^{2} b c^{3} e^{3} - 13 \, a b c^{2} e^{3} - 36 \, {\left (3 \, a b^{3} c^{4} e - b^{3} c^{3} e\right )} d^{2} + 3 \, b c e^{3} + 8 \, {\left (11 \, a^{2} b^{2} c^{4} e^{2} - 7 \, a b^{2} c^{3} e^{2} + 2 \, b^{2} c^{2} e^{2}\right )} d\right )} x - 144 \, {\left (b^{4} c^{4} x^{4} e^{3} + 4 \, b^{4} c^{4} d x^{3} e^{2} + 6 \, b^{4} c^{4} d^{2} x^{2} e + 4 \, b^{4} c^{4} d^{3} x\right )} {\rm Li}_2\left (b c x + a c\right ) - 12 \, {\left (3 \, b^{4} c^{4} x^{4} e^{3} - 25 \, a^{4} c^{4} e^{3} + 48 \, a^{3} c^{3} e^{3} - 36 \, a^{2} c^{2} e^{3} + 48 \, {\left (a b^{3} c^{4} - b^{3} c^{3}\right )} d^{3} + 4 \, {\left (4 \, b^{4} c^{4} d e^{2} - a b^{3} c^{4} e^{3}\right )} x^{3} - 36 \, {\left (3 \, a^{2} b^{2} c^{4} e - 4 \, a b^{2} c^{3} e + b^{2} c^{2} e\right )} d^{2} + 6 \, {\left (6 \, b^{4} c^{4} d^{2} e - 4 \, a b^{3} c^{4} d e^{2} + a^{2} b^{2} c^{4} e^{3}\right )} x^{2} + 16 \, a c e^{3} + 8 \, {\left (11 \, a^{3} b c^{4} e^{2} - 18 \, a^{2} b c^{3} e^{2} + 9 \, a b c^{2} e^{2} - 2 \, b c e^{2}\right )} d + 12 \, {\left (4 \, b^{4} c^{4} d^{3} - 6 \, a b^{3} c^{4} d^{2} e + 4 \, a^{2} b^{2} c^{4} d e^{2} - a^{3} b c^{4} e^{3}\right )} x - 3 \, e^{3}\right )} \log \left (-b c x - a c + 1\right )}{576 \, b^{4} c^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.36, size = 625, normalized size = 1.03 \begin {gather*} -\frac {576 \, b^{4} c^{4} d^{3} x - 144 \, {\left (4 \, b^{4} c^{4} d^{3} x + 4 \, a b^{3} c^{4} d^{3} + {\left (b^{4} c^{4} x^{4} - a^{4} c^{4}\right )} e^{3} + 4 \, {\left (b^{4} c^{4} d x^{3} + a^{3} b c^{4} d\right )} e^{2} + 6 \, {\left (b^{4} c^{4} d^{2} x^{2} - a^{2} b^{2} c^{4} d^{2}\right )} e\right )} {\rm Li}_2\left (b c x + a c\right ) + {\left (9 \, b^{4} c^{4} x^{4} - 4 \, {\left (7 \, a b^{3} c^{4} - 3 \, b^{3} c^{3}\right )} x^{3} + 6 \, {\left (13 \, a^{2} b^{2} c^{4} - 10 \, a b^{2} c^{3} + 3 \, b^{2} c^{2}\right )} x^{2} - 12 \, {\left (25 \, a^{3} b c^{4} - 23 \, a^{2} b c^{3} + 13 \, a b c^{2} - 3 \, b c\right )} x\right )} e^{3} + 16 \, {\left (4 \, b^{4} c^{4} d x^{3} - 3 \, {\left (5 \, a b^{3} c^{4} - 2 \, b^{3} c^{3}\right )} d x^{2} + 6 \, {\left (11 \, a^{2} b^{2} c^{4} - 7 \, a b^{2} c^{3} + 2 \, b^{2} c^{2}\right )} d x\right )} e^{2} + 216 \, {\left (b^{4} c^{4} d^{2} x^{2} - 2 \, {\left (3 \, a b^{3} c^{4} - b^{3} c^{3}\right )} d^{2} x\right )} e - 12 \, {\left (48 \, b^{4} c^{4} d^{3} x + 48 \, {\left (a b^{3} c^{4} - b^{3} c^{3}\right )} d^{3} + {\left (3 \, b^{4} c^{4} x^{4} - 4 \, a b^{3} c^{4} x^{3} + 6 \, a^{2} b^{2} c^{4} x^{2} - 12 \, a^{3} b c^{4} x - 25 \, a^{4} c^{4} + 48 \, a^{3} c^{3} - 36 \, a^{2} c^{2} + 16 \, a c - 3\right )} e^{3} + 8 \, {\left (2 \, b^{4} c^{4} d x^{3} - 3 \, a b^{3} c^{4} d x^{2} + 6 \, a^{2} b^{2} c^{4} d x + {\left (11 \, a^{3} b c^{4} - 18 \, a^{2} b c^{3} + 9 \, a b c^{2} - 2 \, b c\right )} d\right )} e^{2} + 36 \, {\left (b^{4} c^{4} d^{2} x^{2} - 2 \, a b^{3} c^{4} d^{2} x - {\left (3 \, a^{2} b^{2} c^{4} - 4 \, a b^{2} c^{3} + b^{2} c^{2}\right )} d^{2}\right )} e\right )} \log \left (-b c x - a c + 1\right )}{576 \, b^{4} c^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 20.82, size = 1030, normalized size = 1.70 \begin {gather*} \begin {cases} 0 & \text {for}\: c = 0 \wedge \left (b = 0 \vee c = 0\right ) \\\left (d^{3} x + \frac {3 d^{2} e x^{2}}{2} + d e^{2} x^{3} + \frac {e^{3} x^{4}}{4}\right ) \operatorname {Li}_{2}\left (a c\right ) & \text {for}\: b = 0 \\\frac {25 a^{4} e^{3} \operatorname {Li}_{1}\left (a c + b c x\right )}{48 b^{4}} - \frac {a^{4} e^{3} \operatorname {Li}_{2}\left (a c + b c x\right )}{4 b^{4}} - \frac {11 a^{3} d e^{2} \operatorname {Li}_{1}\left (a c + b c x\right )}{6 b^{3}} + \frac {a^{3} d e^{2} \operatorname {Li}_{2}\left (a c + b c x\right )}{b^{3}} + \frac {a^{3} e^{3} x \operatorname {Li}_{1}\left (a c + b c x\right )}{4 b^{3}} + \frac {25 a^{3} e^{3} x}{48 b^{3}} - \frac {a^{3} e^{3} \operatorname {Li}_{1}\left (a c + b c x\right )}{b^{4} c} + \frac {9 a^{2} d^{2} e \operatorname {Li}_{1}\left (a c + b c x\right )}{4 b^{2}} - \frac {3 a^{2} d^{2} e \operatorname {Li}_{2}\left (a c + b c x\right )}{2 b^{2}} - \frac {a^{2} d e^{2} x \operatorname {Li}_{1}\left (a c + b c x\right )}{b^{2}} - \frac {11 a^{2} d e^{2} x}{6 b^{2}} - \frac {a^{2} e^{3} x^{2} \operatorname {Li}_{1}\left (a c + b c x\right )}{8 b^{2}} - \frac {13 a^{2} e^{3} x^{2}}{96 b^{2}} + \frac {3 a^{2} d e^{2} \operatorname {Li}_{1}\left (a c + b c x\right )}{b^{3} c} - \frac {23 a^{2} e^{3} x}{48 b^{3} c} + \frac {3 a^{2} e^{3} \operatorname {Li}_{1}\left (a c + b c x\right )}{4 b^{4} c^{2}} - \frac {a d^{3} \operatorname {Li}_{1}\left (a c + b c x\right )}{b} + \frac {a d^{3} \operatorname {Li}_{2}\left (a c + b c x\right )}{b} + \frac {3 a d^{2} e x \operatorname {Li}_{1}\left (a c + b c x\right )}{2 b} + \frac {9 a d^{2} e x}{4 b} + \frac {a d e^{2} x^{2} \operatorname {Li}_{1}\left (a c + b c x\right )}{2 b} + \frac {5 a d e^{2} x^{2}}{12 b} + \frac {a e^{3} x^{3} \operatorname {Li}_{1}\left (a c + b c x\right )}{12 b} + \frac {7 a e^{3} x^{3}}{144 b} - \frac {3 a d^{2} e \operatorname {Li}_{1}\left (a c + b c x\right )}{b^{2} c} + \frac {7 a d e^{2} x}{6 b^{2} c} + \frac {5 a e^{3} x^{2}}{48 b^{2} c} - \frac {3 a d e^{2} \operatorname {Li}_{1}\left (a c + b c x\right )}{2 b^{3} c^{2}} + \frac {13 a e^{3} x}{48 b^{3} c^{2}} - \frac {a e^{3} \operatorname {Li}_{1}\left (a c + b c x\right )}{3 b^{4} c^{3}} - d^{3} x \operatorname {Li}_{1}\left (a c + b c x\right ) + d^{3} x \operatorname {Li}_{2}\left (a c + b c x\right ) - d^{3} x - \frac {3 d^{2} e x^{2} \operatorname {Li}_{1}\left (a c + b c x\right )}{4} + \frac {3 d^{2} e x^{2} \operatorname {Li}_{2}\left (a c + b c x\right )}{2} - \frac {3 d^{2} e x^{2}}{8} - \frac {d e^{2} x^{3} \operatorname {Li}_{1}\left (a c + b c x\right )}{3} + d e^{2} x^{3} \operatorname {Li}_{2}\left (a c + b c x\right ) - \frac {d e^{2} x^{3}}{9} - \frac {e^{3} x^{4} \operatorname {Li}_{1}\left (a c + b c x\right )}{16} + \frac {e^{3} x^{4} \operatorname {Li}_{2}\left (a c + b c x\right )}{4} - \frac {e^{3} x^{4}}{64} + \frac {d^{3} \operatorname {Li}_{1}\left (a c + b c x\right )}{b c} - \frac {3 d^{2} e x}{4 b c} - \frac {d e^{2} x^{2}}{6 b c} - \frac {e^{3} x^{3}}{48 b c} + \frac {3 d^{2} e \operatorname {Li}_{1}\left (a c + b c x\right )}{4 b^{2} c^{2}} - \frac {d e^{2} x}{3 b^{2} c^{2}} - \frac {e^{3} x^{2}}{32 b^{2} c^{2}} + \frac {d e^{2} \operatorname {Li}_{1}\left (a c + b c x\right )}{3 b^{3} c^{3}} - \frac {e^{3} x}{16 b^{3} c^{3}} + \frac {e^{3} \operatorname {Li}_{1}\left (a c + b c x\right )}{16 b^{4} c^{4}} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \mathrm {polylog}\left (2,c\,\left (a+b\,x\right )\right )\,{\left (d+e\,x\right )}^3 \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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