3.2.66 \(\int \frac {\log (1-c x) \text {PolyLog}(2,c x)}{x^2} \, dx\) [166]

Optimal. Leaf size=111 \[ \frac {(1-c x) \log ^2(1-c x)}{x}+c \log (c x) \log ^2(1-c x)-2 c \text {PolyLog}(2,c x)+c \log (1-c x) \text {PolyLog}(2,c x)-\frac {\log (1-c x) \text {PolyLog}(2,c x)}{x}+2 c \log (1-c x) \text {PolyLog}(2,1-c x)-c \text {PolyLog}(3,c x)-2 c \text {PolyLog}(3,1-c x) \]

[Out]

(-c*x+1)*ln(-c*x+1)^2/x+c*ln(c*x)*ln(-c*x+1)^2-2*c*polylog(2,c*x)+c*ln(-c*x+1)*polylog(2,c*x)-ln(-c*x+1)*polyl
og(2,c*x)/x+2*c*ln(-c*x+1)*polylog(2,-c*x+1)-c*polylog(3,c*x)-2*c*polylog(3,-c*x+1)

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Rubi [A]
time = 0.11, antiderivative size = 111, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 13, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.812, Rules used = {6726, 2442, 36, 29, 31, 6738, 2444, 2438, 6724, 6731, 2443, 2481, 2421} \begin {gather*} -2 c \text {Li}_2(c x)-c \text {Li}_3(c x)-2 c \text {Li}_3(1-c x)+c \text {Li}_2(c x) \log (1-c x)-\frac {\text {Li}_2(c x) \log (1-c x)}{x}+2 c \text {Li}_2(1-c x) \log (1-c x)+\frac {(1-c x) \log ^2(1-c x)}{x}+c \log (c x) \log ^2(1-c x) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(Log[1 - c*x]*PolyLog[2, c*x])/x^2,x]

[Out]

((1 - c*x)*Log[1 - c*x]^2)/x + c*Log[c*x]*Log[1 - c*x]^2 - 2*c*PolyLog[2, c*x] + c*Log[1 - c*x]*PolyLog[2, c*x
] - (Log[1 - c*x]*PolyLog[2, c*x])/x + 2*c*Log[1 - c*x]*PolyLog[2, 1 - c*x] - c*PolyLog[3, c*x] - 2*c*PolyLog[
3, 1 - c*x]

Rule 29

Int[(x_)^(-1), x_Symbol] :> Simp[Log[x], x]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 36

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :> Dist[b/(b*c - a*d), Int[1/(a + b*x), x], x] -
Dist[d/(b*c - a*d), Int[1/(c + d*x), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0]

Rule 2421

Int[(Log[(d_.)*((e_) + (f_.)*(x_)^(m_.))]*((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.))/(x_), x_Symbol] :> Simp
[(-PolyLog[2, (-d)*f*x^m])*((a + b*Log[c*x^n])^p/m), x] + Dist[b*n*(p/m), Int[PolyLog[2, (-d)*f*x^m]*((a + b*L
og[c*x^n])^(p - 1)/x), x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IGtQ[p, 0] && EqQ[d*e, 1]

Rule 2438

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2, (-c)*e*x^n]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2442

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[(f + g*
x)^(q + 1)*((a + b*Log[c*(d + e*x)^n])/(g*(q + 1))), x] - Dist[b*e*(n/(g*(q + 1))), Int[(f + g*x)^(q + 1)/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*f - d*g, 0] && NeQ[q, -1]

Rule 2443

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[Log[e*((
f + g*x)/(e*f - d*g))]*((a + b*Log[c*(d + e*x)^n])^p/g), x] - Dist[b*e*n*(p/g), Int[Log[(e*(f + g*x))/(e*f - d
*g)]*((a + b*Log[c*(d + e*x)^n])^(p - 1)/(d + e*x)), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && NeQ[e*
f - d*g, 0] && IGtQ[p, 1]

Rule 2444

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)/((f_.) + (g_.)*(x_))^2, x_Symbol] :> Simp[(d + e
*x)*((a + b*Log[c*(d + e*x)^n])^p/((e*f - d*g)*(f + g*x))), x] - Dist[b*e*n*(p/(e*f - d*g)), Int[(a + b*Log[c*
(d + e*x)^n])^(p - 1)/(f + g*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && NeQ[e*f - d*g, 0] && GtQ[p, 0
]

Rule 2481

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_.) + Log[(h_.)*((i_.) + (j_.)*(x_))^(m_.)]*
(g_.))*((k_.) + (l_.)*(x_))^(r_.), x_Symbol] :> Dist[1/e, Subst[Int[(k*(x/d))^r*(a + b*Log[c*x^n])^p*(f + g*Lo
g[h*((e*i - d*j)/e + j*(x/e))^m]), x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, h, i, j, k, l, n, p, r},
x] && EqQ[e*k - d*l, 0]

Rule 6724

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rule 6726

Int[((d_.)*(x_))^(m_.)*PolyLog[n_, (a_.)*((b_.)*(x_)^(p_.))^(q_.)], x_Symbol] :> Simp[(d*x)^(m + 1)*(PolyLog[n
, a*(b*x^p)^q]/(d*(m + 1))), x] - Dist[p*(q/(m + 1)), Int[(d*x)^m*PolyLog[n - 1, a*(b*x^p)^q], x], x] /; FreeQ
[{a, b, d, m, p, q}, x] && NeQ[m, -1] && GtQ[n, 0]

Rule 6731

Int[PolyLog[2, (c_.)*((a_.) + (b_.)*(x_))]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[Log[1 - a*c - b*c*x]*(PolyL
og[2, c*(a + b*x)]/e), x] + Dist[b/e, Int[Log[1 - a*c - b*c*x]^2/(a + b*x), x], x] /; FreeQ[{a, b, c, d, e}, x
] && EqQ[c*(b*d - a*e) + e, 0]

Rule 6738

Int[((g_.) + Log[(f_.)*((d_.) + (e_.)*(x_))^(n_.)]*(h_.))*(x_)^(m_.)*PolyLog[2, (c_.)*((a_.) + (b_.)*(x_))], x
_Symbol] :> Simp[x^(m + 1)*(g + h*Log[f*(d + e*x)^n])*(PolyLog[2, c*(a + b*x)]/(m + 1)), x] + (Dist[b/(m + 1),
Int[ExpandIntegrand[(g + h*Log[f*(d + e*x)^n])*Log[1 - a*c - b*c*x], x^(m + 1)/(a + b*x), x], x], x] - Dist[e
*h*(n/(m + 1)), Int[ExpandIntegrand[PolyLog[2, c*(a + b*x)], x^(m + 1)/(d + e*x), x], x], x]) /; FreeQ[{a, b,
c, d, e, f, g, h, n}, x] && IntegerQ[m] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \frac {\log (1-c x) \text {Li}_2(c x)}{x^2} \, dx &=-\frac {\log (1-c x) \text {Li}_2(c x)}{x}-c \int \left (\frac {\text {Li}_2(c x)}{x}-\frac {c \text {Li}_2(c x)}{-1+c x}\right ) \, dx-\int \frac {\log ^2(1-c x)}{x^2} \, dx\\ &=\frac {(1-c x) \log ^2(1-c x)}{x}-\frac {\log (1-c x) \text {Li}_2(c x)}{x}-c \int \frac {\text {Li}_2(c x)}{x} \, dx+(2 c) \int \frac {\log (1-c x)}{x} \, dx+c^2 \int \frac {\text {Li}_2(c x)}{-1+c x} \, dx\\ &=\frac {(1-c x) \log ^2(1-c x)}{x}-2 c \text {Li}_2(c x)+c \log (1-c x) \text {Li}_2(c x)-\frac {\log (1-c x) \text {Li}_2(c x)}{x}-c \text {Li}_3(c x)+c \int \frac {\log ^2(1-c x)}{x} \, dx\\ &=\frac {(1-c x) \log ^2(1-c x)}{x}+c \log (c x) \log ^2(1-c x)-2 c \text {Li}_2(c x)+c \log (1-c x) \text {Li}_2(c x)-\frac {\log (1-c x) \text {Li}_2(c x)}{x}-c \text {Li}_3(c x)+\left (2 c^2\right ) \int \frac {\log (c x) \log (1-c x)}{1-c x} \, dx\\ &=\frac {(1-c x) \log ^2(1-c x)}{x}+c \log (c x) \log ^2(1-c x)-2 c \text {Li}_2(c x)+c \log (1-c x) \text {Li}_2(c x)-\frac {\log (1-c x) \text {Li}_2(c x)}{x}-c \text {Li}_3(c x)-(2 c) \text {Subst}\left (\int \frac {\log (x) \log \left (c \left (\frac {1}{c}-\frac {x}{c}\right )\right )}{x} \, dx,x,1-c x\right )\\ &=\frac {(1-c x) \log ^2(1-c x)}{x}+c \log (c x) \log ^2(1-c x)-2 c \text {Li}_2(c x)+c \log (1-c x) \text {Li}_2(c x)-\frac {\log (1-c x) \text {Li}_2(c x)}{x}+2 c \log (1-c x) \text {Li}_2(1-c x)-c \text {Li}_3(c x)-(2 c) \text {Subst}\left (\int \frac {\text {Li}_2(x)}{x} \, dx,x,1-c x\right )\\ &=\frac {(1-c x) \log ^2(1-c x)}{x}+c \log (c x) \log ^2(1-c x)-2 c \text {Li}_2(c x)+c \log (1-c x) \text {Li}_2(c x)-\frac {\log (1-c x) \text {Li}_2(c x)}{x}+2 c \log (1-c x) \text {Li}_2(1-c x)-c \text {Li}_3(c x)-2 c \text {Li}_3(1-c x)\\ \end {align*}

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Mathematica [A]
time = 0.10, size = 115, normalized size = 1.04 \begin {gather*} 2 c \log (c x) \log (1-c x)-c \log ^2(1-c x)+\frac {\log ^2(1-c x)}{x}+c \log (c x) \log ^2(1-c x)+\frac {(-1+c x) \log (1-c x) \text {PolyLog}(2,c x)}{x}+2 c (1+\log (1-c x)) \text {PolyLog}(2,1-c x)-c \text {PolyLog}(3,c x)-2 c \text {PolyLog}(3,1-c x) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(Log[1 - c*x]*PolyLog[2, c*x])/x^2,x]

[Out]

2*c*Log[c*x]*Log[1 - c*x] - c*Log[1 - c*x]^2 + Log[1 - c*x]^2/x + c*Log[c*x]*Log[1 - c*x]^2 + ((-1 + c*x)*Log[
1 - c*x]*PolyLog[2, c*x])/x + 2*c*(1 + Log[1 - c*x])*PolyLog[2, 1 - c*x] - c*PolyLog[3, c*x] - 2*c*PolyLog[3,
1 - c*x]

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Maple [F]
time = 0.04, size = 0, normalized size = 0.00 \[\int \frac {\ln \left (-c x +1\right ) \polylog \left (2, c x \right )}{x^{2}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(ln(-c*x+1)*polylog(2,c*x)/x^2,x)

[Out]

int(ln(-c*x+1)*polylog(2,c*x)/x^2,x)

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Maxima [A]
time = 0.31, size = 113, normalized size = 1.02 \begin {gather*} {\left (\log \left (c x\right ) \log \left (-c x + 1\right )^{2} + 2 \, {\rm Li}_2\left (-c x + 1\right ) \log \left (-c x + 1\right ) - 2 \, {\rm Li}_{3}(-c x + 1)\right )} c + 2 \, {\left (\log \left (c x\right ) \log \left (-c x + 1\right ) + {\rm Li}_2\left (-c x + 1\right )\right )} c - c {\rm Li}_{3}(c x) + \frac {{\left (c x - 1\right )} {\rm Li}_2\left (c x\right ) \log \left (-c x + 1\right ) - {\left (c x - 1\right )} \log \left (-c x + 1\right )^{2}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(-c*x+1)*polylog(2,c*x)/x^2,x, algorithm="maxima")

[Out]

(log(c*x)*log(-c*x + 1)^2 + 2*dilog(-c*x + 1)*log(-c*x + 1) - 2*polylog(3, -c*x + 1))*c + 2*(log(c*x)*log(-c*x
+ 1) + dilog(-c*x + 1))*c - c*polylog(3, c*x) + ((c*x - 1)*dilog(c*x)*log(-c*x + 1) - (c*x - 1)*log(-c*x + 1)
^2)/x

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(-c*x+1)*polylog(2,c*x)/x^2,x, algorithm="fricas")

[Out]

integral(dilog(c*x)*log(-c*x + 1)/x^2, x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\log {\left (- c x + 1 \right )} \operatorname {Li}_{2}\left (c x\right )}{x^{2}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(ln(-c*x+1)*polylog(2,c*x)/x**2,x)

[Out]

Integral(log(-c*x + 1)*polylog(2, c*x)/x**2, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(-c*x+1)*polylog(2,c*x)/x^2,x, algorithm="giac")

[Out]

integrate(dilog(c*x)*log(-c*x + 1)/x^2, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\ln \left (1-c\,x\right )\,\mathrm {polylog}\left (2,c\,x\right )}{x^2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((log(1 - c*x)*polylog(2, c*x))/x^2,x)

[Out]

int((log(1 - c*x)*polylog(2, c*x))/x^2, x)

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