Optimal. Leaf size=60 \[ \frac {x^2}{2}+\frac {\left (1-a x^2\right ) \log \left (1-a x^2\right )}{2 a}-\frac {1}{2} x^2 \text {PolyLog}\left (2,a x^2\right )+\frac {1}{2} x^2 \text {PolyLog}\left (3,a x^2\right ) \]
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Rubi [A]
time = 0.02, antiderivative size = 60, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.444, Rules used = {6726, 2504,
2436, 2332} \begin {gather*} -\frac {1}{2} x^2 \text {Li}_2\left (a x^2\right )+\frac {1}{2} x^2 \text {Li}_3\left (a x^2\right )+\frac {\left (1-a x^2\right ) \log \left (1-a x^2\right )}{2 a}+\frac {x^2}{2} \end {gather*}
Antiderivative was successfully verified.
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Rule 2332
Rule 2436
Rule 2504
Rule 6726
Rubi steps
\begin {align*} \int x \text {Li}_3\left (a x^2\right ) \, dx &=\frac {1}{2} x^2 \text {Li}_3\left (a x^2\right )-\int x \text {Li}_2\left (a x^2\right ) \, dx\\ &=-\frac {1}{2} x^2 \text {Li}_2\left (a x^2\right )+\frac {1}{2} x^2 \text {Li}_3\left (a x^2\right )-\int x \log \left (1-a x^2\right ) \, dx\\ &=-\frac {1}{2} x^2 \text {Li}_2\left (a x^2\right )+\frac {1}{2} x^2 \text {Li}_3\left (a x^2\right )-\frac {1}{2} \text {Subst}\left (\int \log (1-a x) \, dx,x,x^2\right )\\ &=-\frac {1}{2} x^2 \text {Li}_2\left (a x^2\right )+\frac {1}{2} x^2 \text {Li}_3\left (a x^2\right )+\frac {\text {Subst}\left (\int \log (x) \, dx,x,1-a x^2\right )}{2 a}\\ &=\frac {x^2}{2}+\frac {\left (1-a x^2\right ) \log \left (1-a x^2\right )}{2 a}-\frac {1}{2} x^2 \text {Li}_2\left (a x^2\right )+\frac {1}{2} x^2 \text {Li}_3\left (a x^2\right )\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 52, normalized size = 0.87 \begin {gather*} \frac {1}{2} x^2 \left (1-\log \left (1-a x^2\right )+\frac {\log \left (1-a x^2\right )}{a x^2}-\text {PolyLog}\left (2,a x^2\right )+\text {PolyLog}\left (3,a x^2\right )\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.06, size = 56, normalized size = 0.93
method | result | size |
meijerg | \(\frac {a \,x^{2}+\frac {\left (-2 a \,x^{2}+2\right ) \ln \left (-a \,x^{2}+1\right )}{2}-a \,x^{2} \polylog \left (2, a \,x^{2}\right )+a \,x^{2} \polylog \left (3, a \,x^{2}\right )}{2 a}\) | \(56\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.27, size = 53, normalized size = 0.88 \begin {gather*} -\frac {a x^{2} {\rm Li}_2\left (a x^{2}\right ) - a x^{2} {\rm Li}_{3}(a x^{2}) - a x^{2} + {\left (a x^{2} - 1\right )} \log \left (-a x^{2} + 1\right )}{2 \, a} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.46, size = 53, normalized size = 0.88 \begin {gather*} -\frac {a x^{2} {\rm Li}_2\left (a x^{2}\right ) - a x^{2} {\rm polylog}\left (3, a x^{2}\right ) - a x^{2} + {\left (a x^{2} - 1\right )} \log \left (-a x^{2} + 1\right )}{2 \, a} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x \operatorname {Li}_{3}\left (a x^{2}\right )\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.38, size = 57, normalized size = 0.95 \begin {gather*} \frac {x^2\,\mathrm {polylog}\left (3,a\,x^2\right )}{2}-\frac {x^2\,\mathrm {polylog}\left (2,a\,x^2\right )}{2}+\frac {\ln \left (a\,x^2-1\right )}{2\,a}-\frac {x^2\,\ln \left (1-a\,x^2\right )}{2}+\frac {x^2}{2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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