3.1.27 \(\int \frac {-5+2 x}{-2+3 x^2} \, dx\) [27]

Optimal. Leaf size=47 \[ \frac {1}{12} \left (4-5 \sqrt {6}\right ) \log \left (\sqrt {6}-3 x\right )+\frac {1}{12} \left (4+5 \sqrt {6}\right ) \log \left (\sqrt {6}+3 x\right ) \]

[Out]

1/12*ln(-3*x+6^(1/2))*(4-5*6^(1/2))+1/12*ln(3*x+6^(1/2))*(4+5*6^(1/2))

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Rubi [A]
time = 0.02, antiderivative size = 47, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {647, 31} \begin {gather*} \frac {1}{12} \left (4-5 \sqrt {6}\right ) \log \left (\sqrt {6}-3 x\right )+\frac {1}{12} \left (4+5 \sqrt {6}\right ) \log \left (3 x+\sqrt {6}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(-5 + 2*x)/(-2 + 3*x^2),x]

[Out]

((4 - 5*Sqrt[6])*Log[Sqrt[6] - 3*x])/12 + ((4 + 5*Sqrt[6])*Log[Sqrt[6] + 3*x])/12

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 647

Int[((d_) + (e_.)*(x_))/((a_) + (c_.)*(x_)^2), x_Symbol] :> With[{q = Rt[(-a)*c, 2]}, Dist[e/2 + c*(d/(2*q)),
Int[1/(-q + c*x), x], x] + Dist[e/2 - c*(d/(2*q)), Int[1/(q + c*x), x], x]] /; FreeQ[{a, c, d, e}, x] && NiceS
qrtQ[(-a)*c]

Rubi steps

\begin {align*} \int \frac {-5+2 x}{-2+3 x^2} \, dx &=\frac {1}{4} \left (4-5 \sqrt {6}\right ) \int \frac {1}{-\sqrt {6}+3 x} \, dx+\frac {1}{4} \left (4+5 \sqrt {6}\right ) \int \frac {1}{\sqrt {6}+3 x} \, dx\\ &=\frac {1}{12} \left (4-5 \sqrt {6}\right ) \log \left (\sqrt {6}-3 x\right )+\frac {1}{12} \left (4+5 \sqrt {6}\right ) \log \left (\sqrt {6}+3 x\right )\\ \end {align*}

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Mathematica [A]
time = 0.02, size = 47, normalized size = 1.00 \begin {gather*} \frac {1}{12} \left (4-5 \sqrt {6}\right ) \log \left (\sqrt {6}-3 x\right )+\frac {1}{12} \left (4+5 \sqrt {6}\right ) \log \left (\sqrt {6}+3 x\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(-5 + 2*x)/(-2 + 3*x^2),x]

[Out]

((4 - 5*Sqrt[6])*Log[Sqrt[6] - 3*x])/12 + ((4 + 5*Sqrt[6])*Log[Sqrt[6] + 3*x])/12

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Mathics [A]
time = 2.00, size = 35, normalized size = 0.74 \begin {gather*} \frac {\left (4-5 \sqrt {6}\right ) \text {Log}\left [-\frac {\sqrt {6}}{3}+x\right ]}{12}+\frac {\left (4+5 \sqrt {6}\right ) \text {Log}\left [\frac {\sqrt {6}}{3}+x\right ]}{12} \end {gather*}

Antiderivative was successfully verified.

[In]

mathics('Integrate[(2*x - 5)/(3*x^2 - 2),x]')

[Out]

(4 - 5 Sqrt[6]) Log[-Sqrt[6] / 3 + x] / 12 + (4 + 5 Sqrt[6]) Log[Sqrt[6] / 3 + x] / 12

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Maple [A]
time = 0.05, size = 24, normalized size = 0.51

method result size
default \(\frac {\ln \left (3 x^{2}-2\right )}{3}+\frac {5 \sqrt {6}\, \arctanh \left (\frac {x \sqrt {6}}{2}\right )}{6}\) \(24\)
meijerg \(\frac {5 \sqrt {6}\, \arctanh \left (\frac {x \sqrt {2}\, \sqrt {3}}{2}\right )}{6}+\frac {\ln \left (1-\frac {3 x^{2}}{2}\right )}{3}\) \(27\)
risch \(\frac {\ln \left (3 x +\sqrt {6}\right )}{3}+\frac {5 \ln \left (3 x +\sqrt {6}\right ) \sqrt {6}}{12}+\frac {\ln \left (3 x -\sqrt {6}\right )}{3}-\frac {5 \ln \left (3 x -\sqrt {6}\right ) \sqrt {6}}{12}\) \(52\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2*x-5)/(3*x^2-2),x,method=_RETURNVERBOSE)

[Out]

1/3*ln(3*x^2-2)+5/6*6^(1/2)*arctanh(1/2*x*6^(1/2))

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Maxima [A]
time = 0.35, size = 36, normalized size = 0.77 \begin {gather*} -\frac {5}{12} \, \sqrt {6} \log \left (\frac {3 \, x - \sqrt {6}}{3 \, x + \sqrt {6}}\right ) + \frac {1}{3} \, \log \left (3 \, x^{2} - 2\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-5+2*x)/(3*x^2-2),x, algorithm="maxima")

[Out]

-5/12*sqrt(6)*log((3*x - sqrt(6))/(3*x + sqrt(6))) + 1/3*log(3*x^2 - 2)

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Fricas [A]
time = 0.32, size = 40, normalized size = 0.85 \begin {gather*} \frac {5}{12} \, \sqrt {6} \log \left (\frac {3 \, x^{2} + 2 \, \sqrt {6} x + 2}{3 \, x^{2} - 2}\right ) + \frac {1}{3} \, \log \left (3 \, x^{2} - 2\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-5+2*x)/(3*x^2-2),x, algorithm="fricas")

[Out]

5/12*sqrt(6)*log((3*x^2 + 2*sqrt(6)*x + 2)/(3*x^2 - 2)) + 1/3*log(3*x^2 - 2)

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Sympy [A]
time = 0.06, size = 42, normalized size = 0.89 \begin {gather*} \left (\frac {1}{3} - \frac {5 \sqrt {6}}{12}\right ) \log {\left (x - \frac {\sqrt {6}}{3} \right )} + \left (\frac {1}{3} + \frac {5 \sqrt {6}}{12}\right ) \log {\left (x + \frac {\sqrt {6}}{3} \right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-5+2*x)/(3*x**2-2),x)

[Out]

(1/3 - 5*sqrt(6)/12)*log(x - sqrt(6)/3) + (1/3 + 5*sqrt(6)/12)*log(x + sqrt(6)/3)

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Giac [A]
time = 0.00, size = 51, normalized size = 1.09 \begin {gather*} \frac {1}{12} \left (-5 \sqrt {6}+4\right ) \ln \left |x-\frac {\sqrt {6}}{3}\right |+\frac {1}{12} \left (5 \sqrt {6}+4\right ) \ln \left |x+\frac {\sqrt {6}}{3}\right | \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-5+2*x)/(3*x^2-2),x)

[Out]

1/12*(5*sqrt(6) + 4)*log(abs(x + 1/3*sqrt(6))) - 1/12*(5*sqrt(6) - 4)*log(abs(x - 1/3*sqrt(6)))

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Mupad [B]
time = 0.13, size = 47, normalized size = 1.00 \begin {gather*} \frac {\ln \left (x-\frac {\sqrt {6}}{3}\right )}{3}+\frac {\ln \left (x+\frac {\sqrt {6}}{3}\right )}{3}-\frac {5\,\sqrt {6}\,\ln \left (x-\frac {\sqrt {6}}{3}\right )}{12}+\frac {5\,\sqrt {6}\,\ln \left (x+\frac {\sqrt {6}}{3}\right )}{12} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2*x - 5)/(3*x^2 - 2),x)

[Out]

log(x - 6^(1/2)/3)/3 + log(x + 6^(1/2)/3)/3 - (5*6^(1/2)*log(x - 6^(1/2)/3))/12 + (5*6^(1/2)*log(x + 6^(1/2)/3
))/12

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