Optimal. Leaf size=102 \[ \frac {\tan ^{-1}\left (\frac {1-\sqrt {\cos (2 x)}}{\sqrt {2} \sqrt [4]{\cos (2 x)}}\right )}{\sqrt {2}}-\frac {\tanh ^{-1}\left (\frac {1+\sqrt {\cos (2 x)}}{\sqrt {2} \sqrt [4]{\cos (2 x)}}\right )}{\sqrt {2}}+\frac {7}{4} \sqrt [4]{\cos (2 x)}-\frac {1}{5} \cos ^{\frac {5}{4}}(2 x)+\frac {1}{36} \cos ^{\frac {9}{4}}(2 x) \]
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Rubi [A]
time = 0.12, antiderivative size = 154, normalized size of antiderivative = 1.51, number of steps
used = 14, number of rules used = 10, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.667, Rules used = {4446, 457,
90, 65, 217, 1179, 642, 1176, 631, 210} \begin {gather*} \frac {1}{36} \cos ^{\frac {9}{4}}(2 x)-\frac {1}{5} \cos ^{\frac {5}{4}}(2 x)+\frac {7}{4} \sqrt [4]{\cos (2 x)}+\frac {\log \left (\sqrt {\cos (2 x)}-\sqrt {2} \sqrt [4]{\cos (2 x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\sqrt {\cos (2 x)}+\sqrt {2} \sqrt [4]{\cos (2 x)}+1\right )}{2 \sqrt {2}}+\frac {\tan ^{-1}\left (1-\sqrt {2} \sqrt [4]{\cos (2 x)}\right )}{\sqrt {2}}-\frac {\tan ^{-1}\left (\sqrt {2} \sqrt [4]{\cos (2 x)}+1\right )}{\sqrt {2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 65
Rule 90
Rule 210
Rule 217
Rule 457
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 4446
Rubi steps
\begin {align*} \int \frac {\sin ^6(x) \tan (x)}{\cos ^{\frac {3}{4}}(2 x)} \, dx &=-\text {Subst}\left (\int \frac {\left (1-x^2\right )^3}{x \left (-1+2 x^2\right )^{3/4}} \, dx,x,\cos (x)\right )\\ &=-\left (\frac {1}{2} \text {Subst}\left (\int \frac {(1-x)^3}{x (-1+2 x)^{3/4}} \, dx,x,\cos ^2(x)\right )\right )\\ &=-\left (\frac {1}{2} \text {Subst}\left (\int \left (-\frac {7}{4 (-1+2 x)^{3/4}}+\frac {1}{x (-1+2 x)^{3/4}}+\sqrt [4]{-1+2 x}-\frac {1}{4} (-1+2 x)^{5/4}\right ) \, dx,x,\cos ^2(x)\right )\right )\\ &=\frac {7}{4} \sqrt [4]{-1+2 \cos ^2(x)}-\frac {1}{5} \left (-1+2 \cos ^2(x)\right )^{5/4}+\frac {1}{36} \left (-1+2 \cos ^2(x)\right )^{9/4}-\frac {1}{2} \text {Subst}\left (\int \frac {1}{x (-1+2 x)^{3/4}} \, dx,x,\cos ^2(x)\right )\\ &=\frac {7}{4} \sqrt [4]{-1+2 \cos ^2(x)}-\frac {1}{5} \left (-1+2 \cos ^2(x)\right )^{5/4}+\frac {1}{36} \left (-1+2 \cos ^2(x)\right )^{9/4}-\text {Subst}\left (\int \frac {1}{\frac {1}{2}+\frac {x^4}{2}} \, dx,x,\sqrt [4]{-1+2 \cos ^2(x)}\right )\\ &=\frac {7}{4} \sqrt [4]{-1+2 \cos ^2(x)}-\frac {1}{5} \left (-1+2 \cos ^2(x)\right )^{5/4}+\frac {1}{36} \left (-1+2 \cos ^2(x)\right )^{9/4}-\frac {1}{2} \text {Subst}\left (\int \frac {1-x^2}{\frac {1}{2}+\frac {x^4}{2}} \, dx,x,\sqrt [4]{-1+2 \cos ^2(x)}\right )-\frac {1}{2} \text {Subst}\left (\int \frac {1+x^2}{\frac {1}{2}+\frac {x^4}{2}} \, dx,x,\sqrt [4]{-1+2 \cos ^2(x)}\right )\\ &=\frac {7}{4} \sqrt [4]{-1+2 \cos ^2(x)}-\frac {1}{5} \left (-1+2 \cos ^2(x)\right )^{5/4}+\frac {1}{36} \left (-1+2 \cos ^2(x)\right )^{9/4}-\frac {1}{2} \text {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\sqrt [4]{-1+2 \cos ^2(x)}\right )-\frac {1}{2} \text {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\sqrt [4]{-1+2 \cos ^2(x)}\right )+\frac {\text {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\sqrt [4]{-1+2 \cos ^2(x)}\right )}{2 \sqrt {2}}+\frac {\text {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\sqrt [4]{-1+2 \cos ^2(x)}\right )}{2 \sqrt {2}}\\ &=\frac {7}{4} \sqrt [4]{-1+2 \cos ^2(x)}-\frac {1}{5} \left (-1+2 \cos ^2(x)\right )^{5/4}+\frac {1}{36} \left (-1+2 \cos ^2(x)\right )^{9/4}+\frac {\log \left (1-\sqrt {2} \sqrt [4]{-1+2 \cos ^2(x)}+\sqrt {-1+2 \cos ^2(x)}\right )}{2 \sqrt {2}}-\frac {\log \left (1+\sqrt {2} \sqrt [4]{-1+2 \cos ^2(x)}+\sqrt {-1+2 \cos ^2(x)}\right )}{2 \sqrt {2}}-\frac {\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\sqrt {2} \sqrt [4]{-1+2 \cos ^2(x)}\right )}{\sqrt {2}}+\frac {\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\sqrt {2} \sqrt [4]{-1+2 \cos ^2(x)}\right )}{\sqrt {2}}\\ &=\frac {\tan ^{-1}\left (1-\sqrt {2} \sqrt [4]{-1+2 \cos ^2(x)}\right )}{\sqrt {2}}-\frac {\tan ^{-1}\left (1+\sqrt {2} \sqrt [4]{-1+2 \cos ^2(x)}\right )}{\sqrt {2}}+\frac {7}{4} \sqrt [4]{-1+2 \cos ^2(x)}-\frac {1}{5} \left (-1+2 \cos ^2(x)\right )^{5/4}+\frac {1}{36} \left (-1+2 \cos ^2(x)\right )^{9/4}+\frac {\log \left (1-\sqrt {2} \sqrt [4]{-1+2 \cos ^2(x)}+\sqrt {-1+2 \cos ^2(x)}\right )}{2 \sqrt {2}}-\frac {\log \left (1+\sqrt {2} \sqrt [4]{-1+2 \cos ^2(x)}+\sqrt {-1+2 \cos ^2(x)}\right )}{2 \sqrt {2}}\\ \end {align*}
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Mathematica [A]
time = 0.08, size = 153, normalized size = 1.50 \begin {gather*} \frac {1}{360} \left (180 \sqrt {2} \tan ^{-1}\left (1-\sqrt {2} \sqrt [4]{\cos (2 x)}\right )-180 \sqrt {2} \tan ^{-1}\left (1+\sqrt {2} \sqrt [4]{\cos (2 x)}\right )+635 \sqrt [4]{\cos (2 x)}-72 \cos ^{\frac {5}{4}}(2 x)+5 \sqrt [4]{\cos (2 x)} \cos (4 x)+90 \sqrt {2} \log \left (1-\sqrt {2} \sqrt [4]{\cos (2 x)}+\sqrt {\cos (2 x)}\right )-90 \sqrt {2} \log \left (1+\sqrt {2} \sqrt [4]{\cos (2 x)}+\sqrt {\cos (2 x)}\right )\right ) \end {gather*}
Antiderivative was successfully verified.
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Mathics [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 0.31, size = 0, normalized size = 0.00 \[\int \frac {\left (\sin ^{6}\left (x \right )\right ) \tan \left (x \right )}{\cos \left (2 x \right )^{\frac {3}{4}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 166 vs.
\(2 (75) = 150\).
time = 0.01, size = 244, normalized size = 2.39 \begin {gather*} \frac {1}{4} \sqrt {2} \ln \left (\sqrt {-2 \sin ^{2}x+1}-\sqrt {2} \left (-2 \sin ^{2}x+1\right )^{\frac {1}{4}}+1\right )-\frac {1}{2} \sqrt {2} \arctan \left (\frac {2 \left (\left (-2 \sin ^{2}x+1\right )^{\frac {1}{4}}-\frac {\sqrt {2}}{2}\right )}{\sqrt {2}}\right )-\frac {1}{4} \sqrt {2} \ln \left (\sqrt {-2 \sin ^{2}x+1}+\sqrt {2} \left (-2 \sin ^{2}x+1\right )^{\frac {1}{4}}+1\right )-\frac {1}{2} \sqrt {2} \arctan \left (\frac {2 \left (\left (-2 \sin ^{2}x+1\right )^{\frac {1}{4}}+\frac {\sqrt {2}}{2}\right )}{\sqrt {2}}\right )+\frac {\frac {65536}{9} \left (-2 \sin ^{2}x+1\right )^{\frac {1}{4}} \left (-2 \sin ^{2}x+1\right )^{2}-\frac {262144}{5} \left (-2 \sin ^{2}x+1\right )^{\frac {1}{4}} \left (-2 \sin ^{2}x+1\right )+458752 \left (-2 \sin ^{2}x+1\right )^{\frac {1}{4}}}{262144} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\sin \left (x\right )}^6\,\mathrm {tan}\left (x\right )}{{\cos \left (2\,x\right )}^{3/4}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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