3.1.90 \(\int \frac {1-\sqrt {3}+x}{(1+\sqrt {3}+x) \sqrt {-4+4 \sqrt {3} x^2+x^4}} \, dx\) [90]

Optimal. Leaf size=65 \[ \frac {1}{3} \sqrt {-3+2 \sqrt {3}} \tanh ^{-1}\left (\frac {\left (1-\sqrt {3}+x\right )^2}{\sqrt {3 \left (-3+2 \sqrt {3}\right )} \sqrt {-4+4 \sqrt {3} x^2+x^4}}\right ) \]

[Out]

1/3*arctanh((1+x-3^(1/2))^2/(-9+6*3^(1/2))^(1/2)/(-4+x^4+4*3^(1/2)*x^2)^(1/2))*(-3+2*3^(1/2))^(1/2)

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Rubi [A]
time = 0.08, antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 40, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {1754, 213} \begin {gather*} \frac {1}{3} \sqrt {2 \sqrt {3}-3} \tanh ^{-1}\left (\frac {\left (x-\sqrt {3}+1\right )^2}{\sqrt {3 \left (2 \sqrt {3}-3\right )} \sqrt {x^4+4 \sqrt {3} x^2-4}}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 - Sqrt[3] + x)/((1 + Sqrt[3] + x)*Sqrt[-4 + 4*Sqrt[3]*x^2 + x^4]),x]

[Out]

(Sqrt[-3 + 2*Sqrt[3]]*ArcTanh[(1 - Sqrt[3] + x)^2/(Sqrt[3*(-3 + 2*Sqrt[3])]*Sqrt[-4 + 4*Sqrt[3]*x^2 + x^4])])/
3

Rule 213

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[b, 2])^(-1))*ArcTanh[Rt[b, 2]*(x/Rt[-a, 2])]
, x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 1754

Int[((A_) + (B_.)*(x_))/(((d_) + (e_.)*(x_))*Sqrt[(a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4]), x_Symbol] :> Dist[(-A^
2)*((B*d + A*e)/e), Subst[Int[1/(6*A^3*B*d + 3*A^4*e - a*e*x^2), x], x, (A + B*x)^2/Sqrt[a + b*x^2 + c*x^4]],
x] /; FreeQ[{a, b, c, d, e, A, B}, x] && NeQ[B*d - A*e, 0] && EqQ[c^2*d^6 + a*e^4*(13*c*d^2 + b*e^2), 0] && Eq
Q[b^2*e^4 - 12*c*d^2*(c*d^2 - b*e^2), 0] && EqQ[4*A*c*d*e + B*(2*c*d^2 - b*e^2), 0]

Rubi steps

\begin {align*} \int \frac {1-\sqrt {3}+x}{\left (1+\sqrt {3}+x\right ) \sqrt {-4+4 \sqrt {3} x^2+x^4}} \, dx &=-\left (\left (4 \left (2-\sqrt {3}\right )\right ) \text {Subst}\left (\int \frac {1}{3 \left (1-\sqrt {3}\right )^4+6 \left (1-\sqrt {3}\right )^3 \left (1+\sqrt {3}\right )+4 x^2} \, dx,x,\frac {\left (1-\sqrt {3}+x\right )^2}{\sqrt {-4+4 \sqrt {3} x^2+x^4}}\right )\right )\\ &=\frac {1}{3} \sqrt {-3+2 \sqrt {3}} \tanh ^{-1}\left (\frac {\left (1-\sqrt {3}+x\right )^2}{\sqrt {3 \left (-3+2 \sqrt {3}\right )} \sqrt {-4+4 \sqrt {3} x^2+x^4}}\right )\\ \end {align*}

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Mathematica [A]
time = 8.08, size = 77, normalized size = 1.18 \begin {gather*} \frac {1}{3} \sqrt {-3+2 \sqrt {3}} \tanh ^{-1}\left (\frac {\sqrt {9+6 \sqrt {3}} \sqrt {-4+4 \sqrt {3} x^2+x^4}}{2+\left (-2-2 \sqrt {3}\right ) x+\left (2+\sqrt {3}\right ) x^2}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1 - Sqrt[3] + x)/((1 + Sqrt[3] + x)*Sqrt[-4 + 4*Sqrt[3]*x^2 + x^4]),x]

[Out]

(Sqrt[-3 + 2*Sqrt[3]]*ArcTanh[(Sqrt[9 + 6*Sqrt[3]]*Sqrt[-4 + 4*Sqrt[3]*x^2 + x^4])/(2 + (-2 - 2*Sqrt[3])*x + (
2 + Sqrt[3])*x^2)])/3

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Mathics [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {cought exception: maximum recursion depth exceeded while calling a Python object} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

mathics('Integrate[(1 - Sqrt[3] + x)/((1 + Sqrt[3] + x)*Sqrt[-4 + 4*Sqrt[3]*x^2 + x^4]),x]')

[Out]

cought exception: maximum recursion depth exceeded while calling a Python object

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Maple [C] Result contains higher order function than in optimal. Order 4 vs. order 3.
time = 0.42, size = 327, normalized size = 5.03

method	result	size
default	\(\frac {\sqrt {1-\left (-1+\frac {\sqrt {3}}{2}\right ) x^{2}}\, \sqrt {1-\left (1+\frac {\sqrt {3}}{2}\right ) x^{2}}\, \EllipticF \left (x \left (\frac {i \sqrt {3}}{2}-\frac {i}{2}\right ), i \sqrt {1+4 \sqrt {3}\, \left (1+\frac {\sqrt {3}}{2}\right )}\right )}{\left (\frac {i \sqrt {3}}{2}-\frac {i}{2}\right ) \sqrt {-4+x^{4}+4 \sqrt {3}\, x^{2}}}-2 \sqrt {3}\, \left (-\frac {\arctanh \left (\frac {4 \left (-1-\sqrt {3}\right )^{2} \sqrt {3}-8+4 \sqrt {3}\, x^{2}+2 x^{2} \left (-1-\sqrt {3}\right )^{2}}{2 \sqrt {\left (-1-\sqrt {3}\right )^{4}+4 \left (-1-\sqrt {3}\right )^{2} \sqrt {3}-4}\, \sqrt {-4+x^{4}+4 \sqrt {3}\, x^{2}}}\right )}{2 \sqrt {\left (-1-\sqrt {3}\right )^{4}+4 \left (-1-\sqrt {3}\right )^{2} \sqrt {3}-4}}-\frac {\sqrt {1-\left (-1+\frac {\sqrt {3}}{2}\right ) x^{2}}\, \sqrt {1-\left (1+\frac {\sqrt {3}}{2}\right ) x^{2}}\, \EllipticPi \left (\sqrt {-1+\frac {\sqrt {3}}{2}}\, x , \frac {1}{\left (-1+\frac {\sqrt {3}}{2}\right ) \left (-1-\sqrt {3}\right )^{2}}, \frac {\sqrt {1+\frac {\sqrt {3}}{2}}}{\sqrt {-1+\frac {\sqrt {3}}{2}}}\right )}{\sqrt {-1+\frac {\sqrt {3}}{2}}\, \left (-1-\sqrt {3}\right ) \sqrt {-4+x^{4}+4 \sqrt {3}\, x^{2}}}\right )\)	\(327\)
elliptic	\(\frac {\sqrt {1-\left (-1+\frac {\sqrt {3}}{2}\right ) x^{2}}\, \sqrt {1-\left (1+\frac {\sqrt {3}}{2}\right ) x^{2}}\, \EllipticF \left (x \left (\frac {i \sqrt {3}}{2}-\frac {i}{2}\right ), i \sqrt {1+4 \sqrt {3}\, \left (1+\frac {\sqrt {3}}{2}\right )}\right )}{\left (\frac {i \sqrt {3}}{2}-\frac {i}{2}\right ) \sqrt {-4+x^{4}+4 \sqrt {3}\, x^{2}}}-2 \sqrt {3}\, \left (-\frac {\arctanh \left (\frac {4 \left (-1-\sqrt {3}\right )^{2} \sqrt {3}-8+4 \sqrt {3}\, x^{2}+2 x^{2} \left (-1-\sqrt {3}\right )^{2}}{2 \sqrt {\left (-1-\sqrt {3}\right )^{4}+4 \left (-1-\sqrt {3}\right )^{2} \sqrt {3}-4}\, \sqrt {-4+x^{4}+4 \sqrt {3}\, x^{2}}}\right )}{2 \sqrt {\left (-1-\sqrt {3}\right )^{4}+4 \left (-1-\sqrt {3}\right )^{2} \sqrt {3}-4}}-\frac {\sqrt {1-\left (-1+\frac {\sqrt {3}}{2}\right ) x^{2}}\, \sqrt {1-\left (1+\frac {\sqrt {3}}{2}\right ) x^{2}}\, \EllipticPi \left (\sqrt {-1+\frac {\sqrt {3}}{2}}\, x , \frac {1}{\left (-1+\frac {\sqrt {3}}{2}\right ) \left (-1-\sqrt {3}\right )^{2}}, \frac {\sqrt {1+\frac {\sqrt {3}}{2}}}{\sqrt {-1+\frac {\sqrt {3}}{2}}}\right )}{\sqrt {-1+\frac {\sqrt {3}}{2}}\, \left (-1-\sqrt {3}\right ) \sqrt {-4+x^{4}+4 \sqrt {3}\, x^{2}}}\right )\)	\(327\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1+x-3^(1/2))/(1+x+3^(1/2))/(-4+x^4+4*3^(1/2)*x^2)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/(1/2*I*3^(1/2)-1/2*I)*(1-(-1+1/2*3^(1/2))*x^2)^(1/2)*(1-(1+1/2*3^(1/2))*x^2)^(1/2)/(-4+x^4+4*3^(1/2)*x^2)^(1
/2)*EllipticF(x*(1/2*I*3^(1/2)-1/2*I),I*(1+4*3^(1/2)*(1+1/2*3^(1/2)))^(1/2))-2*3^(1/2)*(-1/2/((-1-3^(1/2))^4+4
*(-1-3^(1/2))^2*3^(1/2)-4)^(1/2)*arctanh(1/2*(4*(-1-3^(1/2))^2*3^(1/2)-8+4*3^(1/2)*x^2+2*x^2*(-1-3^(1/2))^2)/(
(-1-3^(1/2))^4+4*(-1-3^(1/2))^2*3^(1/2)-4)^(1/2)/(-4+x^4+4*3^(1/2)*x^2)^(1/2))-1/(-1+1/2*3^(1/2))^(1/2)/(-1-3^
(1/2))*(1-(-1+1/2*3^(1/2))*x^2)^(1/2)*(1-(1+1/2*3^(1/2))*x^2)^(1/2)/(-4+x^4+4*3^(1/2)*x^2)^(1/2)*EllipticPi((-
1+1/2*3^(1/2))^(1/2)*x,1/(-1+1/2*3^(1/2))/(-1-3^(1/2))^2,(1+1/2*3^(1/2))^(1/2)/(-1+1/2*3^(1/2))^(1/2)))

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+x-3^(1/2))/(1+x+3^(1/2))/(-4+x^4+4*3^(1/2)*x^2)^(1/2),x, algorithm="maxima")

[Out]

integrate((x - sqrt(3) + 1)/(sqrt(x^4 + 4*sqrt(3)*x^2 - 4)*(x + sqrt(3) + 1)), x)

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 323 vs. \(2 (47) = 94\).
time = 0.41, size = 323, normalized size = 4.97 \begin {gather*} \frac {1}{12} \, \sqrt {2 \, \sqrt {3} - 3} \log \left (-\frac {37 \, x^{12} - 204 \, x^{11} + 804 \, x^{10} - 2408 \, x^{9} + 3708 \, x^{8} - 5472 \, x^{7} + 6432 \, x^{6} + 10944 \, x^{5} + 14832 \, x^{4} + 19264 \, x^{3} + 12864 \, x^{2} + {\left (54 \, x^{10} - 300 \, x^{9} + 1026 \, x^{8} - 2232 \, x^{7} + 3024 \, x^{6} - 3024 \, x^{5} - 1008 \, x^{4} - 2016 \, x^{3} - 2592 \, x^{2} + \sqrt {3} {\left (31 \, x^{10} - 176 \, x^{9} + 576 \, x^{8} - 1320 \, x^{7} + 1848 \, x^{6} - 1008 \, x^{5} + 1344 \, x^{4} + 1632 \, x^{3} + 1008 \, x^{2} + 832 \, x + 256\right )} - 1152 \, x - 480\right )} \sqrt {x^{4} + 4 \, \sqrt {3} x^{2} - 4} \sqrt {2 \, \sqrt {3} - 3} + 3 \, \sqrt {3} {\left (7 \, x^{12} - 40 \, x^{11} + 160 \, x^{10} - 400 \, x^{9} + 924 \, x^{8} - 960 \, x^{7} - 1920 \, x^{5} - 3696 \, x^{4} - 3200 \, x^{3} - 2560 \, x^{2} - 1280 \, x - 448\right )} + 6528 \, x + 2368}{x^{12} + 12 \, x^{11} + 48 \, x^{10} + 40 \, x^{9} - 180 \, x^{8} - 288 \, x^{7} + 384 \, x^{6} + 576 \, x^{5} - 720 \, x^{4} - 320 \, x^{3} + 768 \, x^{2} - 384 \, x + 64}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+x-3^(1/2))/(1+x+3^(1/2))/(-4+x^4+4*3^(1/2)*x^2)^(1/2),x, algorithm="fricas")

[Out]

1/12*sqrt(2*sqrt(3) - 3)*log(-(37*x^12 - 204*x^11 + 804*x^10 - 2408*x^9 + 3708*x^8 - 5472*x^7 + 6432*x^6 + 109
44*x^5 + 14832*x^4 + 19264*x^3 + 12864*x^2 + (54*x^10 - 300*x^9 + 1026*x^8 - 2232*x^7 + 3024*x^6 - 3024*x^5 -
1008*x^4 - 2016*x^3 - 2592*x^2 + sqrt(3)*(31*x^10 - 176*x^9 + 576*x^8 - 1320*x^7 + 1848*x^6 - 1008*x^5 + 1344*
x^4 + 1632*x^3 + 1008*x^2 + 832*x + 256) - 1152*x - 480)*sqrt(x^4 + 4*sqrt(3)*x^2 - 4)*sqrt(2*sqrt(3) - 3) + 3
*sqrt(3)*(7*x^12 - 40*x^11 + 160*x^10 - 400*x^9 + 924*x^8 - 960*x^7 - 1920*x^5 - 3696*x^4 - 3200*x^3 - 2560*x^
2 - 1280*x - 448) + 6528*x + 2368)/(x^12 + 12*x^11 + 48*x^10 + 40*x^9 - 180*x^8 - 288*x^7 + 384*x^6 + 576*x^5
- 720*x^4 - 320*x^3 + 768*x^2 - 384*x + 64))

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x - \sqrt {3} + 1}{\left (x + 1 + \sqrt {3}\right ) \sqrt {x^{4} + 4 \sqrt {3} x^{2} - 4}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+x-3**(1/2))/(1+x+3**(1/2))/(-4+x**4+4*3**(1/2)*x**2)**(1/2),x)

[Out]

Integral((x - sqrt(3) + 1)/((x + 1 + sqrt(3))*sqrt(x**4 + 4*sqrt(3)*x**2 - 4)), x)

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Giac [F] N/A
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+x-3^(1/2))/(1+x+3^(1/2))/(-4+x^4+4*3^(1/2)*x^2)^(1/2),x)

[Out]

Could not integrate

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {x-\sqrt {3}+1}{\left (x+\sqrt {3}+1\right )\,\sqrt {x^4+4\,\sqrt {3}\,x^2-4}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x - 3^(1/2) + 1)/((x + 3^(1/2) + 1)*(4*3^(1/2)*x^2 + x^4 - 4)^(1/2)),x)

[Out]

int((x - 3^(1/2) + 1)/((x + 3^(1/2) + 1)*(4*3^(1/2)*x^2 + x^4 - 4)^(1/2)), x)

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