3.2.1 \(\int \frac {e^x}{1+e^{2 x}} \, dx\) [101]

Optimal. Leaf size=4 \[ \tan ^{-1}\left (e^x\right ) \]

[Out]

arctan(exp(x))

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Rubi [A]
time = 0.01, antiderivative size = 4, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {2281, 209} \begin {gather*} \tan ^{-1}\left (e^x\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[E^x/(1 + E^(2*x)),x]

[Out]

ArcTan[E^x]

Rule 209

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*ArcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /;
 FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 2281

Int[((a_) + (b_.)*(F_)^((e_.)*((c_.) + (d_.)*(x_))))^(p_.)*(G_)^((h_.)*((f_.) + (g_.)*(x_))), x_Symbol] :> Wit
h[{m = FullSimplify[d*e*(Log[F]/(g*h*Log[G]))]}, Dist[Denominator[m]/(g*h*Log[G]), Subst[Int[x^(Denominator[m]
 - 1)*(a + b*F^(c*e - d*e*(f/g))*x^Numerator[m])^p, x], x, G^(h*((f + g*x)/Denominator[m]))], x] /; LtQ[m, -1]
 || GtQ[m, 1]] /; FreeQ[{F, G, a, b, c, d, e, f, g, h, p}, x]

Rubi steps

\begin {align*} \int \frac {e^x}{1+e^{2 x}} \, dx &=\text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,e^x\right )\\ &=\tan ^{-1}\left (e^x\right )\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 4, normalized size = 1.00 \begin {gather*} \tan ^{-1}\left (e^x\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[E^x/(1 + E^(2*x)),x]

[Out]

ArcTan[E^x]

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Mathics [C] Result contains complex when optimal does not.
time = 1.83, size = 23, normalized size = 5.75 \begin {gather*} \text {RootSum}\left [1+4 \text {\#1}^2\&,\text {Log}\left [E^x+2 \text {\#1}\right ] \text {\#1}\&\right ] \end {gather*}

Antiderivative was successfully verified.

[In]

mathics('Integrate[E^x/(1 + E^(2*x)),x]')

[Out]

RootSum[1 + 4 #1 ^ 2&, Log[E ^ x + 2 #1] #1&]

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Maple [A]
time = 0.02, size = 4, normalized size = 1.00

method result size
default \(\arctan \left ({\mathrm e}^{x}\right )\) \(4\)
risch \(\frac {i \ln \left ({\mathrm e}^{x}+i\right )}{2}-\frac {i \ln \left ({\mathrm e}^{x}-i\right )}{2}\) \(20\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(x)/(1+exp(2*x)),x,method=_RETURNVERBOSE)

[Out]

arctan(exp(x))

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Maxima [A]
time = 0.34, size = 3, normalized size = 0.75 \begin {gather*} \arctan \left (e^{x}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(x)/(1+exp(2*x)),x, algorithm="maxima")

[Out]

arctan(e^x)

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Fricas [A]
time = 0.40, size = 3, normalized size = 0.75 \begin {gather*} \arctan \left (e^{x}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(x)/(1+exp(2*x)),x, algorithm="fricas")

[Out]

arctan(e^x)

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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 15 vs. \(2 (3) = 6\)
time = 0.06, size = 15, normalized size = 3.75 \begin {gather*} \operatorname {RootSum} {\left (4 z^{2} + 1, \left ( i \mapsto i \log {\left (2 i + e^{x} \right )} \right )\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(x)/(1+exp(2*x)),x)

[Out]

RootSum(4*_z**2 + 1, Lambda(_i, _i*log(2*_i + exp(x))))

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Giac [A]
time = 0.00, size = 3, normalized size = 0.75 \begin {gather*} \arctan \left (\mathrm {e}^{x}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(x)/(1+exp(2*x)),x)

[Out]

arctan(e^x)

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Mupad [B]
time = 0.10, size = 3, normalized size = 0.75 \begin {gather*} \mathrm {atan}\left ({\mathrm {e}}^x\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(x)/(exp(2*x) + 1),x)

[Out]

atan(exp(x))

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