3.4.45 \(\int \frac {\sqrt {-1+9 x^2}}{x^2} \, dx\) [345]

Optimal. Leaf size=34 \[ -\frac {\sqrt {-1+9 x^2}}{x}+3 \tanh ^{-1}\left (\frac {3 x}{\sqrt {-1+9 x^2}}\right ) \]

[Out]

3*arctanh(3*x/(9*x^2-1)^(1/2))-(9*x^2-1)^(1/2)/x

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Rubi [A]
time = 0.00, antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {283, 223, 212} \begin {gather*} 3 \tanh ^{-1}\left (\frac {3 x}{\sqrt {9 x^2-1}}\right )-\frac {\sqrt {9 x^2-1}}{x} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[-1 + 9*x^2]/x^2,x]

[Out]

-(Sqrt[-1 + 9*x^2]/x) + 3*ArcTanh[(3*x)/Sqrt[-1 + 9*x^2]]

Rule 212

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 223

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rule 283

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c*x)^(m + 1)*((a + b*x^n)^p/(c*(m + 1
))), x] - Dist[b*n*(p/(c^n*(m + 1))), Int[(c*x)^(m + n)*(a + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b, c}, x] &&
IGtQ[n, 0] && GtQ[p, 0] && LtQ[m, -1] &&  !ILtQ[(m + n*p + n + 1)/n, 0] && IntBinomialQ[a, b, c, n, m, p, x]

Rubi steps

\begin {align*} \int \frac {\sqrt {-1+9 x^2}}{x^2} \, dx &=-\frac {\sqrt {-1+9 x^2}}{x}+9 \int \frac {1}{\sqrt {-1+9 x^2}} \, dx\\ &=-\frac {\sqrt {-1+9 x^2}}{x}+9 \text {Subst}\left (\int \frac {1}{1-9 x^2} \, dx,x,\frac {x}{\sqrt {-1+9 x^2}}\right )\\ &=-\frac {\sqrt {-1+9 x^2}}{x}+3 \tanh ^{-1}\left (\frac {3 x}{\sqrt {-1+9 x^2}}\right )\\ \end {align*}

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Mathematica [A]
time = 0.03, size = 35, normalized size = 1.03 \begin {gather*} -\frac {\sqrt {-1+9 x^2}}{x}-3 \log \left (-3 x+\sqrt {-1+9 x^2}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[-1 + 9*x^2]/x^2,x]

[Out]

-(Sqrt[-1 + 9*x^2]/x) - 3*Log[-3*x + Sqrt[-1 + 9*x^2]]

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Mathics [A]
time = 1.81, size = 21, normalized size = 0.62 \begin {gather*} -\frac {\sqrt {-1+9 x^2}}{x}+3 \text {ArcCosh}\left [3 x\right ] \end {gather*}

Warning: Unable to verify antiderivative.

[In]

mathics('Integrate[Sqrt[-1 + 9*x^2]/x^2,x]')

[Out]

-Sqrt[-1 + 9 x ^ 2] / x + 3 ArcCosh[3 x]

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Maple [A]
time = 0.12, size = 47, normalized size = 1.38

method	result	size
trager	\(-\frac {\sqrt {9 x^{2}-1}}{x}+3 \ln \left (3 x +\sqrt {9 x^{2}-1}\right )\)	\(32\)
risch	\(-\frac {\sqrt {9 x^{2}-1}}{x}+\ln \left (\sqrt {9}\, x +\sqrt {9 x^{2}-1}\right ) \sqrt {9}\)	\(36\)
default	\(\frac {\left (9 x^{2}-1\right )^{\frac {3}{2}}}{x}-9 x \sqrt {9 x^{2}-1}+\ln \left (\sqrt {9}\, x +\sqrt {9 x^{2}-1}\right ) \sqrt {9}\)	\(47\)
meijerg	\(-\frac {3 i \sqrt {\mathrm {signum}\left (9 x^{2}-1\right )}\, \left (-\frac {4 i \sqrt {\pi }\, \sqrt {-9 x^{2}+1}}{3 x}-4 i \sqrt {\pi }\, \arcsin \left (3 x \right )\right )}{4 \sqrt {\pi }\, \sqrt {-\mathrm {signum}\left (9 x^{2}-1\right )}}\)	\(58\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((9*x^2-1)^(1/2)/x^2,x,method=_RETURNVERBOSE)

[Out]

1/x*(9*x^2-1)^(3/2)-9*x*(9*x^2-1)^(1/2)+ln(9^(1/2)*x+(9*x^2-1)^(1/2))*9^(1/2)

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Maxima [A]
time = 0.35, size = 33, normalized size = 0.97 \begin {gather*} -\frac {\sqrt {9 \, x^{2} - 1}}{x} + 3 \, \log \left (18 \, x + 6 \, \sqrt {9 \, x^{2} - 1}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((9*x^2-1)^(1/2)/x^2,x, algorithm="maxima")

[Out]

-sqrt(9*x^2 - 1)/x + 3*log(18*x + 6*sqrt(9*x^2 - 1))

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Fricas [A]
time = 0.33, size = 35, normalized size = 1.03 \begin {gather*} -\frac {3 \, x \log \left (-3 \, x + \sqrt {9 \, x^{2} - 1}\right ) + 3 \, x + \sqrt {9 \, x^{2} - 1}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((9*x^2-1)^(1/2)/x^2,x, algorithm="fricas")

[Out]

-(3*x*log(-3*x + sqrt(9*x^2 - 1)) + 3*x + sqrt(9*x^2 - 1))/x

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Sympy [A]
time = 0.11, size = 17, normalized size = 0.50 \begin {gather*} 3 \operatorname {acosh}{\left (3 x \right )} - \frac {\sqrt {9 x^{2} - 1}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((9*x**2-1)**(1/2)/x**2,x)

[Out]

3*acosh(3*x) - sqrt(9*x**2 - 1)/x

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Giac [A]
time = 0.00, size = 50, normalized size = 1.47 \begin {gather*} 2 \left (-\frac {3}{\left (\sqrt {9 x^{2}-1}-3 x\right )^{2}+1}-\frac {3}{4} \ln \left (\left (\sqrt {9 x^{2}-1}-3 x\right )^{2}\right )\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((9*x^2-1)^(1/2)/x^2,x)

[Out]

-6/((3*x - sqrt(9*x^2 - 1))^2 + 1) - 3/2*log((3*x - sqrt(9*x^2 - 1))^2)

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Mupad [B]
time = 0.52, size = 32, normalized size = 0.94 \begin {gather*} -\frac {\left (\frac {3\,x\,\mathrm {asin}\left (3\,x\right )}{\sqrt {1-9\,x^2}}+1\right )\,\sqrt {9\,x^2-1}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((9*x^2 - 1)^(1/2)/x^2,x)

[Out]

-(((3*x*asin(3*x))/(1 - 9*x^2)^(1/2) + 1)*(9*x^2 - 1)^(1/2))/x

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