\(\int \frac {1}{x (a^3+x^3)} \, dx\) [121]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 13, antiderivative size = 22 \[ \int \frac {1}{x \left (a^3+x^3\right )} \, dx=\frac {\log (x)}{a^3}-\frac {\log \left (a^3+x^3\right )}{3 a^3} \]

[Out]

ln(x)/a^3-1/3*ln(a^3+x^3)/a^3

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {272, 36, 29, 31} \[ \int \frac {1}{x \left (a^3+x^3\right )} \, dx=\frac {\log (x)}{a^3}-\frac {\log \left (a^3+x^3\right )}{3 a^3} \]

[In]

Int[1/(x*(a^3 + x^3)),x]

[Out]

Log[x]/a^3 - Log[a^3 + x^3]/(3*a^3)

Rule 29

Int[(x_)^(-1), x_Symbol] :> Simp[Log[x], x]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 36

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :> Dist[b/(b*c - a*d), Int[1/(a + b*x), x], x] -
Dist[d/(b*c - a*d), Int[1/(c + d*x), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0]

Rule 272

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {1}{x \left (a^3+x\right )} \, dx,x,x^3\right ) \\ & = \frac {\text {Subst}\left (\int \frac {1}{x} \, dx,x,x^3\right )}{3 a^3}-\frac {\text {Subst}\left (\int \frac {1}{a^3+x} \, dx,x,x^3\right )}{3 a^3} \\ & = \frac {\log (x)}{a^3}-\frac {\log \left (a^3+x^3\right )}{3 a^3} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.01 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x \left (a^3+x^3\right )} \, dx=\frac {\log (x)}{a^3}-\frac {\log \left (a^3+x^3\right )}{3 a^3} \]

[In]

Integrate[1/(x*(a^3 + x^3)),x]

[Out]

Log[x]/a^3 - Log[a^3 + x^3]/(3*a^3)

Maple [A] (verified)

Time = 0.20 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.95

method result size
risch \(\frac {\ln \left (x \right )}{a^{3}}-\frac {\ln \left (a^{3}+x^{3}\right )}{3 a^{3}}\) \(21\)
parallelrisch \(\frac {3 \ln \left (x \right )-\ln \left (a +x \right )-\ln \left (a^{2}-a x +x^{2}\right )}{3 a^{3}}\) \(31\)
default \(\frac {\ln \left (x \right )}{a^{3}}-\frac {\ln \left (a^{2}-a x +x^{2}\right )}{3 a^{3}}-\frac {\ln \left (a +x \right )}{3 a^{3}}\) \(34\)
norman \(\frac {\ln \left (x \right )}{a^{3}}-\frac {\ln \left (a^{2}-a x +x^{2}\right )}{3 a^{3}}-\frac {\ln \left (a +x \right )}{3 a^{3}}\) \(34\)

[In]

int(1/x/(a^3+x^3),x,method=_RETURNVERBOSE)

[Out]

ln(x)/a^3-1/3*ln(a^3+x^3)/a^3

Fricas [A] (verification not implemented)

none

Time = 0.23 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.82 \[ \int \frac {1}{x \left (a^3+x^3\right )} \, dx=-\frac {\log \left (a^{3} + x^{3}\right ) - 3 \, \log \left (x\right )}{3 \, a^{3}} \]

[In]

integrate(1/x/(a^3+x^3),x, algorithm="fricas")

[Out]

-1/3*(log(a^3 + x^3) - 3*log(x))/a^3

Sympy [A] (verification not implemented)

Time = 0.10 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86 \[ \int \frac {1}{x \left (a^3+x^3\right )} \, dx=\frac {\log {\left (x \right )}}{a^{3}} - \frac {\log {\left (a^{3} + x^{3} \right )}}{3 a^{3}} \]

[In]

integrate(1/x/(a**3+x**3),x)

[Out]

log(x)/a**3 - log(a**3 + x**3)/(3*a**3)

Maxima [A] (verification not implemented)

none

Time = 0.20 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.05 \[ \int \frac {1}{x \left (a^3+x^3\right )} \, dx=-\frac {\log \left (a^{3} + x^{3}\right )}{3 \, a^{3}} + \frac {\log \left (x^{3}\right )}{3 \, a^{3}} \]

[In]

integrate(1/x/(a^3+x^3),x, algorithm="maxima")

[Out]

-1/3*log(a^3 + x^3)/a^3 + 1/3*log(x^3)/a^3

Giac [A] (verification not implemented)

none

Time = 0.33 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x \left (a^3+x^3\right )} \, dx=-\frac {\log \left ({\left | a^{3} + x^{3} \right |}\right )}{3 \, a^{3}} + \frac {\log \left ({\left | x \right |}\right )}{a^{3}} \]

[In]

integrate(1/x/(a^3+x^3),x, algorithm="giac")

[Out]

-1/3*log(abs(a^3 + x^3))/a^3 + log(abs(x))/a^3

Mupad [B] (verification not implemented)

Time = 0.29 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.82 \[ \int \frac {1}{x \left (a^3+x^3\right )} \, dx=-\frac {\ln \left (a^3+x^3\right )-3\,\ln \left (x\right )}{3\,a^3} \]

[In]

int(1/(x*(a^3 + x^3)),x)

[Out]

-(log(a^3 + x^3) - 3*log(x))/(3*a^3)