Integrand size = 9, antiderivative size = 49 \[ \int \frac {x}{1+x^6} \, dx=-\frac {\arctan \left (\frac {1-2 x^2}{\sqrt {3}}\right )}{2 \sqrt {3}}+\frac {1}{6} \log \left (1+x^2\right )-\frac {1}{12} \log \left (1-x^2+x^4\right ) \]
[Out]
Time = 0.03 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.778, Rules used = {281, 206, 31, 648, 632, 210, 642} \[ \int \frac {x}{1+x^6} \, dx=-\frac {\arctan \left (\frac {1-2 x^2}{\sqrt {3}}\right )}{2 \sqrt {3}}+\frac {1}{6} \log \left (x^2+1\right )-\frac {1}{12} \log \left (x^4-x^2+1\right ) \]
[In]
[Out]
Rule 31
Rule 206
Rule 210
Rule 281
Rule 632
Rule 642
Rule 648
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {1}{1+x^3} \, dx,x,x^2\right ) \\ & = \frac {1}{6} \text {Subst}\left (\int \frac {1}{1+x} \, dx,x,x^2\right )+\frac {1}{6} \text {Subst}\left (\int \frac {2-x}{1-x+x^2} \, dx,x,x^2\right ) \\ & = \frac {1}{6} \log \left (1+x^2\right )-\frac {1}{12} \text {Subst}\left (\int \frac {-1+2 x}{1-x+x^2} \, dx,x,x^2\right )+\frac {1}{4} \text {Subst}\left (\int \frac {1}{1-x+x^2} \, dx,x,x^2\right ) \\ & = \frac {1}{6} \log \left (1+x^2\right )-\frac {1}{12} \log \left (1-x^2+x^4\right )-\frac {1}{2} \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,-1+2 x^2\right ) \\ & = -\frac {\arctan \left (\frac {1-2 x^2}{\sqrt {3}}\right )}{2 \sqrt {3}}+\frac {1}{6} \log \left (1+x^2\right )-\frac {1}{12} \log \left (1-x^2+x^4\right ) \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.59 \[ \int \frac {x}{1+x^6} \, dx=\frac {1}{12} \left (-2 \sqrt {3} \arctan \left (\sqrt {3}-2 x\right )-2 \sqrt {3} \arctan \left (\sqrt {3}+2 x\right )+2 \log \left (1+x^2\right )-\log \left (1-\sqrt {3} x+x^2\right )-\log \left (1+\sqrt {3} x+x^2\right )\right ) \]
[In]
[Out]
Time = 0.22 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.80
method | result | size |
risch | \(\frac {\ln \left (x^{2}+1\right )}{6}-\frac {\ln \left (x^{4}-x^{2}+1\right )}{12}+\frac {\sqrt {3}\, \arctan \left (\frac {2 \left (x^{2}-\frac {1}{2}\right ) \sqrt {3}}{3}\right )}{6}\) | \(39\) |
default | \(-\frac {\ln \left (x^{4}-x^{2}+1\right )}{12}+\frac {\arctan \left (\frac {\left (2 x^{2}-1\right ) \sqrt {3}}{3}\right ) \sqrt {3}}{6}+\frac {\ln \left (x^{2}+1\right )}{6}\) | \(41\) |
meijerg | \(\frac {x^{2} \ln \left (1+\left (x^{6}\right )^{\frac {1}{3}}\right )}{6 \left (x^{6}\right )^{\frac {1}{3}}}-\frac {x^{2} \ln \left (1-\left (x^{6}\right )^{\frac {1}{3}}+\left (x^{6}\right )^{\frac {2}{3}}\right )}{12 \left (x^{6}\right )^{\frac {1}{3}}}+\frac {x^{2} \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (x^{6}\right )^{\frac {1}{3}}}{2-\left (x^{6}\right )^{\frac {1}{3}}}\right )}{6 \left (x^{6}\right )^{\frac {1}{3}}}\) | \(80\) |
[In]
[Out]
none
Time = 0.25 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.82 \[ \int \frac {x}{1+x^6} \, dx=\frac {1}{6} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x^{2} - 1\right )}\right ) - \frac {1}{12} \, \log \left (x^{4} - x^{2} + 1\right ) + \frac {1}{6} \, \log \left (x^{2} + 1\right ) \]
[In]
[Out]
Time = 0.06 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.94 \[ \int \frac {x}{1+x^6} \, dx=\frac {\log {\left (x^{2} + 1 \right )}}{6} - \frac {\log {\left (x^{4} - x^{2} + 1 \right )}}{12} + \frac {\sqrt {3} \operatorname {atan}{\left (\frac {2 \sqrt {3} x^{2}}{3} - \frac {\sqrt {3}}{3} \right )}}{6} \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.82 \[ \int \frac {x}{1+x^6} \, dx=\frac {1}{6} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x^{2} - 1\right )}\right ) - \frac {1}{12} \, \log \left (x^{4} - x^{2} + 1\right ) + \frac {1}{6} \, \log \left (x^{2} + 1\right ) \]
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.82 \[ \int \frac {x}{1+x^6} \, dx=\frac {1}{6} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x^{2} - 1\right )}\right ) - \frac {1}{12} \, \log \left (x^{4} - x^{2} + 1\right ) + \frac {1}{6} \, \log \left (x^{2} + 1\right ) \]
[In]
[Out]
Time = 0.10 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.06 \[ \int \frac {x}{1+x^6} \, dx=\frac {\ln \left (x^2+1\right )}{6}-\ln \left (x^2-\frac {\sqrt {3}\,1{}\mathrm {i}}{2}-\frac {1}{2}\right )\,\left (\frac {1}{12}+\frac {\sqrt {3}\,1{}\mathrm {i}}{12}\right )+\ln \left (x^2+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}-\frac {1}{2}\right )\,\left (-\frac {1}{12}+\frac {\sqrt {3}\,1{}\mathrm {i}}{12}\right ) \]
[In]
[Out]