Integrand size = 12, antiderivative size = 58 \[ \int \frac {1}{\left (4+2 x+x^2\right )^{7/2}} \, dx=\frac {1+x}{15 \left (4+2 x+x^2\right )^{5/2}}+\frac {4 (1+x)}{135 \left (4+2 x+x^2\right )^{3/2}}+\frac {8 (1+x)}{405 \sqrt {4+2 x+x^2}} \]
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Time = 0.01 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {628, 627} \[ \int \frac {1}{\left (4+2 x+x^2\right )^{7/2}} \, dx=\frac {8 (x+1)}{405 \sqrt {x^2+2 x+4}}+\frac {4 (x+1)}{135 \left (x^2+2 x+4\right )^{3/2}}+\frac {x+1}{15 \left (x^2+2 x+4\right )^{5/2}} \]
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Rule 627
Rule 628
Rubi steps \begin{align*} \text {integral}& = \frac {1+x}{15 \left (4+2 x+x^2\right )^{5/2}}+\frac {4}{15} \int \frac {1}{\left (4+2 x+x^2\right )^{5/2}} \, dx \\ & = \frac {1+x}{15 \left (4+2 x+x^2\right )^{5/2}}+\frac {4 (1+x)}{135 \left (4+2 x+x^2\right )^{3/2}}+\frac {8}{135} \int \frac {1}{\left (4+2 x+x^2\right )^{3/2}} \, dx \\ & = \frac {1+x}{15 \left (4+2 x+x^2\right )^{5/2}}+\frac {4 (1+x)}{135 \left (4+2 x+x^2\right )^{3/2}}+\frac {8 (1+x)}{405 \sqrt {4+2 x+x^2}} \\ \end{align*}
Time = 0.31 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.67 \[ \int \frac {1}{\left (4+2 x+x^2\right )^{7/2}} \, dx=\frac {(1+x) \left (203+152 x+108 x^2+32 x^3+8 x^4\right )}{405 \left (4+2 x+x^2\right )^{5/2}} \]
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Time = 0.44 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.66
method | result | size |
gosper | \(\frac {8 x^{5}+40 x^{4}+140 x^{3}+260 x^{2}+355 x +203}{405 \left (x^{2}+2 x +4\right )^{\frac {5}{2}}}\) | \(38\) |
trager | \(\frac {8 x^{5}+40 x^{4}+140 x^{3}+260 x^{2}+355 x +203}{405 \left (x^{2}+2 x +4\right )^{\frac {5}{2}}}\) | \(38\) |
risch | \(\frac {8 x^{5}+40 x^{4}+140 x^{3}+260 x^{2}+355 x +203}{405 \left (x^{2}+2 x +4\right )^{\frac {5}{2}}}\) | \(38\) |
default | \(\frac {2 x +2}{30 \left (x^{2}+2 x +4\right )^{\frac {5}{2}}}+\frac {\frac {4}{135}+\frac {4 x}{135}}{\left (x^{2}+2 x +4\right )^{\frac {3}{2}}}+\frac {\frac {8}{405}+\frac {8 x}{405}}{\sqrt {x^{2}+2 x +4}}\) | \(53\) |
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Leaf count of result is larger than twice the leaf count of optimal. 98 vs. \(2 (46) = 92\).
Time = 0.24 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.69 \[ \int \frac {1}{\left (4+2 x+x^2\right )^{7/2}} \, dx=\frac {8 \, x^{6} + 48 \, x^{5} + 192 \, x^{4} + 448 \, x^{3} + 768 \, x^{2} + {\left (8 \, x^{5} + 40 \, x^{4} + 140 \, x^{3} + 260 \, x^{2} + 355 \, x + 203\right )} \sqrt {x^{2} + 2 \, x + 4} + 768 \, x + 512}{405 \, {\left (x^{6} + 6 \, x^{5} + 24 \, x^{4} + 56 \, x^{3} + 96 \, x^{2} + 96 \, x + 64\right )}} \]
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\[ \int \frac {1}{\left (4+2 x+x^2\right )^{7/2}} \, dx=\int \frac {1}{\left (x^{2} + 2 x + 4\right )^{\frac {7}{2}}}\, dx \]
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none
Time = 0.19 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.31 \[ \int \frac {1}{\left (4+2 x+x^2\right )^{7/2}} \, dx=\frac {8 \, x}{405 \, \sqrt {x^{2} + 2 \, x + 4}} + \frac {8}{405 \, \sqrt {x^{2} + 2 \, x + 4}} + \frac {4 \, x}{135 \, {\left (x^{2} + 2 \, x + 4\right )}^{\frac {3}{2}}} + \frac {4}{135 \, {\left (x^{2} + 2 \, x + 4\right )}^{\frac {3}{2}}} + \frac {x}{15 \, {\left (x^{2} + 2 \, x + 4\right )}^{\frac {5}{2}}} + \frac {1}{15 \, {\left (x^{2} + 2 \, x + 4\right )}^{\frac {5}{2}}} \]
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none
Time = 0.29 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.57 \[ \int \frac {1}{\left (4+2 x+x^2\right )^{7/2}} \, dx=\frac {{\left (4 \, {\left ({\left (2 \, {\left (x + 5\right )} x + 35\right )} x + 65\right )} x + 355\right )} x + 203}{405 \, {\left (x^{2} + 2 \, x + 4\right )}^{\frac {5}{2}}} \]
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Time = 0.28 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.19 \[ \int \frac {1}{\left (4+2 x+x^2\right )^{7/2}} \, dx=\frac {51\,x+8\,x\,{\left (x^2+2\,x+4\right )}^2+8\,{\left (x^2+2\,x+4\right )}^2+12\,x^2+12\,x\,\left (x^2+2\,x+4\right )+75}{{\left (x^2+2\,x+4\right )}^{3/2}\,\left (405\,x^2+810\,x+1620\right )} \]
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