Integrand size = 29, antiderivative size = 76 \[ \int \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan ^2\left (\frac {\pi }{4}+\frac {x}{2}\right ) \, dx=-\frac {1}{4} \text {arctanh}\left (\sin \left (\frac {\pi }{4}+\frac {x}{2}\right )\right )-\frac {1}{4} \sec \left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan \left (\frac {\pi }{4}+\frac {x}{2}\right )+\frac {1}{2} \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan \left (\frac {\pi }{4}+\frac {x}{2}\right ) \]
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Time = 0.05 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {2691, 3853, 3855} \[ \int \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan ^2\left (\frac {\pi }{4}+\frac {x}{2}\right ) \, dx=-\frac {1}{4} \text {arctanh}\left (\sin \left (\frac {x}{2}+\frac {\pi }{4}\right )\right )+\frac {1}{2} \tan \left (\frac {x}{2}+\frac {\pi }{4}\right ) \sec ^3\left (\frac {x}{2}+\frac {\pi }{4}\right )-\frac {1}{4} \tan \left (\frac {x}{2}+\frac {\pi }{4}\right ) \sec \left (\frac {x}{2}+\frac {\pi }{4}\right ) \]
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Rule 2691
Rule 3853
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan \left (\frac {\pi }{4}+\frac {x}{2}\right )-\frac {1}{4} \int \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \, dx \\ & = -\frac {1}{4} \sec \left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan \left (\frac {\pi }{4}+\frac {x}{2}\right )+\frac {1}{2} \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan \left (\frac {\pi }{4}+\frac {x}{2}\right )-\frac {1}{8} \int \csc \left (\frac {\pi }{4}-\frac {x}{2}\right ) \, dx \\ & = -\frac {1}{4} \text {arctanh}\left (\sin \left (\frac {\pi }{4}+\frac {x}{2}\right )\right )-\frac {1}{4} \sec \left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan \left (\frac {\pi }{4}+\frac {x}{2}\right )+\frac {1}{2} \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan \left (\frac {\pi }{4}+\frac {x}{2}\right ) \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.97 \[ \int \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan ^2\left (\frac {\pi }{4}+\frac {x}{2}\right ) \, dx=-\frac {1}{4} \text {arctanh}\left (\sin \left (\frac {\pi }{4}+\frac {x}{2}\right )\right )-\frac {1}{4} \sec ^2\left (\frac {1}{4} (\pi +2 x)\right ) \sin \left (\frac {\pi }{4}+\frac {x}{2}\right )+\frac {1}{2} \sec ^4\left (\frac {1}{4} (\pi +2 x)\right ) \sin \left (\frac {\pi }{4}+\frac {x}{2}\right ) \]
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Time = 0.78 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.00
method | result | size |
derivativedivides | \(\frac {\sin ^{3}\left (\frac {\pi }{4}+\frac {x}{2}\right )}{2 \cos \left (\frac {\pi }{4}+\frac {x}{2}\right )^{4}}+\frac {\sin ^{3}\left (\frac {\pi }{4}+\frac {x}{2}\right )}{4 \cos \left (\frac {\pi }{4}+\frac {x}{2}\right )^{2}}+\frac {\sin \left (\frac {\pi }{4}+\frac {x}{2}\right )}{4}-\frac {\ln \left (\sec \left (\frac {\pi }{4}+\frac {x}{2}\right )+\tan \left (\frac {\pi }{4}+\frac {x}{2}\right )\right )}{4}\) | \(76\) |
default | \(\frac {\sin ^{3}\left (\frac {\pi }{4}+\frac {x}{2}\right )}{2 \cos \left (\frac {\pi }{4}+\frac {x}{2}\right )^{4}}+\frac {\sin ^{3}\left (\frac {\pi }{4}+\frac {x}{2}\right )}{4 \cos \left (\frac {\pi }{4}+\frac {x}{2}\right )^{2}}+\frac {\sin \left (\frac {\pi }{4}+\frac {x}{2}\right )}{4}-\frac {\ln \left (\sec \left (\frac {\pi }{4}+\frac {x}{2}\right )+\tan \left (\frac {\pi }{4}+\frac {x}{2}\right )\right )}{4}\) | \(76\) |
risch | \(\frac {i \left (-\left (-1\right )^{\frac {3}{4}} {\mathrm e}^{\frac {7 i x}{2}}+7 \left (-1\right )^{\frac {1}{4}} {\mathrm e}^{\frac {5 i x}{2}}+7 \left (-1\right )^{\frac {3}{4}} {\mathrm e}^{\frac {3 i x}{2}}-\left (-1\right )^{\frac {1}{4}} {\mathrm e}^{\frac {i x}{2}}\right )}{2 \left (i {\mathrm e}^{i x}+1\right )^{4}}-\frac {\ln \left ({\mathrm e}^{\frac {i \left (\pi +2 x \right )}{4}}+i\right )}{4}+\frac {\ln \left ({\mathrm e}^{\frac {i \left (\pi +2 x \right )}{4}}-i\right )}{4}\) | \(88\) |
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Time = 0.26 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.08 \[ \int \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan ^2\left (\frac {\pi }{4}+\frac {x}{2}\right ) \, dx=-\frac {\cos \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )^{4} \log \left (\sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right ) + 1\right ) - \cos \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )^{4} \log \left (-\sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right ) + 1\right ) + 2 \, {\left (\cos \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )^{2} - 2\right )} \sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )}{8 \, \cos \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )^{4}} \]
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\[ \int \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan ^2\left (\frac {\pi }{4}+\frac {x}{2}\right ) \, dx=\int \tan ^{2}{\left (\frac {x}{2} + \frac {\pi }{4} \right )} \sec ^{3}{\left (\frac {x}{2} + \frac {\pi }{4} \right )}\, dx \]
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Time = 0.19 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.97 \[ \int \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan ^2\left (\frac {\pi }{4}+\frac {x}{2}\right ) \, dx=\frac {\sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )^{3} + \sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )}{4 \, {\left (\sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )^{4} - 2 \, \sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )^{2} + 1\right )}} - \frac {1}{8} \, \log \left (\sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right ) + 1\right ) + \frac {1}{8} \, \log \left (\sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right ) - 1\right ) \]
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Time = 0.37 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.25 \[ \int \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan ^2\left (\frac {\pi }{4}+\frac {x}{2}\right ) \, dx=\frac {\frac {1}{\sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )} + \sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )}{4 \, {\left ({\left (\frac {1}{\sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )} + \sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )\right )}^{2} - 4\right )}} - \frac {1}{16} \, \log \left ({\left | \frac {1}{\sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )} + \sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right ) + 2 \right |}\right ) + \frac {1}{16} \, \log \left ({\left | \frac {1}{\sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right )} + \sin \left (\frac {1}{4} \, \pi + \frac {1}{2} \, x\right ) - 2 \right |}\right ) \]
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Time = 6.41 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.99 \[ \int \sec ^3\left (\frac {\pi }{4}+\frac {x}{2}\right ) \tan ^2\left (\frac {\pi }{4}+\frac {x}{2}\right ) \, dx=\frac {2\,\left (\frac {{\mathrm {tan}\left (\frac {\Pi }{8}+\frac {x}{4}\right )}^7}{4}+\frac {7\,{\mathrm {tan}\left (\frac {\Pi }{8}+\frac {x}{4}\right )}^5}{4}+\frac {7\,{\mathrm {tan}\left (\frac {\Pi }{8}+\frac {x}{4}\right )}^3}{4}+\frac {\mathrm {tan}\left (\frac {\Pi }{8}+\frac {x}{4}\right )}{4}\right )}{{\left ({\mathrm {tan}\left (\frac {\Pi }{8}+\frac {x}{4}\right )}^2-1\right )}^4}-\frac {\mathrm {atanh}\left (\mathrm {tan}\left (\frac {\Pi }{8}+\frac {x}{4}\right )\right )}{2} \]
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