Integrand size = 15, antiderivative size = 74 \[ \int \left (a^{k x}-a^{l x}\right )^n \, dx=\frac {\left (1-a^{(k-l) x}\right ) \left (a^{k x}-a^{l x}\right )^n \operatorname {Hypergeometric2F1}\left (1,1+\frac {k n}{k-l},1+\frac {l n}{k-l},a^{(k-l) x}\right )}{l n \log (a)} \]
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Time = 0.05 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.11, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {2323, 2283} \[ \int \left (a^{k x}-a^{l x}\right )^n \, dx=\frac {\left (1-a^{-(x (k-l))}\right )^{-n} \left (a^{k x}-a^{l x}\right )^n \operatorname {Hypergeometric2F1}\left (-n,-\frac {k n}{k-l},1-\frac {k n}{k-l},a^{-((k-l) x)}\right )}{k n \log (a)} \]
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Rule 2283
Rule 2323
Rubi steps \begin{align*} \text {integral}& = \left (a^{-k n x} \left (1-a^{-((k-l) x)}\right )^{-n} \left (a^{k x}-a^{l x}\right )^n\right ) \int a^{k n x} \left (1-a^{-((k-l) x)}\right )^n \, dx \\ & = \frac {\left (1-a^{-((k-l) x)}\right )^{-n} \left (a^{k x}-a^{l x}\right )^n \operatorname {Hypergeometric2F1}\left (-n,-\frac {k n}{k-l},1-\frac {k n}{k-l},a^{-((k-l) x)}\right )}{k n \log (a)} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.01 \[ \int \left (a^{k x}-a^{l x}\right )^n \, dx=\frac {\left (a^{k x}-a^{l x}\right )^n \left (1-a^{(-k+l) x}\right ) \operatorname {Hypergeometric2F1}\left (1,1+n+\frac {k n}{-k+l},1+\frac {k n}{-k+l},a^{(-k+l) x}\right )}{k n \log (a)} \]
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\[\int \left (a^{k x}-a^{l x}\right )^{n}d x\]
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\[ \int \left (a^{k x}-a^{l x}\right )^n \, dx=\int { {\left (a^{k x} - a^{l x}\right )}^{n} \,d x } \]
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\[ \int \left (a^{k x}-a^{l x}\right )^n \, dx=\int \left (a^{k x} - a^{l x}\right )^{n}\, dx \]
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\[ \int \left (a^{k x}-a^{l x}\right )^n \, dx=\int { {\left (a^{k x} - a^{l x}\right )}^{n} \,d x } \]
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\[ \int \left (a^{k x}-a^{l x}\right )^n \, dx=\int { {\left (a^{k x} - a^{l x}\right )}^{n} \,d x } \]
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Timed out. \[ \int \left (a^{k x}-a^{l x}\right )^n \, dx=\int {\left (a^{k\,x}-a^{l\,x}\right )}^n \,d x \]
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