Integrand size = 2, antiderivative size = 2 \[ \int \sinh (x) \, dx=\cosh (x) \]
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Time = 0.00 (sec) , antiderivative size = 2, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {2718} \[ \int \sinh (x) \, dx=\cosh (x) \]
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Rule 2718
Rubi steps \begin{align*} \text {integral}& = \cosh (x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 2, normalized size of antiderivative = 1.00 \[ \int \sinh (x) \, dx=\cosh (x) \]
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Time = 0.03 (sec) , antiderivative size = 3, normalized size of antiderivative = 1.50
method | result | size |
lookup | \(\cosh \left (x \right )\) | \(3\) |
default | \(\cosh \left (x \right )\) | \(3\) |
risch | \(\frac {{\mathrm e}^{x}}{2}+\frac {{\mathrm e}^{-x}}{2}\) | \(12\) |
parallelrisch | \(-\frac {2}{\tanh ^{2}\left (\frac {x}{2}\right )-1}\) | \(13\) |
meijerg | \(-\sqrt {\pi }\, \left (\frac {1}{\sqrt {\pi }}-\frac {\cosh \left (x \right )}{\sqrt {\pi }}\right )\) | \(17\) |
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none
Time = 0.23 (sec) , antiderivative size = 2, normalized size of antiderivative = 1.00 \[ \int \sinh (x) \, dx=\cosh \left (x\right ) \]
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Time = 0.07 (sec) , antiderivative size = 2, normalized size of antiderivative = 1.00 \[ \int \sinh (x) \, dx=\cosh {\left (x \right )} \]
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none
Time = 0.22 (sec) , antiderivative size = 2, normalized size of antiderivative = 1.00 \[ \int \sinh (x) \, dx=\cosh \left (x\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 11 vs. \(2 (2) = 4\).
Time = 0.29 (sec) , antiderivative size = 11, normalized size of antiderivative = 5.50 \[ \int \sinh (x) \, dx=\frac {1}{2} \, e^{\left (-x\right )} + \frac {1}{2} \, e^{x} \]
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Time = 0.02 (sec) , antiderivative size = 2, normalized size of antiderivative = 1.00 \[ \int \sinh (x) \, dx=\mathrm {cosh}\left (x\right ) \]
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