Integrand size = 11, antiderivative size = 1 \[ \int \frac {e^x}{\cosh (x)+\sinh (x)} \, dx=x \]
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Time = 0.01 (sec) , antiderivative size = 1, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {2320, 29} \[ \int \frac {e^x}{\cosh (x)+\sinh (x)} \, dx=x \]
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Rule 29
Rule 2320
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {1}{x} \, dx,x,e^x\right ) \\ & = x \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 1, normalized size of antiderivative = 1.00 \[ \int \frac {e^x}{\cosh (x)+\sinh (x)} \, dx=x \]
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Time = 0.51 (sec) , antiderivative size = 2, normalized size of antiderivative = 2.00
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none
Time = 0.22 (sec) , antiderivative size = 1, normalized size of antiderivative = 1.00 \[ \int \frac {e^x}{\cosh (x)+\sinh (x)} \, dx=x \]
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Leaf count of result is larger than twice the leaf count of optimal. 10 vs. \(2 (0) = 0\).
Time = 0.17 (sec) , antiderivative size = 10, normalized size of antiderivative = 10.00 \[ \int \frac {e^x}{\cosh (x)+\sinh (x)} \, dx=\frac {x e^{x}}{\sinh {\left (x \right )} + \cosh {\left (x \right )}} \]
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none
Time = 0.20 (sec) , antiderivative size = 1, normalized size of antiderivative = 1.00 \[ \int \frac {e^x}{\cosh (x)+\sinh (x)} \, dx=x \]
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none
Time = 0.28 (sec) , antiderivative size = 1, normalized size of antiderivative = 1.00 \[ \int \frac {e^x}{\cosh (x)+\sinh (x)} \, dx=x \]
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Time = 0.32 (sec) , antiderivative size = 1, normalized size of antiderivative = 1.00 \[ \int \frac {e^x}{\cosh (x)+\sinh (x)} \, dx=x \]
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