Integrand size = 14, antiderivative size = 28 \[ \int \frac {\log \left (\cos \left (\frac {x}{2}\right )\right )}{1+\cos (x)} \, dx=-\frac {x}{2}+\frac {\log \left (\cos \left (\frac {x}{2}\right )\right ) \sin (x)}{1+\cos (x)}+\tan \left (\frac {x}{2}\right ) \]
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Time = 0.03 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.357, Rules used = {2727, 2634, 12, 3554, 8} \[ \int \frac {\log \left (\cos \left (\frac {x}{2}\right )\right )}{1+\cos (x)} \, dx=-\frac {x}{2}+\tan \left (\frac {x}{2}\right )+\frac {\sin (x) \log \left (\cos \left (\frac {x}{2}\right )\right )}{\cos (x)+1} \]
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Rule 8
Rule 12
Rule 2634
Rule 2727
Rule 3554
Rubi steps \begin{align*} \text {integral}& = \frac {\log \left (\cos \left (\frac {x}{2}\right )\right ) \sin (x)}{1+\cos (x)}-\int -\frac {1}{2} \tan ^2\left (\frac {x}{2}\right ) \, dx \\ & = \frac {\log \left (\cos \left (\frac {x}{2}\right )\right ) \sin (x)}{1+\cos (x)}+\frac {1}{2} \int \tan ^2\left (\frac {x}{2}\right ) \, dx \\ & = \frac {\log \left (\cos \left (\frac {x}{2}\right )\right ) \sin (x)}{1+\cos (x)}+\tan \left (\frac {x}{2}\right )-\frac {\int 1 \, dx}{2} \\ & = -\frac {x}{2}+\frac {\log \left (\cos \left (\frac {x}{2}\right )\right ) \sin (x)}{1+\cos (x)}+\tan \left (\frac {x}{2}\right ) \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.14 \[ \int \frac {\log \left (\cos \left (\frac {x}{2}\right )\right )}{1+\cos (x)} \, dx=-\frac {\left (x \cot \left (\frac {x}{2}\right )-2 \left (1+\log \left (\cos \left (\frac {x}{2}\right )\right )\right )\right ) \sin (x)}{2 (1+\cos (x))} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.67 (sec) , antiderivative size = 164, normalized size of antiderivative = 5.86
method | result | size |
risch | \(-\frac {2 i \ln \left ({\mathrm e}^{\frac {i x}{2}}\right )}{{\mathrm e}^{i x}+1}+\frac {\pi \,\operatorname {csgn}\left (i \left ({\mathrm e}^{i x}+1\right )\right ) \operatorname {csgn}\left (i {\mathrm e}^{-\frac {i x}{2}}\right ) \operatorname {csgn}\left (i \cos \left (\frac {x}{2}\right )\right )-\pi \,\operatorname {csgn}\left (i \left ({\mathrm e}^{i x}+1\right )\right ) \operatorname {csgn}\left (i \cos \left (\frac {x}{2}\right )\right )^{2}-\pi \,\operatorname {csgn}\left (i {\mathrm e}^{-\frac {i x}{2}}\right ) \operatorname {csgn}\left (i \cos \left (\frac {x}{2}\right )\right )^{2}+\pi \operatorname {csgn}\left (i \cos \left (\frac {x}{2}\right )\right )^{3}-i \ln \left ({\mathrm e}^{i x}+1\right ) {\mathrm e}^{i x}-x \,{\mathrm e}^{i x}-2 i \ln \left (2\right )+i \ln \left ({\mathrm e}^{i x}+1\right )+2 i-x}{{\mathrm e}^{i x}+1}\) | \(164\) |
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none
Time = 0.24 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.14 \[ \int \frac {\log \left (\cos \left (\frac {x}{2}\right )\right )}{1+\cos (x)} \, dx=-\frac {x \cos \left (\frac {1}{2} \, x\right ) - 2 \, \log \left (\cos \left (\frac {1}{2} \, x\right )\right ) \sin \left (\frac {1}{2} \, x\right ) - 2 \, \sin \left (\frac {1}{2} \, x\right )}{2 \, \cos \left (\frac {1}{2} \, x\right )} \]
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\[ \int \frac {\log \left (\cos \left (\frac {x}{2}\right )\right )}{1+\cos (x)} \, dx=\int \frac {\log {\left (\cos {\left (\frac {x}{2} \right )} \right )}}{\cos {\left (x \right )} + 1}\, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. 56 vs. \(2 (22) = 44\).
Time = 0.20 (sec) , antiderivative size = 56, normalized size of antiderivative = 2.00 \[ \int \frac {\log \left (\cos \left (\frac {x}{2}\right )\right )}{1+\cos (x)} \, dx=\frac {\log \left (\cos \left (\frac {1}{2} \, x\right )\right ) \sin \left (x\right )}{\cos \left (x\right ) + 1} - \frac {x \cos \left (x\right )^{2} + x \sin \left (x\right )^{2} + 2 \, x \cos \left (x\right ) + x - 4 \, \sin \left (x\right )}{2 \, {\left (\cos \left (x\right )^{2} + \sin \left (x\right )^{2} + 2 \, \cos \left (x\right ) + 1\right )}} \]
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Time = 0.31 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.54 \[ \int \frac {\log \left (\cos \left (\frac {x}{2}\right )\right )}{1+\cos (x)} \, dx=-\frac {1}{2} \, x - \frac {2 \, \log \left (\cos \left (\frac {1}{2} \, x\right )\right ) \tan \left (\frac {1}{2} \, x\right )}{{\left (x^{2} + 1\right )} {\left (\frac {x^{2} - 1}{x^{2} + 1} - 1\right )}} + \tan \left (\frac {1}{2} \, x\right ) \]
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Time = 0.64 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.39 \[ \int \frac {\log \left (\cos \left (\frac {x}{2}\right )\right )}{1+\cos (x)} \, dx=\mathrm {tan}\left (\frac {x}{2}\right )-x+\mathrm {tan}\left (\frac {x}{2}\right )\,\ln \left (\cos \left (\frac {x}{2}\right )\right )+\ln \left (\cos \left (\frac {x}{2}\right )\right )\,1{}\mathrm {i}-\ln \left (\cos \left (x\right )+1+\sin \left (x\right )\,1{}\mathrm {i}\right )\,1{}\mathrm {i} \]
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