Integrand size = 12, antiderivative size = 57 \[ \int \frac {\arcsin (x)}{(1-x)^{5/2}} \, dx=-\frac {\sqrt {1+x}}{3 (1-x)}+\frac {2 \arcsin (x)}{3 (1-x)^{3/2}}-\frac {\text {arctanh}\left (\frac {\sqrt {1+x}}{\sqrt {2}}\right )}{3 \sqrt {2}} \]
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Time = 0.02 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {4827, 641, 44, 65, 212} \[ \int \frac {\arcsin (x)}{(1-x)^{5/2}} \, dx=\frac {2 \arcsin (x)}{3 (1-x)^{3/2}}-\frac {\text {arctanh}\left (\frac {\sqrt {x+1}}{\sqrt {2}}\right )}{3 \sqrt {2}}-\frac {\sqrt {x+1}}{3 (1-x)} \]
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Rule 44
Rule 65
Rule 212
Rule 641
Rule 4827
Rubi steps \begin{align*} \text {integral}& = \frac {2 \arcsin (x)}{3 (1-x)^{3/2}}-\frac {2}{3} \int \frac {1}{(1-x)^{3/2} \sqrt {1-x^2}} \, dx \\ & = \frac {2 \arcsin (x)}{3 (1-x)^{3/2}}-\frac {2}{3} \int \frac {1}{(1-x)^2 \sqrt {1+x}} \, dx \\ & = -\frac {\sqrt {1+x}}{3 (1-x)}+\frac {2 \arcsin (x)}{3 (1-x)^{3/2}}-\frac {1}{6} \int \frac {1}{(1-x) \sqrt {1+x}} \, dx \\ & = -\frac {\sqrt {1+x}}{3 (1-x)}+\frac {2 \arcsin (x)}{3 (1-x)^{3/2}}-\frac {1}{3} \text {Subst}\left (\int \frac {1}{2-x^2} \, dx,x,\sqrt {1+x}\right ) \\ & = -\frac {\sqrt {1+x}}{3 (1-x)}+\frac {2 \arcsin (x)}{3 (1-x)^{3/2}}-\frac {\text {arctanh}\left (\frac {\sqrt {1+x}}{\sqrt {2}}\right )}{3 \sqrt {2}} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.07 \[ \int \frac {\arcsin (x)}{(1-x)^{5/2}} \, dx=\frac {1}{6} \left (-\frac {2 \left (\sqrt {1-x^2}-2 \arcsin (x)\right )}{(1-x)^{3/2}}-\sqrt {2} \text {arctanh}\left (\frac {\sqrt {1-x^2}}{\sqrt {2-2 x}}\right )\right ) \]
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Time = 0.29 (sec) , antiderivative size = 70, normalized size of antiderivative = 1.23
method | result | size |
derivativedivides | \(\frac {2 \arcsin \left (x \right )}{3 \left (1-x \right )^{\frac {3}{2}}}-\frac {\sqrt {1+x}\, \left (\sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {2}}{\sqrt {1+x}}\right ) \left (1-x \right )+2 \sqrt {1+x}\right )}{6 \sqrt {1-x}\, \sqrt {-\left (1-x \right )^{2}+2-2 x}}\) | \(70\) |
default | \(\frac {2 \arcsin \left (x \right )}{3 \left (1-x \right )^{\frac {3}{2}}}-\frac {\sqrt {1+x}\, \left (\sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {2}}{\sqrt {1+x}}\right ) \left (1-x \right )+2 \sqrt {1+x}\right )}{6 \sqrt {1-x}\, \sqrt {-\left (1-x \right )^{2}+2-2 x}}\) | \(70\) |
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Leaf count of result is larger than twice the leaf count of optimal. 90 vs. \(2 (40) = 80\).
Time = 0.25 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.58 \[ \int \frac {\arcsin (x)}{(1-x)^{5/2}} \, dx=\frac {\sqrt {2} {\left (x^{2} - 2 \, x + 1\right )} \log \left (-\frac {x^{2} + 2 \, \sqrt {2} \sqrt {-x^{2} + 1} \sqrt {-x + 1} + 2 \, x - 3}{x^{2} - 2 \, x + 1}\right ) - 4 \, \sqrt {-x + 1} {\left (\sqrt {-x^{2} + 1} - 2 \, \arcsin \left (x\right )\right )}}{12 \, {\left (x^{2} - 2 \, x + 1\right )}} \]
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\[ \int \frac {\arcsin (x)}{(1-x)^{5/2}} \, dx=\int \frac {\operatorname {asin}{\left (x \right )}}{\left (1 - x\right )^{\frac {5}{2}}}\, dx \]
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\[ \int \frac {\arcsin (x)}{(1-x)^{5/2}} \, dx=\int { \frac {\arcsin \left (x\right )}{{\left (-x + 1\right )}^{\frac {5}{2}}} \,d x } \]
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none
Time = 0.30 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.02 \[ \int \frac {\arcsin (x)}{(1-x)^{5/2}} \, dx=\frac {1}{12} \, \sqrt {2} \log \left (\frac {\sqrt {2} - \sqrt {x + 1}}{\sqrt {2} + \sqrt {x + 1}}\right ) + \frac {\sqrt {x + 1}}{3 \, {\left (x - 1\right )}} - \frac {2 \, \arcsin \left (x\right )}{3 \, {\left (x - 1\right )} \sqrt {-x + 1}} \]
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Timed out. \[ \int \frac {\arcsin (x)}{(1-x)^{5/2}} \, dx=\int \frac {\mathrm {asin}\left (x\right )}{{\left (1-x\right )}^{5/2}} \,d x \]
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