Integrand size = 15, antiderivative size = 71 \[ \int \sqrt {(b-x) (-a+x)} \, dx=-\frac {1}{4} (a+b-2 x) \sqrt {-a b+(a+b) x-x^2}-\frac {1}{8} (a-b)^2 \arctan \left (\frac {a+b-2 x}{2 \sqrt {-a b+(a+b) x-x^2}}\right ) \]
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Time = 0.02 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {1976, 626, 635, 210} \[ \int \sqrt {(b-x) (-a+x)} \, dx=-\frac {1}{8} (a-b)^2 \arctan \left (\frac {a+b-2 x}{2 \sqrt {x (a+b)-a b-x^2}}\right )-\frac {1}{4} (a+b-2 x) \sqrt {x (a+b)-a b-x^2} \]
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Rule 210
Rule 626
Rule 635
Rule 1976
Rubi steps \begin{align*} \text {integral}& = \int \sqrt {-a b+(a+b) x-x^2} \, dx \\ & = -\frac {1}{4} (a+b-2 x) \sqrt {-a b+(a+b) x-x^2}+\frac {1}{8} (a-b)^2 \int \frac {1}{\sqrt {-a b+(a+b) x-x^2}} \, dx \\ & = -\frac {1}{4} (a+b-2 x) \sqrt {-a b+(a+b) x-x^2}+\frac {1}{4} (a-b)^2 \text {Subst}\left (\int \frac {1}{-4-x^2} \, dx,x,\frac {a+b-2 x}{\sqrt {-a b+(a+b) x-x^2}}\right ) \\ & = -\frac {1}{4} (a+b-2 x) \sqrt {-a b+(a+b) x-x^2}-\frac {1}{8} (a-b)^2 \arctan \left (\frac {a+b-2 x}{2 \sqrt {-a b+(a+b) x-x^2}}\right ) \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.06 \[ \int \sqrt {(b-x) (-a+x)} \, dx=\frac {1}{4} \sqrt {(a-x) (-b+x)} \left (-a-b+2 x+\frac {(a-b)^2 \arctan \left (\frac {\sqrt {-a+x}}{\sqrt {b-x}}\right )}{\sqrt {b-x} \sqrt {-a+x}}\right ) \]
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Time = 0.19 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.96
method | result | size |
default | \(-\frac {\left (a +b -2 x \right ) \sqrt {-a b +\left (a +b \right ) x -x^{2}}}{4}-\frac {\left (4 a b -\left (a +b \right )^{2}\right ) \arctan \left (\frac {x -\frac {b}{2}-\frac {a}{2}}{\sqrt {-a b +\left (a +b \right ) x -x^{2}}}\right )}{8}\) | \(68\) |
risch | \(\frac {\left (b -x \right ) \left (a -x \right ) \left (a +b -2 x \right )}{4 \sqrt {-\left (-b +x \right ) \left (-a +x \right )}}-\left (\frac {1}{4} a b -\frac {1}{8} b^{2}-\frac {1}{8} a^{2}\right ) \arctan \left (\frac {x -\frac {b}{2}-\frac {a}{2}}{\sqrt {-a b +\left (a +b \right ) x -x^{2}}}\right )\) | \(78\) |
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none
Time = 0.25 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.13 \[ \int \sqrt {(b-x) (-a+x)} \, dx=-\frac {1}{8} \, {\left (a^{2} - 2 \, a b + b^{2}\right )} \arctan \left (-\frac {\sqrt {-a b + {\left (a + b\right )} x - x^{2}} {\left (a + b - 2 \, x\right )}}{2 \, {\left (a b - {\left (a + b\right )} x + x^{2}\right )}}\right ) - \frac {1}{4} \, \sqrt {-a b + {\left (a + b\right )} x - x^{2}} {\left (a + b - 2 \, x\right )} \]
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Time = 1.08 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.61 \[ \int \sqrt {(b-x) (-a+x)} \, dx=\left (- \frac {a b}{2} + \frac {\left (\frac {a}{4} + \frac {b}{4}\right ) \left (a + b\right )}{2}\right ) \left (\begin {cases} - i \log {\left (a + b - 2 x + 2 i \sqrt {- a b - x^{2} + x \left (a + b\right )} \right )} & \text {for}\: a b - \frac {\left (a + b\right )^{2}}{4} \neq 0 \\\frac {\left (- \frac {a}{2} - \frac {b}{2} + x\right ) \log {\left (- \frac {a}{2} - \frac {b}{2} + x \right )}}{\sqrt {- \left (- \frac {a}{2} - \frac {b}{2} + x\right )^{2}}} & \text {otherwise} \end {cases}\right ) + \left (- \frac {a}{4} - \frac {b}{4} + \frac {x}{2}\right ) \sqrt {- a b - x^{2} + x \left (a + b\right )} \]
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Exception generated. \[ \int \sqrt {(b-x) (-a+x)} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.29 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.86 \[ \int \sqrt {(b-x) (-a+x)} \, dx=\frac {1}{8} \, {\left (a^{2} - 2 \, a b + b^{2}\right )} \arcsin \left (\frac {a + b - 2 \, x}{a - b}\right ) \mathrm {sgn}\left (-a + b\right ) - \frac {1}{4} \, \sqrt {-a b + a x + b x - x^{2}} {\left (a + b - 2 \, x\right )} \]
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Timed out. \[ \int \sqrt {(b-x) (-a+x)} \, dx=\int \sqrt {-\left (a-x\right )\,\left (b-x\right )} \,d x \]
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