Integrand size = 19, antiderivative size = 73 \[ \int \frac {1}{x-\sqrt {1+\sqrt {1+x}}} \, dx=\frac {2}{5} \left (5+\sqrt {5}\right ) \log \left (1-\sqrt {5}-2 \sqrt {1+\sqrt {1+x}}\right )+\frac {2}{5} \left (5-\sqrt {5}\right ) \log \left (1+\sqrt {5}-2 \sqrt {1+\sqrt {1+x}}\right ) \]
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Time = 0.08 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {646, 31} \[ \int \frac {1}{x-\sqrt {1+\sqrt {1+x}}} \, dx=\frac {2}{5} \left (5+\sqrt {5}\right ) \log \left (-2 \sqrt {\sqrt {x+1}+1}-\sqrt {5}+1\right )+\frac {2}{5} \left (5-\sqrt {5}\right ) \log \left (-2 \sqrt {\sqrt {x+1}+1}+\sqrt {5}+1\right ) \]
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Rule 31
Rule 646
Rubi steps \begin{align*} \text {integral}& = 2 \text {Subst}\left (\int \frac {x}{-1+x^2-\sqrt {1+x}} \, dx,x,\sqrt {1+x}\right ) \\ & = 4 \text {Subst}\left (\int \frac {-1+x}{-1-x+x^2} \, dx,x,\sqrt {1+\sqrt {1+x}}\right ) \\ & = \frac {1}{5} \left (2 \left (5-\sqrt {5}\right )\right ) \text {Subst}\left (\int \frac {1}{-\frac {1}{2}-\frac {\sqrt {5}}{2}+x} \, dx,x,\sqrt {1+\sqrt {1+x}}\right )+\frac {1}{5} \left (2 \left (5+\sqrt {5}\right )\right ) \text {Subst}\left (\int \frac {1}{-\frac {1}{2}+\frac {\sqrt {5}}{2}+x} \, dx,x,\sqrt {1+\sqrt {1+x}}\right ) \\ & = \frac {2}{5} \left (5+\sqrt {5}\right ) \log \left (1-\sqrt {5}-2 \sqrt {1+\sqrt {1+x}}\right )+\frac {2}{5} \left (5-\sqrt {5}\right ) \log \left (1+\sqrt {5}-2 \sqrt {1+\sqrt {1+x}}\right ) \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.95 \[ \int \frac {1}{x-\sqrt {1+\sqrt {1+x}}} \, dx=-\frac {2}{5} \left (-5+\sqrt {5}\right ) \log \left (1+\sqrt {5}-2 \sqrt {1+\sqrt {1+x}}\right )+\frac {2}{5} \left (5+\sqrt {5}\right ) \log \left (-1+\sqrt {5}+2 \sqrt {1+\sqrt {1+x}}\right ) \]
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Time = 0.15 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.63
method | result | size |
derivativedivides | \(2 \ln \left (\sqrt {1+x}-\sqrt {1+\sqrt {1+x}}\right )+\frac {4 \sqrt {5}\, \operatorname {arctanh}\left (\frac {\left (2 \sqrt {1+\sqrt {1+x}}-1\right ) \sqrt {5}}{5}\right )}{5}\) | \(46\) |
default | \(\frac {\ln \left (x^{2}-x -1\right )}{2}+\frac {\sqrt {5}\, \operatorname {arctanh}\left (\frac {\left (2 x -1\right ) \sqrt {5}}{5}\right )}{5}-\ln \left (\sqrt {1+x}+\sqrt {1+\sqrt {1+x}}\right )+\frac {2 \,\operatorname {arctanh}\left (\frac {\left (1+2 \sqrt {1+\sqrt {1+x}}\right ) \sqrt {5}}{5}\right ) \sqrt {5}}{5}+\ln \left (\sqrt {1+x}-\sqrt {1+\sqrt {1+x}}\right )+\frac {2 \sqrt {5}\, \operatorname {arctanh}\left (\frac {\left (2 \sqrt {1+\sqrt {1+x}}-1\right ) \sqrt {5}}{5}\right )}{5}+\frac {2 \left (7+3 \sqrt {5}\right ) \sqrt {5}\, \operatorname {arctanh}\left (\frac {2 \sqrt {1+\sqrt {1+x}}}{\sqrt {2+2 \sqrt {5}}}\right )}{5 \sqrt {2+2 \sqrt {5}}}-\frac {2 \sqrt {5}\, \left (-7+3 \sqrt {5}\right ) \arctan \left (\frac {2 \sqrt {1+\sqrt {1+x}}}{\sqrt {-2+2 \sqrt {5}}}\right )}{5 \sqrt {-2+2 \sqrt {5}}}-\frac {\ln \left (x +\sqrt {1+x}\right )}{2}+\frac {\sqrt {5}\, \operatorname {arctanh}\left (\frac {\left (1+2 \sqrt {1+x}\right ) \sqrt {5}}{5}\right )}{5}+\frac {\ln \left (x -\sqrt {1+x}\right )}{2}+\frac {\sqrt {5}\, \operatorname {arctanh}\left (\frac {\left (2 \sqrt {1+x}-1\right ) \sqrt {5}}{5}\right )}{5}-\frac {2 \left (3+\sqrt {5}\right ) \sqrt {5}\, \operatorname {arctanh}\left (\frac {2 \sqrt {1+\sqrt {1+x}}}{\sqrt {2+2 \sqrt {5}}}\right )}{5 \sqrt {2+2 \sqrt {5}}}+\frac {2 \left (\sqrt {5}-3\right ) \sqrt {5}\, \arctan \left (\frac {2 \sqrt {1+\sqrt {1+x}}}{\sqrt {-2+2 \sqrt {5}}}\right )}{5 \sqrt {-2+2 \sqrt {5}}}-\frac {4 \left (2+\sqrt {5}\right ) \sqrt {5}\, \operatorname {arctanh}\left (\frac {2 \sqrt {1+\sqrt {1+x}}}{\sqrt {2+2 \sqrt {5}}}\right )}{5 \sqrt {2+2 \sqrt {5}}}+\frac {4 \left (-2+\sqrt {5}\right ) \sqrt {5}\, \arctan \left (\frac {2 \sqrt {1+\sqrt {1+x}}}{\sqrt {-2+2 \sqrt {5}}}\right )}{5 \sqrt {-2+2 \sqrt {5}}}\) | \(419\) |
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Leaf count of result is larger than twice the leaf count of optimal. 112 vs. \(2 (51) = 102\).
Time = 0.25 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.53 \[ \int \frac {1}{x-\sqrt {1+\sqrt {1+x}}} \, dx=\frac {2}{5} \, \sqrt {5} \log \left (\frac {2 \, x^{2} + \sqrt {5} {\left (3 \, x + 1\right )} + {\left (\sqrt {5} {\left (x + 2\right )} + 5 \, x\right )} \sqrt {x + 1} + {\left (\sqrt {5} {\left (x + 2\right )} + {\left (\sqrt {5} {\left (2 \, x - 1\right )} + 5\right )} \sqrt {x + 1} + 5 \, x\right )} \sqrt {\sqrt {x + 1} + 1} + 3 \, x + 3}{x^{2} - x - 1}\right ) + 2 \, \log \left (\sqrt {x + 1} - \sqrt {\sqrt {x + 1} + 1}\right ) \]
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Time = 2.49 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.04 \[ \int \frac {1}{x-\sqrt {1+\sqrt {1+x}}} \, dx=- \frac {2 \sqrt {5} \left (- \log {\left (\sqrt {\sqrt {x + 1} + 1} - \frac {1}{2} + \frac {\sqrt {5}}{2} \right )} + \log {\left (\sqrt {\sqrt {x + 1} + 1} - \frac {\sqrt {5}}{2} - \frac {1}{2} \right )}\right )}{5} + 2 \log {\left (\sqrt {x + 1} - \sqrt {\sqrt {x + 1} + 1} \right )} \]
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none
Time = 0.27 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.86 \[ \int \frac {1}{x-\sqrt {1+\sqrt {1+x}}} \, dx=-\frac {2}{5} \, \sqrt {5} \log \left (-\frac {\sqrt {5} - 2 \, \sqrt {\sqrt {x + 1} + 1} + 1}{\sqrt {5} + 2 \, \sqrt {\sqrt {x + 1} + 1} - 1}\right ) + 2 \, \log \left (\sqrt {x + 1} - \sqrt {\sqrt {x + 1} + 1}\right ) \]
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none
Time = 0.49 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.92 \[ \int \frac {1}{x-\sqrt {1+\sqrt {1+x}}} \, dx=-\frac {2}{5} \, \sqrt {5} \log \left (\frac {{\left | -\sqrt {5} + 2 \, \sqrt {\sqrt {x + 1} + 1} - 1 \right |}}{{\left | \sqrt {5} + 2 \, \sqrt {\sqrt {x + 1} + 1} - 1 \right |}}\right ) + 2 \, \log \left ({\left | \sqrt {x + 1} - \sqrt {\sqrt {x + 1} + 1} \right |}\right ) \]
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Timed out. \[ \int \frac {1}{x-\sqrt {1+\sqrt {1+x}}} \, dx=\int \frac {1}{x-\sqrt {\sqrt {x+1}+1}} \,d x \]
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