Integrand size = 18, antiderivative size = 55 \[ \int \arctan \left (\frac {-\sqrt {2}+2 x}{\sqrt {2}}\right ) \, dx=\frac {\arctan \left (1-\sqrt {2} x\right )}{\sqrt {2}}-x \arctan \left (1-\sqrt {2} x\right )-\frac {\log \left (1-\sqrt {2} x+x^2\right )}{2 \sqrt {2}} \]
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Time = 0.03 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {5311, 12, 648, 631, 210, 642} \[ \int \arctan \left (\frac {-\sqrt {2}+2 x}{\sqrt {2}}\right ) \, dx=-x \arctan \left (1-\sqrt {2} x\right )+\frac {\arctan \left (1-\sqrt {2} x\right )}{\sqrt {2}}-\frac {\log \left (x^2-\sqrt {2} x+1\right )}{2 \sqrt {2}} \]
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Rule 12
Rule 210
Rule 631
Rule 642
Rule 648
Rule 5311
Rubi steps \begin{align*} \text {integral}& = -x \arctan \left (1-\sqrt {2} x\right )-\int \frac {x}{\sqrt {2} \left (1-\sqrt {2} x+x^2\right )} \, dx \\ & = -x \arctan \left (1-\sqrt {2} x\right )-\frac {\int \frac {x}{1-\sqrt {2} x+x^2} \, dx}{\sqrt {2}} \\ & = -x \arctan \left (1-\sqrt {2} x\right )-\frac {1}{2} \int \frac {1}{1-\sqrt {2} x+x^2} \, dx-\frac {\int \frac {-\sqrt {2}+2 x}{1-\sqrt {2} x+x^2} \, dx}{2 \sqrt {2}} \\ & = -x \arctan \left (1-\sqrt {2} x\right )-\frac {\log \left (1-\sqrt {2} x+x^2\right )}{2 \sqrt {2}}-\frac {\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\sqrt {2} x\right )}{\sqrt {2}} \\ & = \frac {\arctan \left (1-\sqrt {2} x\right )}{\sqrt {2}}-x \arctan \left (1-\sqrt {2} x\right )-\frac {\log \left (1-\sqrt {2} x+x^2\right )}{2 \sqrt {2}} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.87 \[ \int \arctan \left (\frac {-\sqrt {2}+2 x}{\sqrt {2}}\right ) \, dx=\frac {1}{4} \left (2 \left (\sqrt {2}-2 x\right ) \arctan \left (1-\sqrt {2} x\right )-\sqrt {2} \log \left (1-\sqrt {2} x+x^2\right )\right ) \]
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Time = 0.15 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.67
method | result | size |
derivativedivides | \(\frac {\sqrt {2}\, \left (\left (-1+x \sqrt {2}\right ) \arctan \left (-1+x \sqrt {2}\right )-\frac {\ln \left (\left (-1+x \sqrt {2}\right )^{2}+1\right )}{2}\right )}{2}\) | \(37\) |
default | \(\frac {\sqrt {2}\, \left (\left (-1+x \sqrt {2}\right ) \arctan \left (-1+x \sqrt {2}\right )-\frac {\ln \left (\left (-1+x \sqrt {2}\right )^{2}+1\right )}{2}\right )}{2}\) | \(37\) |
parts | \(x \arctan \left (\frac {\left (2 x -\sqrt {2}\right ) \sqrt {2}}{2}\right )-2 \sqrt {2}\, \left (\frac {\ln \left (1+x^{2}-x \sqrt {2}\right )}{8}+\frac {\arctan \left (\frac {\left (2 x -\sqrt {2}\right ) \sqrt {2}}{2}\right )}{4}\right )\) | \(56\) |
risch | \(\frac {i x \ln \left (1+\frac {i \left (-2 x +\sqrt {2}\right ) \sqrt {2}}{2}\right )}{2}-\frac {i x \ln \left (1-\frac {i \left (-2 x +\sqrt {2}\right ) \sqrt {2}}{2}\right )}{2}-\frac {\sqrt {2}\, \ln \left (4-4 x \sqrt {2}+4 x^{2}\right )}{4}-\frac {\sqrt {2}\, \arctan \left (\frac {\left (2 x -\sqrt {2}\right ) \sqrt {2}}{2}\right )}{2}\) | \(81\) |
parallelrisch | \(\frac {\sqrt {2}\, \ln \left (1+x^{2}-x \sqrt {2}\right ) x^{2}+6 \sqrt {2}\, \arctan \left (\frac {\left (2 x -\sqrt {2}\right ) \sqrt {2}}{2}\right ) x^{2}-4 x^{3} \arctan \left (\frac {\left (2 x -\sqrt {2}\right ) \sqrt {2}}{2}\right )+\ln \left (1+x^{2}-x \sqrt {2}\right ) \sqrt {2}+2 \sqrt {2}\, \arctan \left (\frac {\left (2 x -\sqrt {2}\right ) \sqrt {2}}{2}\right )-2 \ln \left (1+x^{2}-x \sqrt {2}\right ) x -8 x \arctan \left (\frac {\left (2 x -\sqrt {2}\right ) \sqrt {2}}{2}\right )}{4 x \sqrt {2}-4 x^{2}-4}\) | \(149\) |
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Time = 0.25 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.67 \[ \int \arctan \left (\frac {-\sqrt {2}+2 x}{\sqrt {2}}\right ) \, dx=\frac {1}{2} \, {\left (2 \, x - \sqrt {2}\right )} \arctan \left (\sqrt {2} x - 1\right ) - \frac {1}{4} \, \sqrt {2} \log \left (x^{2} - \sqrt {2} x + 1\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 230 vs. \(2 (48) = 96\).
Time = 0.48 (sec) , antiderivative size = 230, normalized size of antiderivative = 4.18 \[ \int \arctan \left (\frac {-\sqrt {2}+2 x}{\sqrt {2}}\right ) \, dx=\frac {4 x^{3} \operatorname {atan}{\left (\sqrt {2} x - 1 \right )}}{4 x^{2} - 4 \sqrt {2} x + 4} - \frac {\sqrt {2} x^{2} \log {\left (x^{2} - \sqrt {2} x + 1 \right )}}{4 x^{2} - 4 \sqrt {2} x + 4} - \frac {6 \sqrt {2} x^{2} \operatorname {atan}{\left (\sqrt {2} x - 1 \right )}}{4 x^{2} - 4 \sqrt {2} x + 4} + \frac {2 x \log {\left (x^{2} - \sqrt {2} x + 1 \right )}}{4 x^{2} - 4 \sqrt {2} x + 4} + \frac {8 x \operatorname {atan}{\left (\sqrt {2} x - 1 \right )}}{4 x^{2} - 4 \sqrt {2} x + 4} - \frac {\sqrt {2} \log {\left (x^{2} - \sqrt {2} x + 1 \right )}}{4 x^{2} - 4 \sqrt {2} x + 4} - \frac {2 \sqrt {2} \operatorname {atan}{\left (\sqrt {2} x - 1 \right )}}{4 x^{2} - 4 \sqrt {2} x + 4} \]
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Time = 0.27 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.95 \[ \int \arctan \left (\frac {-\sqrt {2}+2 x}{\sqrt {2}}\right ) \, dx=\frac {1}{4} \, \sqrt {2} {\left (\sqrt {2} {\left (2 \, x - \sqrt {2}\right )} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (2 \, x - \sqrt {2}\right )}\right ) - \log \left (\frac {1}{2} \, {\left (2 \, x - \sqrt {2}\right )}^{2} + 1\right )\right )} \]
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Time = 0.28 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.95 \[ \int \arctan \left (\frac {-\sqrt {2}+2 x}{\sqrt {2}}\right ) \, dx=\frac {1}{4} \, \sqrt {2} {\left (\sqrt {2} {\left (2 \, x - \sqrt {2}\right )} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (2 \, x - \sqrt {2}\right )}\right ) - \log \left (\frac {1}{2} \, {\left (2 \, x - \sqrt {2}\right )}^{2} + 1\right )\right )} \]
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Time = 0.18 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.78 \[ \int \arctan \left (\frac {-\sqrt {2}+2 x}{\sqrt {2}}\right ) \, dx=\mathrm {atan}\left (\frac {\sqrt {2}\,\left (2\,x-\sqrt {2}\right )}{2}\right )\,\left (x-\frac {\sqrt {2}}{2}\right )-\frac {\sqrt {2}\,\ln \left ({\left (2\,x-\sqrt {2}\right )}^2+2\right )}{4} \]
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