Integrand size = 8, antiderivative size = 43 \[ \int \frac {1}{3-5 \sin (x)} \, dx=-\frac {1}{4} \log \left (\cos \left (\frac {x}{2}\right )-3 \sin \left (\frac {x}{2}\right )\right )+\frac {1}{4} \log \left (3 \cos \left (\frac {x}{2}\right )-\sin \left (\frac {x}{2}\right )\right ) \]
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Time = 0.02 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {2739, 630, 31} \[ \int \frac {1}{3-5 \sin (x)} \, dx=\frac {1}{4} \log \left (3 \cos \left (\frac {x}{2}\right )-\sin \left (\frac {x}{2}\right )\right )-\frac {1}{4} \log \left (\cos \left (\frac {x}{2}\right )-3 \sin \left (\frac {x}{2}\right )\right ) \]
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Rule 31
Rule 630
Rule 2739
Rubi steps \begin{align*} \text {integral}& = 2 \text {Subst}\left (\int \frac {1}{3-10 x+3 x^2} \, dx,x,\tan \left (\frac {x}{2}\right )\right ) \\ & = \frac {3}{4} \text {Subst}\left (\int \frac {1}{-9+3 x} \, dx,x,\tan \left (\frac {x}{2}\right )\right )-\frac {3}{4} \text {Subst}\left (\int \frac {1}{-1+3 x} \, dx,x,\tan \left (\frac {x}{2}\right )\right ) \\ & = -\frac {1}{4} \log \left (1-3 \tan \left (\frac {x}{2}\right )\right )+\frac {1}{4} \log \left (3-\tan \left (\frac {x}{2}\right )\right ) \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.00 \[ \int \frac {1}{3-5 \sin (x)} \, dx=-\frac {1}{4} \log \left (\cos \left (\frac {x}{2}\right )-3 \sin \left (\frac {x}{2}\right )\right )+\frac {1}{4} \log \left (3 \cos \left (\frac {x}{2}\right )-\sin \left (\frac {x}{2}\right )\right ) \]
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Time = 0.14 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.51
method | result | size |
default | \(-\frac {\ln \left (3 \tan \left (\frac {x}{2}\right )-1\right )}{4}+\frac {\ln \left (\tan \left (\frac {x}{2}\right )-3\right )}{4}\) | \(22\) |
norman | \(-\frac {\ln \left (3 \tan \left (\frac {x}{2}\right )-1\right )}{4}+\frac {\ln \left (\tan \left (\frac {x}{2}\right )-3\right )}{4}\) | \(22\) |
parallelrisch | \(\ln \left (\left (3 \tan \left (\frac {x}{2}\right )-9\right )^{\frac {1}{4}}\right )+\ln \left (\frac {1}{\left (3 \tan \left (\frac {x}{2}\right )-1\right )^{\frac {1}{4}}}\right )\) | \(24\) |
risch | \(\frac {\ln \left (\frac {4}{5}-\frac {3 i}{5}+{\mathrm e}^{i x}\right )}{4}-\frac {\ln \left ({\mathrm e}^{i x}-\frac {4}{5}-\frac {3 i}{5}\right )}{4}\) | \(26\) |
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Time = 0.28 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.63 \[ \int \frac {1}{3-5 \sin (x)} \, dx=\frac {1}{8} \, \log \left (4 \, \cos \left (x\right ) - 3 \, \sin \left (x\right ) + 5\right ) - \frac {1}{8} \, \log \left (-4 \, \cos \left (x\right ) - 3 \, \sin \left (x\right ) + 5\right ) \]
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Time = 0.11 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.47 \[ \int \frac {1}{3-5 \sin (x)} \, dx=\frac {\log {\left (\tan {\left (\frac {x}{2} \right )} - 3 \right )}}{4} - \frac {\log {\left (3 \tan {\left (\frac {x}{2} \right )} - 1 \right )}}{4} \]
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Time = 0.20 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.70 \[ \int \frac {1}{3-5 \sin (x)} \, dx=-\frac {1}{4} \, \log \left (\frac {3 \, \sin \left (x\right )}{\cos \left (x\right ) + 1} - 1\right ) + \frac {1}{4} \, \log \left (\frac {\sin \left (x\right )}{\cos \left (x\right ) + 1} - 3\right ) \]
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Time = 0.29 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.53 \[ \int \frac {1}{3-5 \sin (x)} \, dx=-\frac {1}{4} \, \log \left ({\left | 3 \, \tan \left (\frac {1}{2} \, x\right ) - 1 \right |}\right ) + \frac {1}{4} \, \log \left ({\left | \tan \left (\frac {1}{2} \, x\right ) - 3 \right |}\right ) \]
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Time = 0.46 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.26 \[ \int \frac {1}{3-5 \sin (x)} \, dx=-\frac {\mathrm {atanh}\left (\frac {3\,\mathrm {tan}\left (\frac {x}{2}\right )}{4}-\frac {5}{4}\right )}{2} \]
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