Integrand size = 12, antiderivative size = 20 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{\sqrt {x}} \, dx=2 \sqrt {x} \arctan \left (\sqrt {x}\right )-\log (1+x) \]
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Time = 0.01 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {4946, 31} \[ \int \frac {\arctan \left (\sqrt {x}\right )}{\sqrt {x}} \, dx=2 \sqrt {x} \arctan \left (\sqrt {x}\right )-\log (x+1) \]
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Rule 31
Rule 4946
Rubi steps \begin{align*} \text {integral}& = 2 \sqrt {x} \arctan \left (\sqrt {x}\right )-\int \frac {1}{1+x} \, dx \\ & = 2 \sqrt {x} \arctan \left (\sqrt {x}\right )-\log (1+x) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.00 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{\sqrt {x}} \, dx=2 \sqrt {x} \arctan \left (\sqrt {x}\right )-\log (1+x) \]
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Time = 0.04 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.85
method | result | size |
derivativedivides | \(-\ln \left (1+x \right )+2 \arctan \left (\sqrt {x}\right ) \sqrt {x}\) | \(17\) |
default | \(-\ln \left (1+x \right )+2 \arctan \left (\sqrt {x}\right ) \sqrt {x}\) | \(17\) |
meijerg | \(-\ln \left (1+x \right )+2 \arctan \left (\sqrt {x}\right ) \sqrt {x}\) | \(17\) |
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none
Time = 0.26 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{\sqrt {x}} \, dx=2 \, \sqrt {x} \arctan \left (\sqrt {x}\right ) - \log \left (x + 1\right ) \]
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Time = 0.13 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.85 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{\sqrt {x}} \, dx=2 \sqrt {x} \operatorname {atan}{\left (\sqrt {x} \right )} - \log {\left (x + 1 \right )} \]
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none
Time = 0.21 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{\sqrt {x}} \, dx=2 \, \sqrt {x} \arctan \left (\sqrt {x}\right ) - \log \left (x + 1\right ) \]
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none
Time = 0.27 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{\sqrt {x}} \, dx=2 \, \sqrt {x} \arctan \left (\sqrt {x}\right ) - \log \left (x + 1\right ) \]
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Time = 0.31 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{\sqrt {x}} \, dx=2\,\sqrt {x}\,\mathrm {atan}\left (\sqrt {x}\right )-\ln \left (x+1\right ) \]
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