Integrand size = 17, antiderivative size = 6 \[ \int \left (e^{-e^x+x}+e^{e^x+x}\right ) \, dx=2 \sinh \left (e^x\right ) \]
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Leaf count is larger than twice the leaf count of optimal. \(15\) vs. \(2(6)=12\).
Time = 0.02 (sec) , antiderivative size = 15, normalized size of antiderivative = 2.50, number of steps used = 5, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {2320, 2225} \[ \int \left (e^{-e^x+x}+e^{e^x+x}\right ) \, dx=e^{e^x}-e^{-e^x} \]
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Rule 2225
Rule 2320
Rubi steps \begin{align*} \text {integral}& = \int e^{-e^x+x} \, dx+\int e^{e^x+x} \, dx \\ & = \text {Subst}\left (\int e^{-x} \, dx,x,e^x\right )+\text {Subst}\left (\int e^x \, dx,x,e^x\right ) \\ & = -e^{-e^x}+e^{e^x} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(15\) vs. \(2(6)=12\).
Time = 0.02 (sec) , antiderivative size = 15, normalized size of antiderivative = 2.50 \[ \int \left (e^{-e^x+x}+e^{e^x+x}\right ) \, dx=-e^{-e^x}+e^{e^x} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(11\) vs. \(2(5)=10\).
Time = 0.03 (sec) , antiderivative size = 12, normalized size of antiderivative = 2.00
method | result | size |
default | \(-{\mathrm e}^{-{\mathrm e}^{x}}+{\mathrm e}^{{\mathrm e}^{x}}\) | \(12\) |
parts | \(-{\mathrm e}^{-{\mathrm e}^{x}}+{\mathrm e}^{{\mathrm e}^{x}}\) | \(12\) |
risch | \(\left ({\mathrm e}^{{\mathrm e}^{x}+x}-{\mathrm e}^{x -{\mathrm e}^{x}}\right ) {\mathrm e}^{-x}\) | \(21\) |
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Leaf count of result is larger than twice the leaf count of optimal. 27 vs. \(2 (5) = 10\).
Time = 0.25 (sec) , antiderivative size = 27, normalized size of antiderivative = 4.50 \[ \int \left (e^{-e^x+x}+e^{e^x+x}\right ) \, dx=-{\left (e^{\left (2 \, x\right )} - e^{\left (2 \, x + 2 \, e^{x}\right )}\right )} e^{\left (-2 \, x - e^{x}\right )} \]
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Timed out. \[ \int \left (e^{-e^x+x}+e^{e^x+x}\right ) \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 11 vs. \(2 (5) = 10\).
Time = 0.18 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.83 \[ \int \left (e^{-e^x+x}+e^{e^x+x}\right ) \, dx=-e^{\left (-e^{x}\right )} + e^{\left (e^{x}\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 11 vs. \(2 (5) = 10\).
Time = 0.28 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.83 \[ \int \left (e^{-e^x+x}+e^{e^x+x}\right ) \, dx=-e^{\left (-e^{x}\right )} + e^{\left (e^{x}\right )} \]
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Time = 16.61 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.83 \[ \int \left (e^{-e^x+x}+e^{e^x+x}\right ) \, dx=2\,\mathrm {sinh}\left ({\mathrm {e}}^x\right ) \]
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