Integrand size = 9, antiderivative size = 10 \[ \int \frac {x}{1+x^2} \, dx=\frac {1}{2} \log \left (1+x^2\right ) \]
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Time = 0.00 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {266} \[ \int \frac {x}{1+x^2} \, dx=\frac {1}{2} \log \left (x^2+1\right ) \]
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Rule 266
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \log \left (1+x^2\right ) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00 \[ \int \frac {x}{1+x^2} \, dx=\frac {1}{2} \log \left (1+x^2\right ) \]
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Time = 0.06 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.90
method | result | size |
derivativedivides | \(\frac {\ln \left (x^{2}+1\right )}{2}\) | \(9\) |
default | \(\frac {\ln \left (x^{2}+1\right )}{2}\) | \(9\) |
norman | \(\frac {\ln \left (x^{2}+1\right )}{2}\) | \(9\) |
meijerg | \(\frac {\ln \left (x^{2}+1\right )}{2}\) | \(9\) |
risch | \(\frac {\ln \left (x^{2}+1\right )}{2}\) | \(9\) |
parallelrisch | \(\frac {\ln \left (x^{2}+1\right )}{2}\) | \(9\) |
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none
Time = 0.24 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {x}{1+x^2} \, dx=\frac {1}{2} \, \log \left (x^{2} + 1\right ) \]
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Time = 0.03 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.70 \[ \int \frac {x}{1+x^2} \, dx=\frac {\log {\left (x^{2} + 1 \right )}}{2} \]
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none
Time = 0.20 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {x}{1+x^2} \, dx=\frac {1}{2} \, \log \left (x^{2} + 1\right ) \]
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none
Time = 0.26 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {x}{1+x^2} \, dx=\frac {1}{2} \, \log \left (x^{2} + 1\right ) \]
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Time = 0.03 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {x}{1+x^2} \, dx=\frac {\ln \left (x^2+1\right )}{2} \]
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