Integrand size = 26, antiderivative size = 225 \[ \int \frac {x^2}{\left (a+8 x-8 x^2+4 x^3-x^4\right )^2} \, dx=\frac {1+(-1+x)^2}{2 (4+a) \left (3+a-2 (-1+x)^2-(-1+x)^4\right )}+\frac {(4+a) \left (2+(-1+x)^2\right ) (-1+x)}{4 \left (12+7 a+a^2\right ) \left (3+a-2 (-1+x)^2-(-1+x)^4\right )}-\frac {\left (4+a+\sqrt {4+a}\right ) \arctan \left (\frac {-1+x}{\sqrt {1-\sqrt {4+a}}}\right )}{8 (3+a) (4+a) \sqrt {1-\sqrt {4+a}}}-\frac {\left (4+a-\sqrt {4+a}\right ) \arctan \left (\frac {-1+x}{\sqrt {1+\sqrt {4+a}}}\right )}{8 (3+a) (4+a) \sqrt {1+\sqrt {4+a}}}+\frac {\text {arctanh}\left (\frac {1+(-1+x)^2}{\sqrt {4+a}}\right )}{2 (4+a)^{3/2}} \]
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Time = 0.18 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {1694, 1687, 1192, 1180, 210, 12, 1121, 628, 632, 212} \[ \int \frac {x^2}{\left (a+8 x-8 x^2+4 x^3-x^4\right )^2} \, dx=\frac {(a+4) \left ((x-1)^2+2\right ) (x-1)}{4 \left (a^2+7 a+12\right ) \left (a-(x-1)^4-2 (x-1)^2+3\right )}-\frac {\left (a+\sqrt {a+4}+4\right ) \arctan \left (\frac {x-1}{\sqrt {1-\sqrt {a+4}}}\right )}{8 (a+3) (a+4) \sqrt {1-\sqrt {a+4}}}-\frac {\left (a-\sqrt {a+4}+4\right ) \arctan \left (\frac {x-1}{\sqrt {\sqrt {a+4}+1}}\right )}{8 (a+3) (a+4) \sqrt {\sqrt {a+4}+1}}+\frac {\text {arctanh}\left (\frac {(x-1)^2+1}{\sqrt {a+4}}\right )}{2 (a+4)^{3/2}}+\frac {(x-1)^2+1}{2 (a+4) \left (a-(x-1)^4-2 (x-1)^2+3\right )} \]
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Rule 12
Rule 210
Rule 212
Rule 628
Rule 632
Rule 1121
Rule 1180
Rule 1192
Rule 1687
Rule 1694
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {(1+x)^2}{\left (3+a-2 x^2-x^4\right )^2} \, dx,x,-1+x\right ) \\ & = \text {Subst}\left (\int \frac {2 x}{\left (3+a-2 x^2-x^4\right )^2} \, dx,x,-1+x\right )+\text {Subst}\left (\int \frac {1+x^2}{\left (3+a-2 x^2-x^4\right )^2} \, dx,x,-1+x\right ) \\ & = \frac {(4+a) \left (2+(-1+x)^2\right ) (-1+x)}{4 \left (12+7 a+a^2\right ) \left (3+a-2 (-1+x)^2-(-1+x)^4\right )}+2 \text {Subst}\left (\int \frac {x}{\left (3+a-2 x^2-x^4\right )^2} \, dx,x,-1+x\right )-\frac {\text {Subst}\left (\int \frac {-4 (4+a)-2 (4+a) x^2}{3+a-2 x^2-x^4} \, dx,x,-1+x\right )}{8 \left (12+7 a+a^2\right )} \\ & = \frac {(4+a) \left (2+(-1+x)^2\right ) (-1+x)}{4 \left (12+7 a+a^2\right ) \left (3+a-2 (-1+x)^2-(-1+x)^4\right )}+\frac {\left (4+a-\sqrt {4+a}\right ) \text {Subst}\left (\int \frac {1}{-1-\sqrt {4+a}-x^2} \, dx,x,-1+x\right )}{8 \left (12+7 a+a^2\right )}+\frac {\left (4+a+\sqrt {4+a}\right ) \text {Subst}\left (\int \frac {1}{-1+\sqrt {4+a}-x^2} \, dx,x,-1+x\right )}{8 \left (12+7 a+a^2\right )}+\text {Subst}\left (\int \frac {1}{\left (3+a-2 x-x^2\right )^2} \, dx,x,(-1+x)^2\right ) \\ & = \frac {1+(-1+x)^2}{2 (4+a) \left (3+a-2 (-1+x)^2-(-1+x)^4\right )}+\frac {(4+a) \left (2+(-1+x)^2\right ) (-1+x)}{4 \left (12+7 a+a^2\right ) \left (3+a-2 (-1+x)^2-(-1+x)^4\right )}+\frac {\left (4+a+\sqrt {4+a}\right ) \tan ^{-1}\left (\frac {1-x}{\sqrt {1-\sqrt {4+a}}}\right )}{8 \left (12+7 a+a^2\right ) \sqrt {1-\sqrt {4+a}}}+\frac {\left (4+a-\sqrt {4+a}\right ) \tan ^{-1}\left (\frac {1-x}{\sqrt {1+\sqrt {4+a}}}\right )}{8 \left (12+7 a+a^2\right ) \sqrt {1+\sqrt {4+a}}}+\frac {\text {Subst}\left (\int \frac {1}{3+a-2 x-x^2} \, dx,x,(-1+x)^2\right )}{2 (4+a)} \\ & = \frac {1+(-1+x)^2}{2 (4+a) \left (3+a-2 (-1+x)^2-(-1+x)^4\right )}+\frac {(4+a) \left (2+(-1+x)^2\right ) (-1+x)}{4 \left (12+7 a+a^2\right ) \left (3+a-2 (-1+x)^2-(-1+x)^4\right )}+\frac {\left (4+a+\sqrt {4+a}\right ) \tan ^{-1}\left (\frac {1-x}{\sqrt {1-\sqrt {4+a}}}\right )}{8 \left (12+7 a+a^2\right ) \sqrt {1-\sqrt {4+a}}}+\frac {\left (4+a-\sqrt {4+a}\right ) \tan ^{-1}\left (\frac {1-x}{\sqrt {1+\sqrt {4+a}}}\right )}{8 \left (12+7 a+a^2\right ) \sqrt {1+\sqrt {4+a}}}-\frac {\text {Subst}\left (\int \frac {1}{4 (4+a)-x^2} \, dx,x,-2 \left (1+(-1+x)^2\right )\right )}{4+a} \\ & = \frac {1+(-1+x)^2}{2 (4+a) \left (3+a-2 (-1+x)^2-(-1+x)^4\right )}+\frac {(4+a) \left (2+(-1+x)^2\right ) (-1+x)}{4 \left (12+7 a+a^2\right ) \left (3+a-2 (-1+x)^2-(-1+x)^4\right )}+\frac {\left (4+a+\sqrt {4+a}\right ) \tan ^{-1}\left (\frac {1-x}{\sqrt {1-\sqrt {4+a}}}\right )}{8 \left (12+7 a+a^2\right ) \sqrt {1-\sqrt {4+a}}}+\frac {\left (4+a-\sqrt {4+a}\right ) \tan ^{-1}\left (\frac {1-x}{\sqrt {1+\sqrt {4+a}}}\right )}{8 \left (12+7 a+a^2\right ) \sqrt {1+\sqrt {4+a}}}+\frac {\tanh ^{-1}\left (\frac {1+(-1+x)^2}{\sqrt {4+a}}\right )}{2 (4+a)^{3/2}} \\ \end{align*}
Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.
Time = 0.05 (sec) , antiderivative size = 182, normalized size of antiderivative = 0.81 \[ \int \frac {x^2}{\left (a+8 x-8 x^2+4 x^3-x^4\right )^2} \, dx=\frac {2 x \left (4-3 x+2 x^2\right )+a \left (1+x-x^2+x^3\right )}{4 (3+a) (4+a) \left (a-x \left (-8+8 x-4 x^2+x^3\right )\right )}-\frac {\text {RootSum}\left [a+8 \text {$\#$1}-8 \text {$\#$1}^2+4 \text {$\#$1}^3-\text {$\#$1}^4\&,\frac {-a \log (x-\text {$\#$1})+4 \log (x-\text {$\#$1}) \text {$\#$1}+2 a \log (x-\text {$\#$1}) \text {$\#$1}+4 \log (x-\text {$\#$1}) \text {$\#$1}^2+a \log (x-\text {$\#$1}) \text {$\#$1}^2}{-2+4 \text {$\#$1}-3 \text {$\#$1}^2+\text {$\#$1}^3}\&\right ]}{16 \left (12+7 a+a^2\right )} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.06 (sec) , antiderivative size = 160, normalized size of antiderivative = 0.71
method | result | size |
default | \(\frac {\frac {x^{3}}{4 a +12}-\frac {\left (6+a \right ) x^{2}}{4 \left (3+a \right ) \left (4+a \right )}+\frac {\left (a +8\right ) x}{4 \left (3+a \right ) \left (4+a \right )}+\frac {a}{4 \left (4+a \right ) \left (3+a \right )}}{-x^{4}+4 x^{3}-8 x^{2}+a +8 x}+\frac {\munderset {\textit {\_R} =\operatorname {RootOf}\left (\textit {\_Z}^{4}-4 \textit {\_Z}^{3}+8 \textit {\_Z}^{2}-8 \textit {\_Z} -a \right )}{\sum }\frac {\left (\textit {\_R}^{2} \left (4+a \right )+2 \left (a +2\right ) \textit {\_R} -a \right ) \ln \left (x -\textit {\_R} \right )}{-\textit {\_R}^{3}+3 \textit {\_R}^{2}-4 \textit {\_R} +2}}{16 \left (4+a \right ) \left (3+a \right )}\) | \(160\) |
risch | \(\frac {\frac {x^{3}}{4 a +12}-\frac {\left (6+a \right ) x^{2}}{4 \left (3+a \right ) \left (4+a \right )}+\frac {\left (a +8\right ) x}{4 \left (3+a \right ) \left (4+a \right )}+\frac {a}{4 \left (4+a \right ) \left (3+a \right )}}{-x^{4}+4 x^{3}-8 x^{2}+a +8 x}+\frac {\left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (\textit {\_Z}^{4}-4 \textit {\_Z}^{3}+8 \textit {\_Z}^{2}-8 \textit {\_Z} -a \right )}{\sum }\frac {\left (\frac {\textit {\_R}^{2}}{3+a}+\frac {2 \left (a +2\right ) \textit {\_R}}{\left (3+a \right ) \left (4+a \right )}-\frac {a}{\left (4+a \right ) \left (3+a \right )}\right ) \ln \left (x -\textit {\_R} \right )}{-\textit {\_R}^{3}+3 \textit {\_R}^{2}-4 \textit {\_R} +2}\right )}{16}\) | \(172\) |
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Timed out. \[ \int \frac {x^2}{\left (a+8 x-8 x^2+4 x^3-x^4\right )^2} \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 561 vs. \(2 (185) = 370\).
Time = 18.36 (sec) , antiderivative size = 561, normalized size of antiderivative = 2.49 \[ \int \frac {x^2}{\left (a+8 x-8 x^2+4 x^3-x^4\right )^2} \, dx=\frac {- a + x^{3} \left (- a - 4\right ) + x^{2} \left (a + 6\right ) + x \left (- a - 8\right )}{- 4 a^{3} - 28 a^{2} - 48 a + x^{4} \cdot \left (4 a^{2} + 28 a + 48\right ) + x^{3} \left (- 16 a^{2} - 112 a - 192\right ) + x^{2} \cdot \left (32 a^{2} + 224 a + 384\right ) + x \left (- 32 a^{2} - 224 a - 384\right )} + \operatorname {RootSum} {\left (t^{4} \cdot \left (65536 a^{9} + 2162688 a^{8} + 31653888 a^{7} + 269680640 a^{6} + 1473773568 a^{5} + 5357174784 a^{4} + 12952010752 a^{3} + 20082327552 a^{2} + 18119393280 a + 7247757312\right ) + t^{2} \left (- 9728 a^{6} - 209408 a^{5} - 1878016 a^{4} - 8986624 a^{3} - 24215552 a^{2} - 34865152 a - 20971520\right ) + t \left (256 a^{5} + 5888 a^{4} + 53248 a^{3} + 237568 a^{2} + 524288 a + 458752\right ) - a^{4} + 144 a^{3} + 1024 a^{2} + 1792 a, \left ( t \mapsto t \log {\left (x + \frac {4096 t^{3} a^{12} - 61440 t^{3} a^{11} - 5480448 t^{3} a^{10} - 111403008 t^{3} a^{9} - 1227173888 t^{3} a^{8} - 8682876928 t^{3} a^{7} - 42187440128 t^{3} a^{6} - 144630284288 t^{3} a^{5} - 350972280832 t^{3} a^{4} - 591750234112 t^{3} a^{3} - 660716126208 t^{3} a^{2} - 439848271872 t^{3} a - 132271570944 t^{3} - 28672 t^{2} a^{10} - 993280 t^{2} a^{9} - 15400960 t^{2} a^{8} - 140742656 t^{2} a^{7} - 839462912 t^{2} a^{6} - 3414427648 t^{2} a^{5} - 9590087680 t^{2} a^{4} - 18363547648 t^{2} a^{3} - 22938255360 t^{2} a^{2} - 16873684992 t^{2} a - 5549064192 t^{2} - 848 t a^{9} - 6096 t a^{8} + 174608 t a^{7} + 3323792 t a^{6} + 26276224 t a^{5} + 119009280 t a^{4} + 332017664 t a^{3} + 566497280 t a^{2} + 544112640 t a + 225837056 t + 11 a^{8} + 958 a^{7} + 17419 a^{6} + 142964 a^{5} + 632632 a^{4} + 1567552 a^{3} + 2049792 a^{2} + 1100800 a}{a^{8} + 870 a^{7} + 18289 a^{6} + 165176 a^{5} + 824560 a^{4} + 2452288 a^{3} + 4340224 a^{2} + 4229120 a + 1748992} \right )} \right )\right )} \]
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\[ \int \frac {x^2}{\left (a+8 x-8 x^2+4 x^3-x^4\right )^2} \, dx=\int { \frac {x^{2}}{{\left (x^{4} - 4 \, x^{3} + 8 \, x^{2} - a - 8 \, x\right )}^{2}} \,d x } \]
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\[ \int \frac {x^2}{\left (a+8 x-8 x^2+4 x^3-x^4\right )^2} \, dx=\int { \frac {x^{2}}{{\left (x^{4} - 4 \, x^{3} + 8 \, x^{2} - a - 8 \, x\right )}^{2}} \,d x } \]
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Time = 9.44 (sec) , antiderivative size = 1218, normalized size of antiderivative = 5.41 \[ \int \frac {x^2}{\left (a+8 x-8 x^2+4 x^3-x^4\right )^2} \, dx=\text {Too large to display} \]
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