Integrand size = 29, antiderivative size = 14 \[ \int \frac {1}{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} \, dx=-\frac {1}{2 b (a+b x)^2} \]
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Time = 0.01 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.069, Rules used = {2083, 32} \[ \int \frac {1}{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} \, dx=-\frac {1}{2 b (a+b x)^2} \]
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Rule 32
Rule 2083
Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{(a+b x)^3} \, dx \\ & = -\frac {1}{2 b (a+b x)^2} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00 \[ \int \frac {1}{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} \, dx=-\frac {1}{2 b (a+b x)^2} \]
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Time = 0.04 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.93
method | result | size |
default | \(-\frac {1}{2 b \left (b x +a \right )^{2}}\) | \(13\) |
norman | \(-\frac {1}{2 b \left (b x +a \right )^{2}}\) | \(13\) |
gosper | \(-\frac {1}{2 b \left (b^{2} x^{2}+2 a b x +a^{2}\right )}\) | \(24\) |
risch | \(-\frac {1}{2 b \left (b^{2} x^{2}+2 a b x +a^{2}\right )}\) | \(24\) |
parallelrisch | \(-\frac {1}{2 b \left (b^{2} x^{2}+2 a b x +a^{2}\right )}\) | \(24\) |
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none
Time = 0.24 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.71 \[ \int \frac {1}{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} \, dx=-\frac {1}{2 \, {\left (b^{3} x^{2} + 2 \, a b^{2} x + a^{2} b\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 26 vs. \(2 (12) = 24\).
Time = 0.08 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.86 \[ \int \frac {1}{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} \, dx=- \frac {1}{2 a^{2} b + 4 a b^{2} x + 2 b^{3} x^{2}} \]
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none
Time = 0.20 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.71 \[ \int \frac {1}{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} \, dx=-\frac {1}{2 \, {\left (b^{3} x^{2} + 2 \, a b^{2} x + a^{2} b\right )}} \]
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Time = 0.30 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.86 \[ \int \frac {1}{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} \, dx=-\frac {1}{2 \, {\left (b x + a\right )}^{2} b} \]
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Time = 0.02 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.86 \[ \int \frac {1}{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} \, dx=-\frac {1}{2\,a^2\,b+4\,a\,b^2\,x+2\,b^3\,x^2} \]
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