Integrand size = 38, antiderivative size = 605 \[ \int \frac {A+B x+C x^2+D x^3}{a+b x+c x^2+b x^3+a x^4} \, dx=\frac {\left (4 a^2 B+b \left (b-\sqrt {8 a^2+b^2-4 a c}\right ) D-a \left (A \left (b-\sqrt {8 a^2+b^2-4 a c}\right )+b C-\sqrt {8 a^2+b^2-4 a c} C+2 c D\right )\right ) \arctan \left (\frac {b-\sqrt {8 a^2+b^2-4 a c}+4 a x}{\sqrt {2} \sqrt {4 a^2+2 a c-b \left (b-\sqrt {8 a^2+b^2-4 a c}\right )}}\right )}{\sqrt {2} a \sqrt {8 a^2+b^2-4 a c} \sqrt {4 a^2+2 a c-b \left (b-\sqrt {8 a^2+b^2-4 a c}\right )}}-\frac {\left (4 a^2 B+b \left (b+\sqrt {8 a^2+b^2-4 a c}\right ) D-a \left (A \left (b+\sqrt {8 a^2+b^2-4 a c}\right )+b C+\sqrt {8 a^2+b^2-4 a c} C+2 c D\right )\right ) \arctan \left (\frac {b+\sqrt {8 a^2+b^2-4 a c}+4 a x}{\sqrt {2} \sqrt {4 a^2+2 a c-b \left (b+\sqrt {8 a^2+b^2-4 a c}\right )}}\right )}{\sqrt {2} a \sqrt {8 a^2+b^2-4 a c} \sqrt {4 a^2+2 a c-b \left (b+\sqrt {8 a^2+b^2-4 a c}\right )}}-\frac {\left (2 a (A-C)+\left (b-\sqrt {8 a^2+b^2-4 a c}\right ) D\right ) \log \left (2 a+\left (b-\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2\right )}{4 a \sqrt {8 a^2+b^2-4 a c}}+\frac {\left (2 a (A-C)+\left (b+\sqrt {8 a^2+b^2-4 a c}\right ) D\right ) \log \left (2 a+\left (b+\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2\right )}{4 a \sqrt {8 a^2+b^2-4 a c}} \]
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Time = 3.07 (sec) , antiderivative size = 605, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.132, Rules used = {2111, 648, 632, 210, 642} \[ \int \frac {A+B x+C x^2+D x^3}{a+b x+c x^2+b x^3+a x^4} \, dx=\frac {\arctan \left (\frac {-\sqrt {8 a^2-4 a c+b^2}+4 a x+b}{\sqrt {2} \sqrt {-b \left (b-\sqrt {8 a^2-4 a c+b^2}\right )+4 a^2+2 a c}}\right ) \left (-a \left (A \left (b-\sqrt {8 a^2-4 a c+b^2}\right )-C \sqrt {8 a^2-4 a c+b^2}+b C+2 c D\right )+b D \left (b-\sqrt {8 a^2-4 a c+b^2}\right )+4 a^2 B\right )}{\sqrt {2} a \sqrt {8 a^2-4 a c+b^2} \sqrt {-b \left (b-\sqrt {8 a^2-4 a c+b^2}\right )+4 a^2+2 a c}}-\frac {\arctan \left (\frac {\sqrt {8 a^2-4 a c+b^2}+4 a x+b}{\sqrt {2} \sqrt {-b \left (\sqrt {8 a^2-4 a c+b^2}+b\right )+4 a^2+2 a c}}\right ) \left (-a \left (A \left (\sqrt {8 a^2-4 a c+b^2}+b\right )+C \sqrt {8 a^2-4 a c+b^2}+b C+2 c D\right )+b D \left (\sqrt {8 a^2-4 a c+b^2}+b\right )+4 a^2 B\right )}{\sqrt {2} a \sqrt {8 a^2-4 a c+b^2} \sqrt {-b \left (\sqrt {8 a^2-4 a c+b^2}+b\right )+4 a^2+2 a c}}-\frac {\log \left (x \left (b-\sqrt {8 a^2-4 a c+b^2}\right )+2 a x^2+2 a\right ) \left (D \left (b-\sqrt {8 a^2-4 a c+b^2}\right )+2 a (A-C)\right )}{4 a \sqrt {8 a^2-4 a c+b^2}}+\frac {\log \left (x \left (\sqrt {8 a^2-4 a c+b^2}+b\right )+2 a x^2+2 a\right ) \left (D \left (\sqrt {8 a^2-4 a c+b^2}+b\right )+2 a (A-C)\right )}{4 a \sqrt {8 a^2-4 a c+b^2}} \]
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Rule 210
Rule 632
Rule 642
Rule 648
Rule 2111
Rubi steps \begin{align*} \text {integral}& = -\frac {\int \frac {A b-2 a B-A \sqrt {8 a^2+b^2-4 a c}+2 a D+\left (2 a A-2 a C+b D-\sqrt {8 a^2+b^2-4 a c} D\right ) x}{2 a+\left (b-\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2} \, dx}{\sqrt {8 a^2+b^2-4 a c}}+\frac {\int \frac {A b-2 a B+A \sqrt {8 a^2+b^2-4 a c}+2 a D+\left (2 a A-2 a C+b D+\sqrt {8 a^2+b^2-4 a c} D\right ) x}{2 a+\left (b+\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2} \, dx}{\sqrt {8 a^2+b^2-4 a c}} \\ & = -\frac {\left (2 a (A-C)+\left (b-\sqrt {8 a^2+b^2-4 a c}\right ) D\right ) \int \frac {b-\sqrt {8 a^2+b^2-4 a c}+4 a x}{2 a+\left (b-\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2} \, dx}{4 a \sqrt {8 a^2+b^2-4 a c}}+\frac {\left (2 a (A-C)+\left (b+\sqrt {8 a^2+b^2-4 a c}\right ) D\right ) \int \frac {b+\sqrt {8 a^2+b^2-4 a c}+4 a x}{2 a+\left (b+\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2} \, dx}{4 a \sqrt {8 a^2+b^2-4 a c}}+\frac {\left (4 a^2 B+b \left (b-\sqrt {8 a^2+b^2-4 a c}\right ) D-a \left (A \left (b-\sqrt {8 a^2+b^2-4 a c}\right )+b C-\sqrt {8 a^2+b^2-4 a c} C+2 c D\right )\right ) \int \frac {1}{2 a+\left (b-\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2} \, dx}{2 a \sqrt {8 a^2+b^2-4 a c}}-\frac {\left (4 a^2 B+b \left (b+\sqrt {8 a^2+b^2-4 a c}\right ) D-a \left (A \left (b+\sqrt {8 a^2+b^2-4 a c}\right )+b C+\sqrt {8 a^2+b^2-4 a c} C+2 c D\right )\right ) \int \frac {1}{2 a+\left (b+\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2} \, dx}{2 a \sqrt {8 a^2+b^2-4 a c}} \\ & = -\frac {\left (2 a (A-C)+\left (b-\sqrt {8 a^2+b^2-4 a c}\right ) D\right ) \log \left (2 a+\left (b-\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2\right )}{4 a \sqrt {8 a^2+b^2-4 a c}}+\frac {\left (2 a (A-C)+\left (b+\sqrt {8 a^2+b^2-4 a c}\right ) D\right ) \log \left (2 a+\left (b+\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2\right )}{4 a \sqrt {8 a^2+b^2-4 a c}}-\frac {\left (4 a^2 B+b \left (b-\sqrt {8 a^2+b^2-4 a c}\right ) D-a \left (A \left (b-\sqrt {8 a^2+b^2-4 a c}\right )+b C-\sqrt {8 a^2+b^2-4 a c} C+2 c D\right )\right ) \text {Subst}\left (\int \frac {1}{-16 a^2+\left (b-\sqrt {8 a^2+b^2-4 a c}\right )^2-x^2} \, dx,x,b-\sqrt {8 a^2+b^2-4 a c}+4 a x\right )}{a \sqrt {8 a^2+b^2-4 a c}}+\frac {\left (4 a^2 B+b \left (b+\sqrt {8 a^2+b^2-4 a c}\right ) D-a \left (A \left (b+\sqrt {8 a^2+b^2-4 a c}\right )+b C+\sqrt {8 a^2+b^2-4 a c} C+2 c D\right )\right ) \text {Subst}\left (\int \frac {1}{-16 a^2+\left (b+\sqrt {8 a^2+b^2-4 a c}\right )^2-x^2} \, dx,x,b+\sqrt {8 a^2+b^2-4 a c}+4 a x\right )}{a \sqrt {8 a^2+b^2-4 a c}} \\ & = \frac {\left (4 a^2 B+b \left (b-\sqrt {8 a^2+b^2-4 a c}\right ) D-a \left (A \left (b-\sqrt {8 a^2+b^2-4 a c}\right )+b C-\sqrt {8 a^2+b^2-4 a c} C+2 c D\right )\right ) \tan ^{-1}\left (\frac {b-\sqrt {8 a^2+b^2-4 a c}+4 a x}{\sqrt {2} \sqrt {4 a^2+2 a c-b \left (b-\sqrt {8 a^2+b^2-4 a c}\right )}}\right )}{\sqrt {2} a \sqrt {8 a^2+b^2-4 a c} \sqrt {4 a^2+2 a c-b \left (b-\sqrt {8 a^2+b^2-4 a c}\right )}}-\frac {\left (4 a^2 B+b \left (b+\sqrt {8 a^2+b^2-4 a c}\right ) D-a \left (A \left (b+\sqrt {8 a^2+b^2-4 a c}\right )+b C+\sqrt {8 a^2+b^2-4 a c} C+2 c D\right )\right ) \tan ^{-1}\left (\frac {b+\sqrt {8 a^2+b^2-4 a c}+4 a x}{\sqrt {2} \sqrt {4 a^2+2 a c-b \left (b+\sqrt {8 a^2+b^2-4 a c}\right )}}\right )}{\sqrt {2} a \sqrt {8 a^2+b^2-4 a c} \sqrt {4 a^2+2 a c-b \left (b+\sqrt {8 a^2+b^2-4 a c}\right )}}-\frac {\left (2 a (A-C)+\left (b-\sqrt {8 a^2+b^2-4 a c}\right ) D\right ) \log \left (2 a+\left (b-\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2\right )}{4 a \sqrt {8 a^2+b^2-4 a c}}+\frac {\left (2 a (A-C)+\left (b+\sqrt {8 a^2+b^2-4 a c}\right ) D\right ) \log \left (2 a+\left (b+\sqrt {8 a^2+b^2-4 a c}\right ) x+2 a x^2\right )}{4 a \sqrt {8 a^2+b^2-4 a c}} \\ \end{align*}
Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.
Time = 0.04 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.16 \[ \int \frac {A+B x+C x^2+D x^3}{a+b x+c x^2+b x^3+a x^4} \, dx=\text {RootSum}\left [a+b \text {$\#$1}+c \text {$\#$1}^2+b \text {$\#$1}^3+a \text {$\#$1}^4\&,\frac {A \log (x-\text {$\#$1})+B \log (x-\text {$\#$1}) \text {$\#$1}+C \log (x-\text {$\#$1}) \text {$\#$1}^2+D \log (x-\text {$\#$1}) \text {$\#$1}^3}{b+2 c \text {$\#$1}+3 b \text {$\#$1}^2+4 a \text {$\#$1}^3}\&\right ] \]
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Time = 0.16 (sec) , antiderivative size = 535, normalized size of antiderivative = 0.88
method | result | size |
default | \(4 a \left (\frac {-\frac {\left (2 A a -2 C a -\sqrt {8 a^{2}-4 a c +b^{2}}\, D+D b \right ) \ln \left (-2 a \,x^{2}+\sqrt {8 a^{2}-4 a c +b^{2}}\, x -b x -2 a \right )}{4 a}+\frac {2 \left (\frac {\left (2 A a -2 C a -\sqrt {8 a^{2}-4 a c +b^{2}}\, D+D b \right ) \left (\sqrt {8 a^{2}-4 a c +b^{2}}-b \right )}{4 a}-\sqrt {8 a^{2}-4 a c +b^{2}}\, A +A b -2 B a +2 D a \right ) \arctan \left (\frac {-4 a x +\sqrt {8 a^{2}-4 a c +b^{2}}-b}{\sqrt {8 a^{2}+4 a c -2 b^{2}+2 \sqrt {8 a^{2}-4 a c +b^{2}}\, b}}\right )}{\sqrt {8 a^{2}+4 a c -2 b^{2}+2 \sqrt {8 a^{2}-4 a c +b^{2}}\, b}}}{4 a \sqrt {8 a^{2}-4 a c +b^{2}}}+\frac {\frac {\left (2 A a -2 C a +\sqrt {8 a^{2}-4 a c +b^{2}}\, D+D b \right ) \ln \left (2 a \,x^{2}+\sqrt {8 a^{2}-4 a c +b^{2}}\, x +b x +2 a \right )}{4 a}+\frac {2 \left (-\frac {\left (2 A a -2 C a +\sqrt {8 a^{2}-4 a c +b^{2}}\, D+D b \right ) \left (b +\sqrt {8 a^{2}-4 a c +b^{2}}\right )}{4 a}+\sqrt {8 a^{2}-4 a c +b^{2}}\, A +A b -2 B a +2 D a \right ) \arctan \left (\frac {b +4 a x +\sqrt {8 a^{2}-4 a c +b^{2}}}{\sqrt {8 a^{2}+4 a c -2 b^{2}-2 \sqrt {8 a^{2}-4 a c +b^{2}}\, b}}\right )}{\sqrt {8 a^{2}+4 a c -2 b^{2}-2 \sqrt {8 a^{2}-4 a c +b^{2}}\, b}}}{4 a \sqrt {8 a^{2}-4 a c +b^{2}}}\right )\) | \(535\) |
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Timed out. \[ \int \frac {A+B x+C x^2+D x^3}{a+b x+c x^2+b x^3+a x^4} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {A+B x+C x^2+D x^3}{a+b x+c x^2+b x^3+a x^4} \, dx=\text {Timed out} \]
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\[ \int \frac {A+B x+C x^2+D x^3}{a+b x+c x^2+b x^3+a x^4} \, dx=\int { \frac {D x^{3} + C x^{2} + B x + A}{a x^{4} + b x^{3} + c x^{2} + b x + a} \,d x } \]
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Exception generated. \[ \int \frac {A+B x+C x^2+D x^3}{a+b x+c x^2+b x^3+a x^4} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {A+B x+C x^2+D x^3}{a+b x+c x^2+b x^3+a x^4} \, dx=\int \frac {A+B\,x+C\,x^2+x^3\,D}{a\,x^4+b\,x^3+c\,x^2+b\,x+a} \,d x \]
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