Integrand size = 17, antiderivative size = 360 \[ \int \frac {(d+e x)^2}{\left (a+c x^4\right )^3} \, dx=\frac {x (d+e x)^2}{8 a \left (a+c x^4\right )^2}+\frac {x \left (7 d^2+12 d e x+5 e^2 x^2\right )}{32 a^2 \left (a+c x^4\right )}+\frac {3 d e \arctan \left (\frac {\sqrt {c} x^2}{\sqrt {a}}\right )}{8 a^{5/2} \sqrt {c}}-\frac {\left (21 \sqrt {c} d^2+5 \sqrt {a} e^2\right ) \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} c^{3/4}}+\frac {\left (21 \sqrt {c} d^2+5 \sqrt {a} e^2\right ) \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} c^{3/4}}-\frac {\left (21 \sqrt {c} d^2-5 \sqrt {a} e^2\right ) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} a^{11/4} c^{3/4}}+\frac {\left (21 \sqrt {c} d^2-5 \sqrt {a} e^2\right ) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} a^{11/4} c^{3/4}} \]
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Time = 0.22 (sec) , antiderivative size = 360, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.588, Rules used = {1869, 1890, 281, 211, 1182, 1176, 631, 210, 1179, 642} \[ \int \frac {(d+e x)^2}{\left (a+c x^4\right )^3} \, dx=-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right ) \left (5 \sqrt {a} e^2+21 \sqrt {c} d^2\right )}{64 \sqrt {2} a^{11/4} c^{3/4}}+\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}+1\right ) \left (5 \sqrt {a} e^2+21 \sqrt {c} d^2\right )}{64 \sqrt {2} a^{11/4} c^{3/4}}+\frac {3 d e \arctan \left (\frac {\sqrt {c} x^2}{\sqrt {a}}\right )}{8 a^{5/2} \sqrt {c}}-\frac {\left (21 \sqrt {c} d^2-5 \sqrt {a} e^2\right ) \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {a}+\sqrt {c} x^2\right )}{128 \sqrt {2} a^{11/4} c^{3/4}}+\frac {\left (21 \sqrt {c} d^2-5 \sqrt {a} e^2\right ) \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {a}+\sqrt {c} x^2\right )}{128 \sqrt {2} a^{11/4} c^{3/4}}+\frac {x \left (7 d^2+12 d e x+5 e^2 x^2\right )}{32 a^2 \left (a+c x^4\right )}+\frac {x (d+e x)^2}{8 a \left (a+c x^4\right )^2} \]
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Rule 210
Rule 211
Rule 281
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 1182
Rule 1869
Rule 1890
Rubi steps \begin{align*} \text {integral}& = \frac {x (d+e x)^2}{8 a \left (a+c x^4\right )^2}-\frac {\int \frac {-7 d^2-12 d e x-5 e^2 x^2}{\left (a+c x^4\right )^2} \, dx}{8 a} \\ & = \frac {x (d+e x)^2}{8 a \left (a+c x^4\right )^2}+\frac {x \left (7 d^2+12 d e x+5 e^2 x^2\right )}{32 a^2 \left (a+c x^4\right )}+\frac {\int \frac {21 d^2+24 d e x+5 e^2 x^2}{a+c x^4} \, dx}{32 a^2} \\ & = \frac {x (d+e x)^2}{8 a \left (a+c x^4\right )^2}+\frac {x \left (7 d^2+12 d e x+5 e^2 x^2\right )}{32 a^2 \left (a+c x^4\right )}+\frac {\int \left (\frac {24 d e x}{a+c x^4}+\frac {21 d^2+5 e^2 x^2}{a+c x^4}\right ) \, dx}{32 a^2} \\ & = \frac {x (d+e x)^2}{8 a \left (a+c x^4\right )^2}+\frac {x \left (7 d^2+12 d e x+5 e^2 x^2\right )}{32 a^2 \left (a+c x^4\right )}+\frac {\int \frac {21 d^2+5 e^2 x^2}{a+c x^4} \, dx}{32 a^2}+\frac {(3 d e) \int \frac {x}{a+c x^4} \, dx}{4 a^2} \\ & = \frac {x (d+e x)^2}{8 a \left (a+c x^4\right )^2}+\frac {x \left (7 d^2+12 d e x+5 e^2 x^2\right )}{32 a^2 \left (a+c x^4\right )}+\frac {(3 d e) \text {Subst}\left (\int \frac {1}{a+c x^2} \, dx,x,x^2\right )}{8 a^2}+\frac {\left (\frac {21 \sqrt {c} d^2}{\sqrt {a}}-5 e^2\right ) \int \frac {\sqrt {a} \sqrt {c}-c x^2}{a+c x^4} \, dx}{64 a^2 c}+\frac {\left (\frac {21 \sqrt {c} d^2}{\sqrt {a}}+5 e^2\right ) \int \frac {\sqrt {a} \sqrt {c}+c x^2}{a+c x^4} \, dx}{64 a^2 c} \\ & = \frac {x (d+e x)^2}{8 a \left (a+c x^4\right )^2}+\frac {x \left (7 d^2+12 d e x+5 e^2 x^2\right )}{32 a^2 \left (a+c x^4\right )}+\frac {3 d e \tan ^{-1}\left (\frac {\sqrt {c} x^2}{\sqrt {a}}\right )}{8 a^{5/2} \sqrt {c}}-\frac {\left (\frac {21 \sqrt {c} d^2}{\sqrt {a}}-5 e^2\right ) \int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{c}}+2 x}{-\frac {\sqrt {a}}{\sqrt {c}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}-x^2} \, dx}{128 \sqrt {2} a^{9/4} c^{3/4}}-\frac {\left (\frac {21 \sqrt {c} d^2}{\sqrt {a}}-5 e^2\right ) \int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{c}}-2 x}{-\frac {\sqrt {a}}{\sqrt {c}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}-x^2} \, dx}{128 \sqrt {2} a^{9/4} c^{3/4}}+\frac {\left (\frac {21 \sqrt {c} d^2}{\sqrt {a}}+5 e^2\right ) \int \frac {1}{\frac {\sqrt {a}}{\sqrt {c}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}+x^2} \, dx}{128 a^2 c}+\frac {\left (\frac {21 \sqrt {c} d^2}{\sqrt {a}}+5 e^2\right ) \int \frac {1}{\frac {\sqrt {a}}{\sqrt {c}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}+x^2} \, dx}{128 a^2 c} \\ & = \frac {x (d+e x)^2}{8 a \left (a+c x^4\right )^2}+\frac {x \left (7 d^2+12 d e x+5 e^2 x^2\right )}{32 a^2 \left (a+c x^4\right )}+\frac {3 d e \tan ^{-1}\left (\frac {\sqrt {c} x^2}{\sqrt {a}}\right )}{8 a^{5/2} \sqrt {c}}-\frac {\left (\frac {21 \sqrt {c} d^2}{\sqrt {a}}-5 e^2\right ) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} a^{9/4} c^{3/4}}+\frac {\left (\frac {21 \sqrt {c} d^2}{\sqrt {a}}-5 e^2\right ) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} a^{9/4} c^{3/4}}+\frac {\left (21 \sqrt {c} d^2+5 \sqrt {a} e^2\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} c^{3/4}}-\frac {\left (21 \sqrt {c} d^2+5 \sqrt {a} e^2\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} c^{3/4}} \\ & = \frac {x (d+e x)^2}{8 a \left (a+c x^4\right )^2}+\frac {x \left (7 d^2+12 d e x+5 e^2 x^2\right )}{32 a^2 \left (a+c x^4\right )}+\frac {3 d e \tan ^{-1}\left (\frac {\sqrt {c} x^2}{\sqrt {a}}\right )}{8 a^{5/2} \sqrt {c}}-\frac {\left (21 \sqrt {c} d^2+5 \sqrt {a} e^2\right ) \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} c^{3/4}}+\frac {\left (21 \sqrt {c} d^2+5 \sqrt {a} e^2\right ) \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} c^{3/4}}-\frac {\left (\frac {21 \sqrt {c} d^2}{\sqrt {a}}-5 e^2\right ) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} a^{9/4} c^{3/4}}+\frac {\left (\frac {21 \sqrt {c} d^2}{\sqrt {a}}-5 e^2\right ) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} a^{9/4} c^{3/4}} \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 358, normalized size of antiderivative = 0.99 \[ \int \frac {(d+e x)^2}{\left (a+c x^4\right )^3} \, dx=\frac {\frac {32 a^2 x (d+e x)^2}{\left (a+c x^4\right )^2}+\frac {8 a x \left (7 d^2+12 d e x+5 e^2 x^2\right )}{a+c x^4}-\frac {2 \sqrt [4]{a} \left (21 \sqrt {2} \sqrt {c} d^2+48 \sqrt [4]{a} \sqrt [4]{c} d e+5 \sqrt {2} \sqrt {a} e^2\right ) \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{c^{3/4}}+\frac {2 \sqrt [4]{a} \left (21 \sqrt {2} \sqrt {c} d^2-48 \sqrt [4]{a} \sqrt [4]{c} d e+5 \sqrt {2} \sqrt {a} e^2\right ) \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{c^{3/4}}+\frac {\sqrt {2} \left (-21 \sqrt [4]{a} \sqrt {c} d^2+5 a^{3/4} e^2\right ) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{c^{3/4}}+\frac {\sqrt {2} \left (21 \sqrt [4]{a} \sqrt {c} d^2-5 a^{3/4} e^2\right ) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{c^{3/4}}}{256 a^3} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.84 (sec) , antiderivative size = 126, normalized size of antiderivative = 0.35
method | result | size |
risch | \(\frac {\frac {5 c \,e^{2} x^{7}}{32 a^{2}}+\frac {3 d c e \,x^{6}}{8 a^{2}}+\frac {7 c \,d^{2} x^{5}}{32 a^{2}}+\frac {9 e^{2} x^{3}}{32 a}+\frac {5 e d \,x^{2}}{8 a}+\frac {11 d^{2} x}{32 a}}{\left (c \,x^{4}+a \right )^{2}}+\frac {\munderset {\textit {\_R} =\operatorname {RootOf}\left (c \,\textit {\_Z}^{4}+a \right )}{\sum }\frac {\left (5 e^{2} \textit {\_R}^{2}+24 e d \textit {\_R} +21 d^{2}\right ) \ln \left (x -\textit {\_R} \right )}{\textit {\_R}^{3}}}{128 a^{2} c}\) | \(126\) |
default | \(d^{2} \left (\frac {x}{8 a \left (c \,x^{4}+a \right )^{2}}+\frac {\frac {7 x}{32 a \left (c \,x^{4}+a \right )}+\frac {21 \left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {x^{2}+\left (\frac {a}{c}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {a}{c}}}{x^{2}-\left (\frac {a}{c}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {a}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{256 a^{2}}}{a}\right )+2 e d \left (\frac {x^{2}}{8 a \left (c \,x^{4}+a \right )^{2}}+\frac {\frac {3 x^{2}}{16 a \left (c \,x^{4}+a \right )}+\frac {3 \arctan \left (x^{2} \sqrt {\frac {c}{a}}\right )}{16 a \sqrt {a c}}}{a}\right )+e^{2} \left (\frac {x^{3}}{8 a \left (c \,x^{4}+a \right )^{2}}+\frac {\frac {5 x^{3}}{32 a \left (c \,x^{4}+a \right )}+\frac {5 \sqrt {2}\, \left (\ln \left (\frac {x^{2}-\left (\frac {a}{c}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {a}{c}}}{x^{2}+\left (\frac {a}{c}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {a}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{256 a c \left (\frac {a}{c}\right )^{\frac {1}{4}}}}{a}\right )\) | \(360\) |
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Result contains complex when optimal does not.
Time = 7.15 (sec) , antiderivative size = 91420, normalized size of antiderivative = 253.94 \[ \int \frac {(d+e x)^2}{\left (a+c x^4\right )^3} \, dx=\text {Too large to display} \]
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Time = 14.65 (sec) , antiderivative size = 374, normalized size of antiderivative = 1.04 \[ \int \frac {(d+e x)^2}{\left (a+c x^4\right )^3} \, dx=\operatorname {RootSum} {\left (268435456 t^{4} a^{11} c^{3} + 25755648 t^{2} a^{6} c^{2} d^{2} e^{2} + t \left (307200 a^{4} c d e^{5} - 5419008 a^{3} c^{2} d^{5} e\right ) + 625 a^{2} e^{8} + 111906 a c d^{4} e^{4} + 194481 c^{2} d^{8}, \left ( t \mapsto t \log {\left (x + \frac {262144000 t^{3} a^{10} c^{2} e^{6} + 46110081024 t^{3} a^{9} c^{3} d^{4} e^{2} - 1645608960 t^{2} a^{7} c^{2} d^{3} e^{5} + 3641573376 t^{2} a^{6} c^{3} d^{7} e + 32688000 t a^{5} c d^{2} e^{8} + 3128219136 t a^{4} c^{2} d^{6} e^{4} + 522764928 t a^{3} c^{3} d^{10} + 225000 a^{3} d e^{11} - 43338240 a^{2} c d^{5} e^{7} - 523431720 a c^{2} d^{9} e^{3}}{15625 a^{3} e^{12} - 21357225 a^{2} c d^{4} e^{8} - 376741449 a c^{2} d^{8} e^{4} + 85766121 c^{3} d^{12}} \right )} \right )\right )} + \frac {11 a d^{2} x + 20 a d e x^{2} + 9 a e^{2} x^{3} + 7 c d^{2} x^{5} + 12 c d e x^{6} + 5 c e^{2} x^{7}}{32 a^{4} + 64 a^{3} c x^{4} + 32 a^{2} c^{2} x^{8}} \]
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Time = 0.28 (sec) , antiderivative size = 364, normalized size of antiderivative = 1.01 \[ \int \frac {(d+e x)^2}{\left (a+c x^4\right )^3} \, dx=\frac {5 \, c e^{2} x^{7} + 12 \, c d e x^{6} + 7 \, c d^{2} x^{5} + 9 \, a e^{2} x^{3} + 20 \, a d e x^{2} + 11 \, a d^{2} x}{32 \, {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )}} + \frac {\frac {\sqrt {2} {\left (21 \, \sqrt {c} d^{2} - 5 \, \sqrt {a} e^{2}\right )} \log \left (\sqrt {c} x^{2} + \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}} x + \sqrt {a}\right )}{a^{\frac {3}{4}} c^{\frac {3}{4}}} - \frac {\sqrt {2} {\left (21 \, \sqrt {c} d^{2} - 5 \, \sqrt {a} e^{2}\right )} \log \left (\sqrt {c} x^{2} - \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}} x + \sqrt {a}\right )}{a^{\frac {3}{4}} c^{\frac {3}{4}}} + \frac {2 \, {\left (21 \, \sqrt {2} a^{\frac {1}{4}} c^{\frac {3}{4}} d^{2} + 5 \, \sqrt {2} a^{\frac {3}{4}} c^{\frac {1}{4}} e^{2} - 48 \, \sqrt {a} \sqrt {c} d e\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, \sqrt {c} x + \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {c}}}\right )}{a^{\frac {3}{4}} \sqrt {\sqrt {a} \sqrt {c}} c^{\frac {3}{4}}} + \frac {2 \, {\left (21 \, \sqrt {2} a^{\frac {1}{4}} c^{\frac {3}{4}} d^{2} + 5 \, \sqrt {2} a^{\frac {3}{4}} c^{\frac {1}{4}} e^{2} + 48 \, \sqrt {a} \sqrt {c} d e\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, \sqrt {c} x - \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {c}}}\right )}{a^{\frac {3}{4}} \sqrt {\sqrt {a} \sqrt {c}} c^{\frac {3}{4}}}}{256 \, a^{2}} \]
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Time = 0.28 (sec) , antiderivative size = 358, normalized size of antiderivative = 0.99 \[ \int \frac {(d+e x)^2}{\left (a+c x^4\right )^3} \, dx=\frac {5 \, c e^{2} x^{7} + 12 \, c d e x^{6} + 7 \, c d^{2} x^{5} + 9 \, a e^{2} x^{3} + 20 \, a d e x^{2} + 11 \, a d^{2} x}{32 \, {\left (c x^{4} + a\right )}^{2} a^{2}} + \frac {\sqrt {2} {\left (24 \, \sqrt {2} \sqrt {a c} c^{2} d e + 21 \, \left (a c^{3}\right )^{\frac {1}{4}} c^{2} d^{2} + 5 \, \left (a c^{3}\right )^{\frac {3}{4}} e^{2}\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, x + \sqrt {2} \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}}{2 \, \left (\frac {a}{c}\right )^{\frac {1}{4}}}\right )}{128 \, a^{3} c^{3}} + \frac {\sqrt {2} {\left (24 \, \sqrt {2} \sqrt {a c} c^{2} d e + 21 \, \left (a c^{3}\right )^{\frac {1}{4}} c^{2} d^{2} + 5 \, \left (a c^{3}\right )^{\frac {3}{4}} e^{2}\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, x - \sqrt {2} \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}}{2 \, \left (\frac {a}{c}\right )^{\frac {1}{4}}}\right )}{128 \, a^{3} c^{3}} + \frac {\sqrt {2} {\left (21 \, \left (a c^{3}\right )^{\frac {1}{4}} c^{2} d^{2} - 5 \, \left (a c^{3}\right )^{\frac {3}{4}} e^{2}\right )} \log \left (x^{2} + \sqrt {2} x \left (\frac {a}{c}\right )^{\frac {1}{4}} + \sqrt {\frac {a}{c}}\right )}{256 \, a^{3} c^{3}} - \frac {\sqrt {2} {\left (21 \, \left (a c^{3}\right )^{\frac {1}{4}} c^{2} d^{2} - 5 \, \left (a c^{3}\right )^{\frac {3}{4}} e^{2}\right )} \log \left (x^{2} - \sqrt {2} x \left (\frac {a}{c}\right )^{\frac {1}{4}} + \sqrt {\frac {a}{c}}\right )}{256 \, a^{3} c^{3}} \]
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Time = 0.27 (sec) , antiderivative size = 676, normalized size of antiderivative = 1.88 \[ \int \frac {(d+e x)^2}{\left (a+c x^4\right )^3} \, dx=\frac {\frac {11\,d^2\,x}{32\,a}+\frac {9\,e^2\,x^3}{32\,a}+\frac {7\,c\,d^2\,x^5}{32\,a^2}+\frac {5\,c\,e^2\,x^7}{32\,a^2}+\frac {5\,d\,e\,x^2}{8\,a}+\frac {3\,c\,d\,e\,x^6}{8\,a^2}}{a^2+2\,a\,c\,x^4+c^2\,x^8}+\left (\sum _{k=1}^4\ln \left (-\frac {c\,\left (125\,a\,e^6-9891\,c\,d^4\,e^2+{\mathrm {root}\left (268435456\,a^{11}\,c^3\,z^4+25755648\,a^6\,c^2\,d^2\,e^2\,z^2-5419008\,a^3\,c^2\,d^5\,e\,z+307200\,a^4\,c\,d\,e^5\,z+111906\,a\,c\,d^4\,e^4+194481\,c^2\,d^8+625\,a^2\,e^8,z,k\right )}^2\,a^5\,c^2\,d^2\,344064-8784\,c\,d^3\,e^3\,x-\mathrm {root}\left (268435456\,a^{11}\,c^3\,z^4+25755648\,a^6\,c^2\,d^2\,e^2\,z^2-5419008\,a^3\,c^2\,d^5\,e\,z+307200\,a^4\,c\,d\,e^5\,z+111906\,a\,c\,d^4\,e^4+194481\,c^2\,d^8+625\,a^2\,e^8,z,k\right )\,a^3\,c\,e^4\,x\,3200+\mathrm {root}\left (268435456\,a^{11}\,c^3\,z^4+25755648\,a^6\,c^2\,d^2\,e^2\,z^2-5419008\,a^3\,c^2\,d^5\,e\,z+307200\,a^4\,c\,d\,e^5\,z+111906\,a\,c\,d^4\,e^4+194481\,c^2\,d^8+625\,a^2\,e^8,z,k\right )\,a^2\,c^2\,d^4\,x\,56448+\mathrm {root}\left (268435456\,a^{11}\,c^3\,z^4+25755648\,a^6\,c^2\,d^2\,e^2\,z^2-5419008\,a^3\,c^2\,d^5\,e\,z+307200\,a^4\,c\,d\,e^5\,z+111906\,a\,c\,d^4\,e^4+194481\,c^2\,d^8+625\,a^2\,e^8,z,k\right )\,a^3\,c\,d\,e^3\,30720-{\mathrm {root}\left (268435456\,a^{11}\,c^3\,z^4+25755648\,a^6\,c^2\,d^2\,e^2\,z^2-5419008\,a^3\,c^2\,d^5\,e\,z+307200\,a^4\,c\,d\,e^5\,z+111906\,a\,c\,d^4\,e^4+194481\,c^2\,d^8+625\,a^2\,e^8,z,k\right )}^2\,a^5\,c^2\,d\,e\,x\,393216\right )}{a^6\,32768}\right )\,\mathrm {root}\left (268435456\,a^{11}\,c^3\,z^4+25755648\,a^6\,c^2\,d^2\,e^2\,z^2-5419008\,a^3\,c^2\,d^5\,e\,z+307200\,a^4\,c\,d\,e^5\,z+111906\,a\,c\,d^4\,e^4+194481\,c^2\,d^8+625\,a^2\,e^8,z,k\right )\right ) \]
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