Integrand size = 16, antiderivative size = 17 \[ \int \frac {24+8 x}{x \left (-4+x^2\right )} \, dx=5 \log (2-x)-6 \log (x)+\log (2+x) \]
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Time = 0.01 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {815} \[ \int \frac {24+8 x}{x \left (-4+x^2\right )} \, dx=5 \log (2-x)-6 \log (x)+\log (x+2) \]
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Rule 815
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {5}{-2+x}-\frac {6}{x}+\frac {1}{2+x}\right ) \, dx \\ & = 5 \log (2-x)-6 \log (x)+\log (2+x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.59 \[ \int \frac {24+8 x}{x \left (-4+x^2\right )} \, dx=8 \left (\frac {5}{8} \log (2-x)-\frac {3 \log (x)}{4}+\frac {1}{8} \log (2+x)\right ) \]
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Time = 0.81 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.94
method | result | size |
default | \(-6 \ln \left (x \right )+\ln \left (x +2\right )+5 \ln \left (x -2\right )\) | \(16\) |
norman | \(-6 \ln \left (x \right )+\ln \left (x +2\right )+5 \ln \left (x -2\right )\) | \(16\) |
risch | \(-6 \ln \left (x \right )+\ln \left (x +2\right )+5 \ln \left (x -2\right )\) | \(16\) |
parallelrisch | \(-6 \ln \left (x \right )+\ln \left (x +2\right )+5 \ln \left (x -2\right )\) | \(16\) |
meijerg | \(3 \ln \left (1-\frac {x^{2}}{4}\right )-6 \ln \left (x \right )+6 \ln \left (2\right )-3 i \pi -4 \,\operatorname {arctanh}\left (\frac {x}{2}\right )\) | \(30\) |
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none
Time = 0.25 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int \frac {24+8 x}{x \left (-4+x^2\right )} \, dx=\log \left (x + 2\right ) + 5 \, \log \left (x - 2\right ) - 6 \, \log \left (x\right ) \]
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Time = 0.06 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int \frac {24+8 x}{x \left (-4+x^2\right )} \, dx=- 6 \log {\left (x \right )} + 5 \log {\left (x - 2 \right )} + \log {\left (x + 2 \right )} \]
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none
Time = 0.19 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int \frac {24+8 x}{x \left (-4+x^2\right )} \, dx=\log \left (x + 2\right ) + 5 \, \log \left (x - 2\right ) - 6 \, \log \left (x\right ) \]
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none
Time = 0.29 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.06 \[ \int \frac {24+8 x}{x \left (-4+x^2\right )} \, dx=\log \left ({\left | x + 2 \right |}\right ) + 5 \, \log \left ({\left | x - 2 \right |}\right ) - 6 \, \log \left ({\left | x \right |}\right ) \]
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Time = 9.18 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int \frac {24+8 x}{x \left (-4+x^2\right )} \, dx=5\,\ln \left (x-2\right )+\ln \left (x+2\right )-6\,\ln \left (x\right ) \]
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