Integrand size = 18, antiderivative size = 21 \[ \int \frac {-3+x}{2 x+3 x^2+x^3} \, dx=-\frac {3 \log (x)}{2}+4 \log (1+x)-\frac {5}{2} \log (2+x) \]
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Time = 0.01 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {1608, 814} \[ \int \frac {-3+x}{2 x+3 x^2+x^3} \, dx=-\frac {3 \log (x)}{2}+4 \log (x+1)-\frac {5}{2} \log (x+2) \]
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Rule 814
Rule 1608
Rubi steps \begin{align*} \text {integral}& = \int \frac {-3+x}{x \left (2+3 x+x^2\right )} \, dx \\ & = \int \left (-\frac {3}{2 x}+\frac {4}{1+x}-\frac {5}{2 (2+x)}\right ) \, dx \\ & = -\frac {3 \log (x)}{2}+4 \log (1+x)-\frac {5}{2} \log (2+x) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00 \[ \int \frac {-3+x}{2 x+3 x^2+x^3} \, dx=-\frac {3 \log (x)}{2}+4 \log (1+x)-\frac {5}{2} \log (2+x) \]
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Time = 0.04 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.86
method | result | size |
default | \(-\frac {3 \ln \left (x \right )}{2}+4 \ln \left (x +1\right )-\frac {5 \ln \left (x +2\right )}{2}\) | \(18\) |
norman | \(-\frac {3 \ln \left (x \right )}{2}+4 \ln \left (x +1\right )-\frac {5 \ln \left (x +2\right )}{2}\) | \(18\) |
risch | \(-\frac {3 \ln \left (x \right )}{2}+4 \ln \left (x +1\right )-\frac {5 \ln \left (x +2\right )}{2}\) | \(18\) |
parallelrisch | \(-\frac {3 \ln \left (x \right )}{2}+4 \ln \left (x +1\right )-\frac {5 \ln \left (x +2\right )}{2}\) | \(18\) |
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none
Time = 0.24 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81 \[ \int \frac {-3+x}{2 x+3 x^2+x^3} \, dx=-\frac {5}{2} \, \log \left (x + 2\right ) + 4 \, \log \left (x + 1\right ) - \frac {3}{2} \, \log \left (x\right ) \]
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Time = 0.06 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.95 \[ \int \frac {-3+x}{2 x+3 x^2+x^3} \, dx=- \frac {3 \log {\left (x \right )}}{2} + 4 \log {\left (x + 1 \right )} - \frac {5 \log {\left (x + 2 \right )}}{2} \]
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none
Time = 0.18 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81 \[ \int \frac {-3+x}{2 x+3 x^2+x^3} \, dx=-\frac {5}{2} \, \log \left (x + 2\right ) + 4 \, \log \left (x + 1\right ) - \frac {3}{2} \, \log \left (x\right ) \]
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none
Time = 0.27 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.95 \[ \int \frac {-3+x}{2 x+3 x^2+x^3} \, dx=-\frac {5}{2} \, \log \left ({\left | x + 2 \right |}\right ) + 4 \, \log \left ({\left | x + 1 \right |}\right ) - \frac {3}{2} \, \log \left ({\left | x \right |}\right ) \]
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Time = 9.55 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81 \[ \int \frac {-3+x}{2 x+3 x^2+x^3} \, dx=4\,\ln \left (x+1\right )-\frac {5\,\ln \left (x+2\right )}{2}-\frac {3\,\ln \left (x\right )}{2} \]
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