Integrand size = 30, antiderivative size = 37 \[ \int \left (8 a e^2-d^3 x+8 d e^2 x^3+8 e^3 x^4\right ) \, dx=8 a e^2 x-\frac {d^3 x^2}{2}+2 d e^2 x^4+\frac {8 e^3 x^5}{5} \]
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Time = 0.01 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \left (8 a e^2-d^3 x+8 d e^2 x^3+8 e^3 x^4\right ) \, dx=8 a e^2 x-\frac {d^3 x^2}{2}+2 d e^2 x^4+\frac {8 e^3 x^5}{5} \]
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Rubi steps \begin{align*} \text {integral}& = 8 a e^2 x-\frac {d^3 x^2}{2}+2 d e^2 x^4+\frac {8 e^3 x^5}{5} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00 \[ \int \left (8 a e^2-d^3 x+8 d e^2 x^3+8 e^3 x^4\right ) \, dx=8 a e^2 x-\frac {d^3 x^2}{2}+2 d e^2 x^4+\frac {8 e^3 x^5}{5} \]
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Time = 0.03 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.92
method | result | size |
gosper | \(8 a \,e^{2} x -\frac {1}{2} d^{3} x^{2}+2 d \,e^{2} x^{4}+\frac {8}{5} e^{3} x^{5}\) | \(34\) |
default | \(8 a \,e^{2} x -\frac {1}{2} d^{3} x^{2}+2 d \,e^{2} x^{4}+\frac {8}{5} e^{3} x^{5}\) | \(34\) |
norman | \(8 a \,e^{2} x -\frac {1}{2} d^{3} x^{2}+2 d \,e^{2} x^{4}+\frac {8}{5} e^{3} x^{5}\) | \(34\) |
risch | \(8 a \,e^{2} x -\frac {1}{2} d^{3} x^{2}+2 d \,e^{2} x^{4}+\frac {8}{5} e^{3} x^{5}\) | \(34\) |
parallelrisch | \(8 a \,e^{2} x -\frac {1}{2} d^{3} x^{2}+2 d \,e^{2} x^{4}+\frac {8}{5} e^{3} x^{5}\) | \(34\) |
parts | \(8 a \,e^{2} x -\frac {1}{2} d^{3} x^{2}+2 d \,e^{2} x^{4}+\frac {8}{5} e^{3} x^{5}\) | \(34\) |
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Time = 0.26 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.89 \[ \int \left (8 a e^2-d^3 x+8 d e^2 x^3+8 e^3 x^4\right ) \, dx=\frac {8}{5} \, e^{3} x^{5} + 2 \, d e^{2} x^{4} - \frac {1}{2} \, d^{3} x^{2} + 8 \, a e^{2} x \]
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Time = 0.02 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.97 \[ \int \left (8 a e^2-d^3 x+8 d e^2 x^3+8 e^3 x^4\right ) \, dx=8 a e^{2} x - \frac {d^{3} x^{2}}{2} + 2 d e^{2} x^{4} + \frac {8 e^{3} x^{5}}{5} \]
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Time = 0.19 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.89 \[ \int \left (8 a e^2-d^3 x+8 d e^2 x^3+8 e^3 x^4\right ) \, dx=\frac {8}{5} \, e^{3} x^{5} + 2 \, d e^{2} x^{4} - \frac {1}{2} \, d^{3} x^{2} + 8 \, a e^{2} x \]
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Time = 0.28 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.89 \[ \int \left (8 a e^2-d^3 x+8 d e^2 x^3+8 e^3 x^4\right ) \, dx=\frac {8}{5} \, e^{3} x^{5} + 2 \, d e^{2} x^{4} - \frac {1}{2} \, d^{3} x^{2} + 8 \, a e^{2} x \]
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Time = 0.02 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.89 \[ \int \left (8 a e^2-d^3 x+8 d e^2 x^3+8 e^3 x^4\right ) \, dx=-\frac {d^3\,x^2}{2}+2\,d\,e^2\,x^4+\frac {8\,e^3\,x^5}{5}+8\,a\,e^2\,x \]
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