Integrand size = 26, antiderivative size = 73 \[ \int \frac {\sqrt {x^2-x \sqrt {-x+x^2}}}{x^3} \, dx=\frac {4 (-3+x) \sqrt {-x \left (-x+\sqrt {-x+x^2}\right )}}{15 x^2}-\frac {4 \sqrt {-x+x^2} \sqrt {-x \left (-x+\sqrt {-x+x^2}\right )}}{15 x^2} \]
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\[ \int \frac {\sqrt {x^2-x \sqrt {-x+x^2}}}{x^3} \, dx=\int \frac {\sqrt {x^2-x \sqrt {-x+x^2}}}{x^3} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\sqrt {x^2-x \sqrt {-x+x^2}}}{x^3} \, dx \\ \end{align*}
Time = 1.21 (sec) , antiderivative size = 91, normalized size of antiderivative = 1.25 \[ \int \frac {\sqrt {x^2-x \sqrt {-x+x^2}}}{x^3} \, dx=-\frac {4 \sqrt {x \left (x-\sqrt {(-1+x) x}\right )} \sqrt {x+\sqrt {(-1+x) x}} \left (-2 x^2-3 \sqrt {(-1+x) x}+2 x \left (2+\sqrt {(-1+x) x}\right )\right )}{15 x^{5/2} \sqrt {x-\sqrt {(-1+x) x}}} \]
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\[\int \frac {\sqrt {x^{2}-x \sqrt {x^{2}-x}}}{x^{3}}d x\]
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Time = 0.25 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.51 \[ \int \frac {\sqrt {x^2-x \sqrt {-x+x^2}}}{x^3} \, dx=\frac {4 \, \sqrt {x^{2} - \sqrt {x^{2} - x} x} {\left (x - \sqrt {x^{2} - x} - 3\right )}}{15 \, x^{2}} \]
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\[ \int \frac {\sqrt {x^2-x \sqrt {-x+x^2}}}{x^3} \, dx=\int \frac {\sqrt {x \left (x - \sqrt {x^{2} - x}\right )}}{x^{3}}\, dx \]
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\[ \int \frac {\sqrt {x^2-x \sqrt {-x+x^2}}}{x^3} \, dx=\int { \frac {\sqrt {x^{2} - \sqrt {x^{2} - x} x}}{x^{3}} \,d x } \]
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\[ \int \frac {\sqrt {x^2-x \sqrt {-x+x^2}}}{x^3} \, dx=\int { \frac {\sqrt {x^{2} - \sqrt {x^{2} - x} x}}{x^{3}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {x^2-x \sqrt {-x+x^2}}}{x^3} \, dx=\int \frac {\sqrt {x^2-x\,\sqrt {x^2-x}}}{x^3} \,d x \]
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