Integrand size = 25, antiderivative size = 79 \[ \int \frac {\sqrt {1+x^2}}{\sqrt {1+\sqrt {1+x^2}}} \, dx=-\frac {2 x}{3 \sqrt {1+\sqrt {1+x^2}}}+\frac {2 x \sqrt {1+x^2}}{3 \sqrt {1+\sqrt {1+x^2}}}+\sqrt {2} \arctan \left (\frac {x}{\sqrt {2} \sqrt {1+\sqrt {1+x^2}}}\right ) \]
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\[ \int \frac {\sqrt {1+x^2}}{\sqrt {1+\sqrt {1+x^2}}} \, dx=\int \frac {\sqrt {1+x^2}}{\sqrt {1+\sqrt {1+x^2}}} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\sqrt {1+x^2}}{\sqrt {1+\sqrt {1+x^2}}} \, dx \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.77 \[ \int \frac {\sqrt {1+x^2}}{\sqrt {1+\sqrt {1+x^2}}} \, dx=\frac {2 x \left (-1+\sqrt {1+x^2}\right )}{3 \sqrt {1+\sqrt {1+x^2}}}+\sqrt {2} \arctan \left (\frac {x}{\sqrt {2} \sqrt {1+\sqrt {1+x^2}}}\right ) \]
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\[\int \frac {\sqrt {x^{2}+1}}{\sqrt {1+\sqrt {x^{2}+1}}}d x\]
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none
Time = 0.68 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.73 \[ \int \frac {\sqrt {1+x^2}}{\sqrt {1+\sqrt {1+x^2}}} \, dx=-\frac {3 \, \sqrt {2} x \arctan \left (\frac {\sqrt {2} \sqrt {\sqrt {x^{2} + 1} + 1}}{x}\right ) - 2 \, {\left (x^{2} - 2 \, \sqrt {x^{2} + 1} + 2\right )} \sqrt {\sqrt {x^{2} + 1} + 1}}{3 \, x} \]
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\[ \int \frac {\sqrt {1+x^2}}{\sqrt {1+\sqrt {1+x^2}}} \, dx=\int \frac {\sqrt {x^{2} + 1}}{\sqrt {\sqrt {x^{2} + 1} + 1}}\, dx \]
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\[ \int \frac {\sqrt {1+x^2}}{\sqrt {1+\sqrt {1+x^2}}} \, dx=\int { \frac {\sqrt {x^{2} + 1}}{\sqrt {\sqrt {x^{2} + 1} + 1}} \,d x } \]
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\[ \int \frac {\sqrt {1+x^2}}{\sqrt {1+\sqrt {1+x^2}}} \, dx=\int { \frac {\sqrt {x^{2} + 1}}{\sqrt {\sqrt {x^{2} + 1} + 1}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {1+x^2}}{\sqrt {1+\sqrt {1+x^2}}} \, dx=\int \frac {\sqrt {x^2+1}}{\sqrt {\sqrt {x^2+1}+1}} \,d x \]
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