Integrand size = 77, antiderivative size = 90 \[ \int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\sqrt [4]{\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right )} \, dx=-\frac {\arctan \left (\frac {\sqrt [4]{d} \sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}}{1+k x}\right )}{d^{3/4}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{d} \sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}}{1+k x}\right )}{d^{3/4}} \]
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\[ \int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\sqrt [4]{\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right )} \, dx=\int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\sqrt [4]{\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right ) \sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}} \, dx \\ & = \int \frac {-2 k-(1-k) (1+k) x+2 k x^2}{\left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2-k \left (d-k^2\right ) x^3\right ) \sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}} \, dx \\ & = \int \left (\frac {(-1-k) (1-k) x}{\left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2-k \left (d-k^2\right ) x^3\right ) \sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}}+\frac {2 k x^2}{\left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2-k \left (d-k^2\right ) x^3\right ) \sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}}+\frac {2 k}{\left (-1+d-(3+d) k x-\left (d+3 k^2\right ) x^2+k \left (d-k^2\right ) x^3\right ) \sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}}\right ) \, dx \\ & = ((-1-k) (1-k)) \int \frac {x}{\left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2-k \left (d-k^2\right ) x^3\right ) \sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}} \, dx+(2 k) \int \frac {x^2}{\left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2-k \left (d-k^2\right ) x^3\right ) \sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}} \, dx+(2 k) \int \frac {1}{\left (-1+d-(3+d) k x-\left (d+3 k^2\right ) x^2+k \left (d-k^2\right ) x^3\right ) \sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}} \, dx \\ \end{align*}
\[ \int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\sqrt [4]{\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right )} \, dx=\int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\sqrt [4]{\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right )} \, dx \]
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\[\int \frac {-2 k +\left (-1+k \right ) \left (1+k \right ) x +2 k \,x^{2}}{{\left (\left (-x^{2}+1\right ) \left (-k^{2} x^{2}+1\right )\right )}^{\frac {1}{4}} \left (1-d +\left (3+d \right ) k x +\left (3 k^{2}+d \right ) x^{2}+k \left (k^{2}-d \right ) x^{3}\right )}d x\]
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Timed out. \[ \int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\sqrt [4]{\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right )} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\sqrt [4]{\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\sqrt [4]{\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right )} \, dx=\int { \frac {{\left (k + 1\right )} {\left (k - 1\right )} x + 2 \, k x^{2} - 2 \, k}{{\left ({\left (k^{2} - d\right )} k x^{3} + {\left (d + 3\right )} k x + {\left (3 \, k^{2} + d\right )} x^{2} - d + 1\right )} \left ({\left (k^{2} x^{2} - 1\right )} {\left (x^{2} - 1\right )}\right )^{\frac {1}{4}}} \,d x } \]
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\[ \int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\sqrt [4]{\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right )} \, dx=\int { \frac {{\left (k + 1\right )} {\left (k - 1\right )} x + 2 \, k x^{2} - 2 \, k}{{\left ({\left (k^{2} - d\right )} k x^{3} + {\left (d + 3\right )} k x + {\left (3 \, k^{2} + d\right )} x^{2} - d + 1\right )} \left ({\left (k^{2} x^{2} - 1\right )} {\left (x^{2} - 1\right )}\right )^{\frac {1}{4}}} \,d x } \]
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Timed out. \[ \int \frac {-2 k+(-1+k) (1+k) x+2 k x^2}{\sqrt [4]{\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1-d+(3+d) k x+\left (d+3 k^2\right ) x^2+k \left (-d+k^2\right ) x^3\right )} \, dx=\int \frac {2\,k\,x^2+\left (k-1\right )\,\left (k+1\right )\,x-2\,k}{{\left (\left (x^2-1\right )\,\left (k^2\,x^2-1\right )\right )}^{1/4}\,\left (-k\,\left (d-k^2\right )\,x^3+\left (3\,k^2+d\right )\,x^2+k\,\left (d+3\right )\,x-d+1\right )} \,d x \]
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