Integrand size = 48, antiderivative size = 92 \[ \int \frac {\left (-1+x^4+2 x^6\right ) \sqrt [3]{x+x^5+x^7}}{\left (1+x^4+x^6\right ) \left (1-x^2+x^4+x^6\right )} \, dx=\frac {1}{2} \sqrt {3} \arctan \left (\frac {\sqrt {3} x}{x+2 \sqrt [3]{x+x^5+x^7}}\right )+\frac {1}{2} \log \left (-x+\sqrt [3]{x+x^5+x^7}\right )-\frac {1}{4} \log \left (x^2+x \sqrt [3]{x+x^5+x^7}+\left (x+x^5+x^7\right )^{2/3}\right ) \]
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\[ \int \frac {\left (-1+x^4+2 x^6\right ) \sqrt [3]{x+x^5+x^7}}{\left (1+x^4+x^6\right ) \left (1-x^2+x^4+x^6\right )} \, dx=\int \frac {\left (-1+x^4+2 x^6\right ) \sqrt [3]{x+x^5+x^7}}{\left (1+x^4+x^6\right ) \left (1-x^2+x^4+x^6\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt [3]{x+x^5+x^7} \int \frac {\sqrt [3]{x} \left (-1+x^4+2 x^6\right )}{\left (1+x^4+x^6\right )^{2/3} \left (1-x^2+x^4+x^6\right )} \, dx}{\sqrt [3]{x} \sqrt [3]{1+x^4+x^6}} \\ & = \frac {\left (3 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \frac {x^3 \left (-1+x^{12}+2 x^{18}\right )}{\left (1+x^{12}+x^{18}\right )^{2/3} \left (1-x^6+x^{12}+x^{18}\right )} \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{x} \sqrt [3]{1+x^4+x^6}} \\ & = \frac {\left (3 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \frac {x \left (-1+x^6+2 x^9\right )}{\left (1+x^6+x^9\right )^{2/3} \left (1-x^3+x^6+x^9\right )} \, dx,x,x^{2/3}\right )}{2 \sqrt [3]{x} \sqrt [3]{1+x^4+x^6}} \\ & = \frac {\left (3 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \left (\frac {2 x}{\left (1+x^6+x^9\right )^{2/3}}+\frac {x \left (-3+2 x^3-x^6\right )}{\left (1+x^6+x^9\right )^{2/3} \left (1-x^3+x^6+x^9\right )}\right ) \, dx,x,x^{2/3}\right )}{2 \sqrt [3]{x} \sqrt [3]{1+x^4+x^6}} \\ & = \frac {\left (3 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \frac {x \left (-3+2 x^3-x^6\right )}{\left (1+x^6+x^9\right )^{2/3} \left (1-x^3+x^6+x^9\right )} \, dx,x,x^{2/3}\right )}{2 \sqrt [3]{x} \sqrt [3]{1+x^4+x^6}}+\frac {\left (3 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \frac {x}{\left (1+x^6+x^9\right )^{2/3}} \, dx,x,x^{2/3}\right )}{\sqrt [3]{x} \sqrt [3]{1+x^4+x^6}} \\ & = \frac {\left (3 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \left (-\frac {3 x}{\left (1+x^6+x^9\right )^{2/3} \left (1-x^3+x^6+x^9\right )}+\frac {2 x^4}{\left (1+x^6+x^9\right )^{2/3} \left (1-x^3+x^6+x^9\right )}-\frac {x^7}{\left (1+x^6+x^9\right )^{2/3} \left (1-x^3+x^6+x^9\right )}\right ) \, dx,x,x^{2/3}\right )}{2 \sqrt [3]{x} \sqrt [3]{1+x^4+x^6}}+\frac {\left (3 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \frac {x}{\left (1+x^6+x^9\right )^{2/3}} \, dx,x,x^{2/3}\right )}{\sqrt [3]{x} \sqrt [3]{1+x^4+x^6}} \\ & = -\frac {\left (3 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \frac {x^7}{\left (1+x^6+x^9\right )^{2/3} \left (1-x^3+x^6+x^9\right )} \, dx,x,x^{2/3}\right )}{2 \sqrt [3]{x} \sqrt [3]{1+x^4+x^6}}+\frac {\left (3 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \frac {x}{\left (1+x^6+x^9\right )^{2/3}} \, dx,x,x^{2/3}\right )}{\sqrt [3]{x} \sqrt [3]{1+x^4+x^6}}+\frac {\left (3 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \frac {x^4}{\left (1+x^6+x^9\right )^{2/3} \left (1-x^3+x^6+x^9\right )} \, dx,x,x^{2/3}\right )}{\sqrt [3]{x} \sqrt [3]{1+x^4+x^6}}-\frac {\left (9 \sqrt [3]{x+x^5+x^7}\right ) \text {Subst}\left (\int \frac {x}{\left (1+x^6+x^9\right )^{2/3} \left (1-x^3+x^6+x^9\right )} \, dx,x,x^{2/3}\right )}{2 \sqrt [3]{x} \sqrt [3]{1+x^4+x^6}} \\ \end{align*}
Time = 3.29 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.49 \[ \int \frac {\left (-1+x^4+2 x^6\right ) \sqrt [3]{x+x^5+x^7}}{\left (1+x^4+x^6\right ) \left (1-x^2+x^4+x^6\right )} \, dx=\frac {\sqrt [3]{x+x^5+x^7} \left (2 \sqrt {3} \arctan \left (\frac {\sqrt {3} x^{2/3}}{x^{2/3}+2 \sqrt [3]{1+x^4+x^6}}\right )+2 \log \left (-x^{2/3}+\sqrt [3]{1+x^4+x^6}\right )-\log \left (x^{4/3}+x^{2/3} \sqrt [3]{1+x^4+x^6}+\left (1+x^4+x^6\right )^{2/3}\right )\right )}{4 \sqrt [3]{x} \sqrt [3]{1+x^4+x^6}} \]
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Time = 8.70 (sec) , antiderivative size = 92, normalized size of antiderivative = 1.00
method | result | size |
pseudoelliptic | \(\frac {\ln \left (\frac {{\left (x \left (x^{6}+x^{4}+1\right )\right )}^{\frac {1}{3}}-x}{x}\right )}{2}-\frac {\ln \left (\frac {{\left (x \left (x^{6}+x^{4}+1\right )\right )}^{\frac {2}{3}}+{\left (x \left (x^{6}+x^{4}+1\right )\right )}^{\frac {1}{3}} x +x^{2}}{x^{2}}\right )}{4}-\frac {\sqrt {3}\, \arctan \left (\frac {\left (2 {\left (x \left (x^{6}+x^{4}+1\right )\right )}^{\frac {1}{3}}+x \right ) \sqrt {3}}{3 x}\right )}{2}\) | \(92\) |
trager | \(\text {Expression too large to display}\) | \(738\) |
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Time = 1.73 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.38 \[ \int \frac {\left (-1+x^4+2 x^6\right ) \sqrt [3]{x+x^5+x^7}}{\left (1+x^4+x^6\right ) \left (1-x^2+x^4+x^6\right )} \, dx=\frac {1}{2} \, \sqrt {3} \arctan \left (\frac {2 \, \sqrt {3} {\left (x^{7} + x^{5} + x\right )}^{\frac {1}{3}} x + \sqrt {3} {\left (x^{6} + x^{4} + x^{2} + 1\right )} + 2 \, \sqrt {3} {\left (x^{7} + x^{5} + x\right )}^{\frac {2}{3}}}{x^{6} + x^{4} - x^{2} + 1}\right ) + \frac {1}{4} \, \log \left (\frac {x^{6} + x^{4} - x^{2} + 3 \, {\left (x^{7} + x^{5} + x\right )}^{\frac {1}{3}} x - 3 \, {\left (x^{7} + x^{5} + x\right )}^{\frac {2}{3}} + 1}{x^{6} + x^{4} - x^{2} + 1}\right ) \]
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Timed out. \[ \int \frac {\left (-1+x^4+2 x^6\right ) \sqrt [3]{x+x^5+x^7}}{\left (1+x^4+x^6\right ) \left (1-x^2+x^4+x^6\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {\left (-1+x^4+2 x^6\right ) \sqrt [3]{x+x^5+x^7}}{\left (1+x^4+x^6\right ) \left (1-x^2+x^4+x^6\right )} \, dx=\int { \frac {{\left (x^{7} + x^{5} + x\right )}^{\frac {1}{3}} {\left (2 \, x^{6} + x^{4} - 1\right )}}{{\left (x^{6} + x^{4} - x^{2} + 1\right )} {\left (x^{6} + x^{4} + 1\right )}} \,d x } \]
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\[ \int \frac {\left (-1+x^4+2 x^6\right ) \sqrt [3]{x+x^5+x^7}}{\left (1+x^4+x^6\right ) \left (1-x^2+x^4+x^6\right )} \, dx=\int { \frac {{\left (x^{7} + x^{5} + x\right )}^{\frac {1}{3}} {\left (2 \, x^{6} + x^{4} - 1\right )}}{{\left (x^{6} + x^{4} - x^{2} + 1\right )} {\left (x^{6} + x^{4} + 1\right )}} \,d x } \]
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Timed out. \[ \int \frac {\left (-1+x^4+2 x^6\right ) \sqrt [3]{x+x^5+x^7}}{\left (1+x^4+x^6\right ) \left (1-x^2+x^4+x^6\right )} \, dx=\int \frac {\left (2\,x^6+x^4-1\right )\,{\left (x^7+x^5+x\right )}^{1/3}}{\left (x^6+x^4+1\right )\,\left (x^6+x^4-x^2+1\right )} \,d x \]
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