Integrand size = 65, antiderivative size = 93 \[ \int \frac {2 a b x+(-3 a+b) x^2}{\sqrt [4]{x^2 (-a+x) (-b+x)} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx=-\frac {2 \arctan \left (\frac {\sqrt [4]{d} \sqrt [4]{a b x^2+(-a-b) x^3+x^4}}{a-x}\right )}{d^{3/4}}+\frac {2 \text {arctanh}\left (\frac {\sqrt [4]{d} \sqrt [4]{a b x^2+(-a-b) x^3+x^4}}{a-x}\right )}{d^{3/4}} \]
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\[ \int \frac {2 a b x+(-3 a+b) x^2}{\sqrt [4]{x^2 (-a+x) (-b+x)} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx=\int \frac {2 a b x+(-3 a+b) x^2}{\sqrt [4]{x^2 (-a+x) (-b+x)} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {x (2 a b+(-3 a+b) x)}{\sqrt [4]{x^2 (-a+x) (-b+x)} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx \\ & = \frac {\left (\sqrt {x} \sqrt [4]{-a+x} \sqrt [4]{-b+x}\right ) \int \frac {\sqrt {x} (2 a b+(-3 a+b) x)}{\sqrt [4]{-a+x} \sqrt [4]{-b+x} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx}{\sqrt [4]{x^2 (-a+x) (-b+x)}} \\ & = \frac {\left (2 \sqrt {x} \sqrt [4]{-a+x} \sqrt [4]{-b+x}\right ) \text {Subst}\left (\int \frac {x^2 \left (2 a b+(-3 a+b) x^2\right )}{\sqrt [4]{-a+x^2} \sqrt [4]{-b+x^2} \left (a^3-3 a^2 x^2+(3 a-b d) x^4+(-1+d) x^6\right )} \, dx,x,\sqrt {x}\right )}{\sqrt [4]{x^2 (-a+x) (-b+x)}} \\ & = \frac {\left (2 \sqrt {x} \sqrt [4]{-a+x} \sqrt [4]{-b+x}\right ) \text {Subst}\left (\int \left (\frac {2 a b x^2}{\sqrt [4]{-a+x^2} \sqrt [4]{-b+x^2} \left (a^3-3 a^2 x^2+3 a \left (1-\frac {b d}{3 a}\right ) x^4-(1-d) x^6\right )}+\frac {(-3 a+b) x^4}{\sqrt [4]{-a+x^2} \sqrt [4]{-b+x^2} \left (a^3-3 a^2 x^2+3 a \left (1-\frac {b d}{3 a}\right ) x^4-(1-d) x^6\right )}\right ) \, dx,x,\sqrt {x}\right )}{\sqrt [4]{x^2 (-a+x) (-b+x)}} \\ & = \frac {\left (4 a b \sqrt {x} \sqrt [4]{-a+x} \sqrt [4]{-b+x}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt [4]{-a+x^2} \sqrt [4]{-b+x^2} \left (a^3-3 a^2 x^2+3 a \left (1-\frac {b d}{3 a}\right ) x^4-(1-d) x^6\right )} \, dx,x,\sqrt {x}\right )}{\sqrt [4]{x^2 (-a+x) (-b+x)}}+\frac {\left (2 (-3 a+b) \sqrt {x} \sqrt [4]{-a+x} \sqrt [4]{-b+x}\right ) \text {Subst}\left (\int \frac {x^4}{\sqrt [4]{-a+x^2} \sqrt [4]{-b+x^2} \left (a^3-3 a^2 x^2+3 a \left (1-\frac {b d}{3 a}\right ) x^4-(1-d) x^6\right )} \, dx,x,\sqrt {x}\right )}{\sqrt [4]{x^2 (-a+x) (-b+x)}} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(211\) vs. \(2(93)=186\).
Time = 33.04 (sec) , antiderivative size = 211, normalized size of antiderivative = 2.27 \[ \int \frac {2 a b x+(-3 a+b) x^2}{\sqrt [4]{x^2 (-a+x) (-b+x)} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx=-\frac {x \sqrt [4]{\frac {-b+x}{a-x}} \left (\arctan \left (\frac {a-x \left (1+\sqrt {d} \sqrt {\frac {-b+x}{a-x}}\right )}{\sqrt {2} \sqrt [4]{d} \sqrt {\frac {x}{a-x}} (-a+x) \sqrt [4]{\frac {-b+x}{a-x}}}\right )-\text {arctanh}\left (\frac {\sqrt [4]{d} x \sqrt [4]{\frac {-b+x}{a-x}}}{\sqrt {\frac {x}{2 a-2 x}} \left (a+x \left (-1+\sqrt {d} \sqrt {\frac {-b+x}{a-x}}\right )\right )}\right )\right )}{d^{3/4} \sqrt {\frac {x}{2 a-2 x}} \sqrt [4]{x^2 (-a+x) (-b+x)}} \]
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\[\int \frac {2 a b x +\left (-3 a +b \right ) x^{2}}{\left (x^{2} \left (-a +x \right ) \left (-b +x \right )\right )^{\frac {1}{4}} \left (a^{3}-3 a^{2} x +\left (-d b +3 a \right ) x^{2}+\left (d -1\right ) x^{3}\right )}d x\]
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Timed out. \[ \int \frac {2 a b x+(-3 a+b) x^2}{\sqrt [4]{x^2 (-a+x) (-b+x)} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {2 a b x+(-3 a+b) x^2}{\sqrt [4]{x^2 (-a+x) (-b+x)} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {2 a b x+(-3 a+b) x^2}{\sqrt [4]{x^2 (-a+x) (-b+x)} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx=\int { \frac {2 \, a b x - {\left (3 \, a - b\right )} x^{2}}{\left ({\left (a - x\right )} {\left (b - x\right )} x^{2}\right )^{\frac {1}{4}} {\left ({\left (d - 1\right )} x^{3} + a^{3} - 3 \, a^{2} x - {\left (b d - 3 \, a\right )} x^{2}\right )}} \,d x } \]
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\[ \int \frac {2 a b x+(-3 a+b) x^2}{\sqrt [4]{x^2 (-a+x) (-b+x)} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx=\int { \frac {2 \, a b x - {\left (3 \, a - b\right )} x^{2}}{\left ({\left (a - x\right )} {\left (b - x\right )} x^{2}\right )^{\frac {1}{4}} {\left ({\left (d - 1\right )} x^{3} + a^{3} - 3 \, a^{2} x - {\left (b d - 3 \, a\right )} x^{2}\right )}} \,d x } \]
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Timed out. \[ \int \frac {2 a b x+(-3 a+b) x^2}{\sqrt [4]{x^2 (-a+x) (-b+x)} \left (a^3-3 a^2 x+(3 a-b d) x^2+(-1+d) x^3\right )} \, dx=\int -\frac {x^2\,\left (3\,a-b\right )-2\,a\,b\,x}{{\left (x^2\,\left (a-x\right )\,\left (b-x\right )\right )}^{1/4}\,\left (x^2\,\left (3\,a-b\,d\right )-3\,a^2\,x+a^3+x^3\,\left (d-1\right )\right )} \,d x \]
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