Integrand size = 84, antiderivative size = 96 \[ \int \frac {\left (1-2 x+x^2\right ) \left (-2+(-1+k) (1+k) x+2 k^2 x^2\right )}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{3/4} \left (-1+d-(1+3 d) x+\left (3 d+k^2\right ) x^2+\left (-d+k^2\right ) x^3\right )} \, dx=-\frac {\arctan \left (\frac {-\sqrt [4]{d}+\sqrt [4]{d} x}{\sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}}\right )}{d^{3/4}}+\frac {\text {arctanh}\left (\frac {-\sqrt [4]{d}+\sqrt [4]{d} x}{\sqrt [4]{1+\left (-1-k^2\right ) x^2+k^2 x^4}}\right )}{d^{3/4}} \]
[Out]
Timed out. \[ \int \frac {\left (1-2 x+x^2\right ) \left (-2+(-1+k) (1+k) x+2 k^2 x^2\right )}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{3/4} \left (-1+d-(1+3 d) x+\left (3 d+k^2\right ) x^2+\left (-d+k^2\right ) x^3\right )} \, dx=\text {\$Aborted} \]
[In]
[Out]
Rubi steps Aborted
\[ \int \frac {\left (1-2 x+x^2\right ) \left (-2+(-1+k) (1+k) x+2 k^2 x^2\right )}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{3/4} \left (-1+d-(1+3 d) x+\left (3 d+k^2\right ) x^2+\left (-d+k^2\right ) x^3\right )} \, dx=\int \frac {\left (1-2 x+x^2\right ) \left (-2+(-1+k) (1+k) x+2 k^2 x^2\right )}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{3/4} \left (-1+d-(1+3 d) x+\left (3 d+k^2\right ) x^2+\left (-d+k^2\right ) x^3\right )} \, dx \]
[In]
[Out]
\[\int \frac {\left (x^{2}-2 x +1\right ) \left (-2+\left (-1+k \right ) \left (1+k \right ) x +2 k^{2} x^{2}\right )}{{\left (\left (-x^{2}+1\right ) \left (-k^{2} x^{2}+1\right )\right )}^{\frac {3}{4}} \left (-1+d -\left (1+3 d \right ) x +\left (k^{2}+3 d \right ) x^{2}+\left (k^{2}-d \right ) x^{3}\right )}d x\]
[In]
[Out]
Timed out. \[ \int \frac {\left (1-2 x+x^2\right ) \left (-2+(-1+k) (1+k) x+2 k^2 x^2\right )}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{3/4} \left (-1+d-(1+3 d) x+\left (3 d+k^2\right ) x^2+\left (-d+k^2\right ) x^3\right )} \, dx=\text {Timed out} \]
[In]
[Out]
Timed out. \[ \int \frac {\left (1-2 x+x^2\right ) \left (-2+(-1+k) (1+k) x+2 k^2 x^2\right )}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{3/4} \left (-1+d-(1+3 d) x+\left (3 d+k^2\right ) x^2+\left (-d+k^2\right ) x^3\right )} \, dx=\text {Timed out} \]
[In]
[Out]
\[ \int \frac {\left (1-2 x+x^2\right ) \left (-2+(-1+k) (1+k) x+2 k^2 x^2\right )}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{3/4} \left (-1+d-(1+3 d) x+\left (3 d+k^2\right ) x^2+\left (-d+k^2\right ) x^3\right )} \, dx=\int { \frac {{\left (2 \, k^{2} x^{2} + {\left (k + 1\right )} {\left (k - 1\right )} x - 2\right )} {\left (x^{2} - 2 \, x + 1\right )}}{{\left ({\left (k^{2} - d\right )} x^{3} + {\left (k^{2} + 3 \, d\right )} x^{2} - {\left (3 \, d + 1\right )} x + d - 1\right )} \left ({\left (k^{2} x^{2} - 1\right )} {\left (x^{2} - 1\right )}\right )^{\frac {3}{4}}} \,d x } \]
[In]
[Out]
\[ \int \frac {\left (1-2 x+x^2\right ) \left (-2+(-1+k) (1+k) x+2 k^2 x^2\right )}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{3/4} \left (-1+d-(1+3 d) x+\left (3 d+k^2\right ) x^2+\left (-d+k^2\right ) x^3\right )} \, dx=\int { \frac {{\left (2 \, k^{2} x^{2} + {\left (k + 1\right )} {\left (k - 1\right )} x - 2\right )} {\left (x^{2} - 2 \, x + 1\right )}}{{\left ({\left (k^{2} - d\right )} x^{3} + {\left (k^{2} + 3 \, d\right )} x^{2} - {\left (3 \, d + 1\right )} x + d - 1\right )} \left ({\left (k^{2} x^{2} - 1\right )} {\left (x^{2} - 1\right )}\right )^{\frac {3}{4}}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {\left (1-2 x+x^2\right ) \left (-2+(-1+k) (1+k) x+2 k^2 x^2\right )}{\left (\left (1-x^2\right ) \left (1-k^2 x^2\right )\right )^{3/4} \left (-1+d-(1+3 d) x+\left (3 d+k^2\right ) x^2+\left (-d+k^2\right ) x^3\right )} \, dx=-\int \frac {\left (x^2-2\,x+1\right )\,\left (2\,k^2\,x^2+x\,\left (k-1\right )\,\left (k+1\right )-2\right )}{{\left (\left (x^2-1\right )\,\left (k^2\,x^2-1\right )\right )}^{3/4}\,\left (\left (d-k^2\right )\,x^3+\left (-k^2-3\,d\right )\,x^2+\left (3\,d+1\right )\,x-d+1\right )} \,d x \]
[In]
[Out]