\(\int \frac {\sqrt [3]{-1+x^3}}{x^7} \, dx\) [1341]

Optimal result

Integrand size = 13, antiderivative size = 97 \[ \int \frac {\sqrt [3]{-1+x^3}}{x^7} \, dx=\frac {\left (-3+x^3\right ) \sqrt [3]{-1+x^3}}{18 x^6}-\frac {\arctan \left (\frac {1}{\sqrt {3}}-\frac {2 \sqrt [3]{-1+x^3}}{\sqrt {3}}\right )}{9 \sqrt {3}}+\frac {1}{27} \log \left (1+\sqrt [3]{-1+x^3}\right )-\frac {1}{54} \log \left (1-\sqrt [3]{-1+x^3}+\left (-1+x^3\right )^{2/3}\right ) \]

[Out]

1/18*(x^3-3)*(x^3-1)^(1/3)/x^6+1/27*arctan(-1/3*3^(1/2)+2/3*(x^3-1)^(1/3)*3^(1/2))*3^(1/2)+1/27*ln(1+(x^3-1)^(
1/3))-1/54*ln(1-(x^3-1)^(1/3)+(x^3-1)^(2/3))

Rubi [A] (verified)

Time = 0.03 (sec) , antiderivative size = 84, normalized size of antiderivative = 0.87, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.538, Rules used = {272, 43, 44, 60, 632, 210, 31} \[ \int \frac {\sqrt [3]{-1+x^3}}{x^7} \, dx=-\frac {\arctan \left (\frac {1-2 \sqrt [3]{x^3-1}}{\sqrt {3}}\right )}{9 \sqrt {3}}+\frac {\sqrt [3]{x^3-1}}{18 x^3}+\frac {1}{18} \log \left (\sqrt [3]{x^3-1}+1\right )-\frac {\sqrt [3]{x^3-1}}{6 x^6}-\frac {\log (x)}{18} \]

[In]

Int[(-1 + x^3)^(1/3)/x^7,x]

[Out]

-1/6*(-1 + x^3)^(1/3)/x^6 + (-1 + x^3)^(1/3)/(18*x^3) - ArcTan[(1 - 2*(-1 + x^3)^(1/3))/Sqrt[3]]/(9*Sqrt[3]) -
Log[x]/18 + Log[1 + (-1 + x^3)^(1/3)]/18

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + 1))), x] - Dist[d*(n/(b*(m + 1))), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d, n
}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, -1] &&  !IntegerQ[n] && GtQ[n, 0]

Rule 44

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n + 1
)/((b*c - a*d)*(m + 1))), x] - Dist[d*((m + n + 2)/((b*c - a*d)*(m + 1))), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, -1] &&  !IntegerQ[n] && LtQ[n, 0]

Rule 60

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(2/3)), x_Symbol] :> With[{q = Rt[-(b*c - a*d)/b, 3]}, Simp[-
Log[RemoveContent[a + b*x, x]]/(2*b*q^2), x] + (Dist[3/(2*b*q), Subst[Int[1/(q^2 - q*x + x^2), x], x, (c + d*x
)^(1/3)], x] + Dist[3/(2*b*q^2), Subst[Int[1/(q + x), x], x, (c + d*x)^(1/3)], x])] /; FreeQ[{a, b, c, d}, x]
&& NegQ[(b*c - a*d)/b]

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 272

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 632

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {\sqrt [3]{-1+x}}{x^3} \, dx,x,x^3\right ) \\ & = -\frac {\sqrt [3]{-1+x^3}}{6 x^6}+\frac {1}{18} \text {Subst}\left (\int \frac {1}{(-1+x)^{2/3} x^2} \, dx,x,x^3\right ) \\ & = -\frac {\sqrt [3]{-1+x^3}}{6 x^6}+\frac {\sqrt [3]{-1+x^3}}{18 x^3}+\frac {1}{27} \text {Subst}\left (\int \frac {1}{(-1+x)^{2/3} x} \, dx,x,x^3\right ) \\ & = -\frac {\sqrt [3]{-1+x^3}}{6 x^6}+\frac {\sqrt [3]{-1+x^3}}{18 x^3}-\frac {\log (x)}{18}+\frac {1}{18} \text {Subst}\left (\int \frac {1}{1+x} \, dx,x,\sqrt [3]{-1+x^3}\right )+\frac {1}{18} \text {Subst}\left (\int \frac {1}{1-x+x^2} \, dx,x,\sqrt [3]{-1+x^3}\right ) \\ & = -\frac {\sqrt [3]{-1+x^3}}{6 x^6}+\frac {\sqrt [3]{-1+x^3}}{18 x^3}-\frac {\log (x)}{18}+\frac {1}{18} \log \left (1+\sqrt [3]{-1+x^3}\right )-\frac {1}{9} \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,-1+2 \sqrt [3]{-1+x^3}\right ) \\ & = -\frac {\sqrt [3]{-1+x^3}}{6 x^6}+\frac {\sqrt [3]{-1+x^3}}{18 x^3}-\frac {\arctan \left (\frac {1-2 \sqrt [3]{-1+x^3}}{\sqrt {3}}\right )}{9 \sqrt {3}}-\frac {\log (x)}{18}+\frac {1}{18} \log \left (1+\sqrt [3]{-1+x^3}\right ) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.11 (sec) , antiderivative size = 90, normalized size of antiderivative = 0.93 \[ \int \frac {\sqrt [3]{-1+x^3}}{x^7} \, dx=\frac {1}{54} \left (\frac {3 \left (-3+x^3\right ) \sqrt [3]{-1+x^3}}{x^6}-2 \sqrt {3} \arctan \left (\frac {1-2 \sqrt [3]{-1+x^3}}{\sqrt {3}}\right )+2 \log \left (1+\sqrt [3]{-1+x^3}\right )-\log \left (1-\sqrt [3]{-1+x^3}+\left (-1+x^3\right )^{2/3}\right )\right ) \]

[In]

Integrate[(-1 + x^3)^(1/3)/x^7,x]

[Out]

((3*(-3 + x^3)*(-1 + x^3)^(1/3))/x^6 - 2*Sqrt[3]*ArcTan[(1 - 2*(-1 + x^3)^(1/3))/Sqrt[3]] + 2*Log[1 + (-1 + x^
3)^(1/3)] - Log[1 - (-1 + x^3)^(1/3) + (-1 + x^3)^(2/3)])/54

Maple [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 9 vs. order 3.

Time = 3.43 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.84

method	result	size
meijerg	\(-\frac {\operatorname {signum}\left (x^{3}-1\right )^{\frac {1}{3}} \left (\frac {5 \Gamma \left (\frac {2}{3}\right ) x^{3} \operatorname {hypergeom}\left (\left [1, 1, \frac {8}{3}\right ], \left [2, 4\right ], x^{3}\right )}{27}+\frac {\left (\frac {\pi \sqrt {3}}{6}-\frac {3 \ln \left (3\right )}{2}+3 \ln \left (x \right )+i \pi \right ) \Gamma \left (\frac {2}{3}\right )}{3}+\frac {3 \Gamma \left (\frac {2}{3}\right )}{2 x^{6}}-\frac {\Gamma \left (\frac {2}{3}\right )}{x^{3}}\right )}{9 \Gamma \left (\frac {2}{3}\right ) {\left (-\operatorname {signum}\left (x^{3}-1\right )\right )}^{\frac {1}{3}}}\)	\(81\)
risch	\(\frac {x^{6}-4 x^{3}+3}{18 x^{6} \left (x^{3}-1\right )^{\frac {2}{3}}}+\frac {{\left (-\operatorname {signum}\left (x^{3}-1\right )\right )}^{\frac {2}{3}} \left (\frac {2 \Gamma \left (\frac {2}{3}\right ) x^{3} \operatorname {hypergeom}\left (\left [1, 1, \frac {5}{3}\right ], \left [2, 2\right ], x^{3}\right )}{3}+\left (\frac {\pi \sqrt {3}}{6}-\frac {3 \ln \left (3\right )}{2}+3 \ln \left (x \right )+i \pi \right ) \Gamma \left (\frac {2}{3}\right )\right )}{27 \Gamma \left (\frac {2}{3}\right ) \operatorname {signum}\left (x^{3}-1\right )^{\frac {2}{3}}}\)	\(89\)
pseudoelliptic	\(\frac {2 \sqrt {3}\, \arctan \left (\frac {\left (2 \left (x^{3}-1\right )^{\frac {1}{3}}-1\right ) \sqrt {3}}{3}\right ) x^{6}+2 \ln \left (1+\left (x^{3}-1\right )^{\frac {1}{3}}\right ) x^{6}-\ln \left (1-\left (x^{3}-1\right )^{\frac {1}{3}}+\left (x^{3}-1\right )^{\frac {2}{3}}\right ) x^{6}+3 x^{3} \left (x^{3}-1\right )^{\frac {1}{3}}-9 \left (x^{3}-1\right )^{\frac {1}{3}}}{54 {\left (1+\left (x^{3}-1\right )^{\frac {1}{3}}\right )}^{2} {\left (1-\left (x^{3}-1\right )^{\frac {1}{3}}+\left (x^{3}-1\right )^{\frac {2}{3}}\right )}^{2}}\)	\(120\)
trager	\(\frac {\left (x^{3}-3\right ) \left (x^{3}-1\right )^{\frac {1}{3}}}{18 x^{6}}-\frac {\ln \left (-\frac {5890048 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2} x^{3}+630720 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) x^{3}-352128 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) \left (x^{3}-1\right )^{\frac {2}{3}}-1477 x^{3}-47120384 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2}+352128 \left (x^{3}-1\right )^{\frac {1}{3}} \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )+14247 \left (x^{3}-1\right )^{\frac {2}{3}}-1088384 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )-14247 \left (x^{3}-1\right )^{\frac {1}{3}}+2743}{x^{3}}\right )}{27}-\frac {64 \ln \left (-\frac {5890048 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2} x^{3}+630720 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) x^{3}-352128 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) \left (x^{3}-1\right )^{\frac {2}{3}}-1477 x^{3}-47120384 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2}+352128 \left (x^{3}-1\right )^{\frac {1}{3}} \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )+14247 \left (x^{3}-1\right )^{\frac {2}{3}}-1088384 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )-14247 \left (x^{3}-1\right )^{\frac {1}{3}}+2743}{x^{3}}\right ) \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )}{27}+\frac {64 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) \ln \left (-\frac {5890048 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2} x^{3}-446656 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) x^{3}+352128 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) \left (x^{3}-1\right )^{\frac {2}{3}}-9894 x^{3}-47120384 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2}-352128 \left (x^{3}-1\right )^{\frac {1}{3}} \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )+19749 \left (x^{3}-1\right )^{\frac {2}{3}}-384128 \operatorname {RootOf}\left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )-19749 \left (x^{3}-1\right )^{\frac {1}{3}}+8245}{x^{3}}\right )}{27}\)	\(446\)

[In]

int((x^3-1)^(1/3)/x^7,x,method=_RETURNVERBOSE)

[Out]

-1/9/GAMMA(2/3)*signum(x^3-1)^(1/3)/(-signum(x^3-1))^(1/3)*(5/27*GAMMA(2/3)*x^3*hypergeom([1,1,8/3],[2,4],x^3)
+1/3*(1/6*Pi*3^(1/2)-3/2*ln(3)+3*ln(x)+I*Pi)*GAMMA(2/3)+3/2*GAMMA(2/3)/x^6-GAMMA(2/3)/x^3)

Fricas [A] (verification not implemented)

none

Time = 0.29 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.89 \[ \int \frac {\sqrt [3]{-1+x^3}}{x^7} \, dx=\frac {2 \, \sqrt {3} x^{6} \arctan \left (\frac {2}{3} \, \sqrt {3} {\left (x^{3} - 1\right )}^{\frac {1}{3}} - \frac {1}{3} \, \sqrt {3}\right ) - x^{6} \log \left ({\left (x^{3} - 1\right )}^{\frac {2}{3}} - {\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1\right ) + 2 \, x^{6} \log \left ({\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1\right ) + 3 \, {\left (x^{3} - 1\right )}^{\frac {1}{3}} {\left (x^{3} - 3\right )}}{54 \, x^{6}} \]

[In]

integrate((x^3-1)^(1/3)/x^7,x, algorithm="fricas")

[Out]

1/54*(2*sqrt(3)*x^6*arctan(2/3*sqrt(3)*(x^3 - 1)^(1/3) - 1/3*sqrt(3)) - x^6*log((x^3 - 1)^(2/3) - (x^3 - 1)^(1
/3) + 1) + 2*x^6*log((x^3 - 1)^(1/3) + 1) + 3*(x^3 - 1)^(1/3)*(x^3 - 3))/x^6

Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 1.18 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.35 \[ \int \frac {\sqrt [3]{-1+x^3}}{x^7} \, dx=- \frac {\Gamma \left (\frac {5}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{3}, \frac {5}{3} \\ \frac {8}{3} \end {matrix}\middle | {\frac {e^{2 i \pi }}{x^{3}}} \right )}}{3 x^{5} \Gamma \left (\frac {8}{3}\right )} \]

[In]

integrate((x**3-1)**(1/3)/x**7,x)

[Out]

-gamma(5/3)*hyper((-1/3, 5/3), (8/3,), exp_polar(2*I*pi)/x**3)/(3*x**5*gamma(8/3))

Maxima [A] (verification not implemented)

none

Time = 0.27 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.94 \[ \int \frac {\sqrt [3]{-1+x^3}}{x^7} \, dx=\frac {1}{27} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, {\left (x^{3} - 1\right )}^{\frac {1}{3}} - 1\right )}\right ) + \frac {{\left (x^{3} - 1\right )}^{\frac {4}{3}} - 2 \, {\left (x^{3} - 1\right )}^{\frac {1}{3}}}{18 \, {\left (2 \, x^{3} + {\left (x^{3} - 1\right )}^{2} - 1\right )}} - \frac {1}{54} \, \log \left ({\left (x^{3} - 1\right )}^{\frac {2}{3}} - {\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1\right ) + \frac {1}{27} \, \log \left ({\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1\right ) \]

[In]

integrate((x^3-1)^(1/3)/x^7,x, algorithm="maxima")

[Out]

1/27*sqrt(3)*arctan(1/3*sqrt(3)*(2*(x^3 - 1)^(1/3) - 1)) + 1/18*((x^3 - 1)^(4/3) - 2*(x^3 - 1)^(1/3))/(2*x^3 +
(x^3 - 1)^2 - 1) - 1/54*log((x^3 - 1)^(2/3) - (x^3 - 1)^(1/3) + 1) + 1/27*log((x^3 - 1)^(1/3) + 1)

Giac [A] (verification not implemented)

none

Time = 0.27 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.81 \[ \int \frac {\sqrt [3]{-1+x^3}}{x^7} \, dx=\frac {1}{27} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, {\left (x^{3} - 1\right )}^{\frac {1}{3}} - 1\right )}\right ) + \frac {{\left (x^{3} - 1\right )}^{\frac {4}{3}} - 2 \, {\left (x^{3} - 1\right )}^{\frac {1}{3}}}{18 \, x^{6}} - \frac {1}{54} \, \log \left ({\left (x^{3} - 1\right )}^{\frac {2}{3}} - {\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1\right ) + \frac {1}{27} \, \log \left ({\left | {\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1 \right |}\right ) \]

[In]

integrate((x^3-1)^(1/3)/x^7,x, algorithm="giac")

[Out]

1/27*sqrt(3)*arctan(1/3*sqrt(3)*(2*(x^3 - 1)^(1/3) - 1)) + 1/18*((x^3 - 1)^(4/3) - 2*(x^3 - 1)^(1/3))/x^6 - 1/
54*log((x^3 - 1)^(2/3) - (x^3 - 1)^(1/3) + 1) + 1/27*log(abs((x^3 - 1)^(1/3) + 1))

Mupad [B] (verification not implemented)

Time = 6.41 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.10 \[ \int \frac {\sqrt [3]{-1+x^3}}{x^7} \, dx=\frac {\ln \left (\frac {{\left (x^3-1\right )}^{1/3}}{81}+\frac {1}{81}\right )}{27}-\frac {\frac {{\left (x^3-1\right )}^{1/3}}{9}-\frac {{\left (x^3-1\right )}^{4/3}}{18}}{{\left (x^3-1\right )}^2+2\,x^3-1}-\ln \left (\frac {1}{6}-\frac {{\left (x^3-1\right )}^{1/3}}{3}+\frac {\sqrt {3}\,1{}\mathrm {i}}{6}\right )\,\left (\frac {1}{54}+\frac {\sqrt {3}\,1{}\mathrm {i}}{54}\right )+\ln \left (\frac {{\left (x^3-1\right )}^{1/3}}{3}-\frac {1}{6}+\frac {\sqrt {3}\,1{}\mathrm {i}}{6}\right )\,\left (-\frac {1}{54}+\frac {\sqrt {3}\,1{}\mathrm {i}}{54}\right ) \]

[In]

int((x^3 - 1)^(1/3)/x^7,x)

[Out]

log((x^3 - 1)^(1/3)/81 + 1/81)/27 - ((x^3 - 1)^(1/3)/9 - (x^3 - 1)^(4/3)/18)/((x^3 - 1)^2 + 2*x^3 - 1) - log((
3^(1/2)*1i)/6 - (x^3 - 1)^(1/3)/3 + 1/6)*((3^(1/2)*1i)/54 + 1/54) + log((3^(1/2)*1i)/6 + (x^3 - 1)^(1/3)/3 - 1
/6)*((3^(1/2)*1i)/54 - 1/54)