Integrand size = 35, antiderivative size = 101 \[ \int \frac {1-x^4}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx=-\frac {\sqrt {a+b x+c x^2+b x^3+a x^4}}{a x}+\frac {b \log (x)}{2 a^{3/2}}-\frac {b \log \left (-2 a-b x-2 a x^2+2 \sqrt {a} \sqrt {a+b x+c x^2+b x^3+a x^4}\right )}{2 a^{3/2}} \]
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\[ \int \frac {1-x^4}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx=\int \frac {1-x^4}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {1}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}}-\frac {x^2}{\sqrt {a+b x+c x^2+b x^3+a x^4}}\right ) \, dx \\ & = \int \frac {1}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx-\int \frac {x^2}{\sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx \\ \end{align*}
Time = 0.42 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.88 \[ \int \frac {1-x^4}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx=-\frac {\sqrt {x \left (b+c x+b x^2\right )+a \left (1+x^4\right )}}{a x}+\frac {b \text {arctanh}\left (\frac {2 \sqrt {a} \sqrt {x \left (b+c x+b x^2\right )+a \left (1+x^4\right )}}{b x+2 a \left (1+x^2\right )}\right )}{2 a^{3/2}} \]
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Time = 3.68 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.90
method | result | size |
risch | \(-\frac {\sqrt {a \,x^{4}+b \,x^{3}+c \,x^{2}+b x +a}}{a x}+\frac {b \left (-\ln \left (2\right )+\ln \left (\frac {2 a \,x^{2}+2 \sqrt {a}\, \sqrt {a \,x^{4}+b \,x^{3}+c \,x^{2}+b x +a}+b x +2 a}{x \sqrt {a}}\right )\right )}{2 a^{\frac {3}{2}}}\) | \(91\) |
default | \(-\frac {-\ln \left (\frac {2 a \,x^{2}+2 \sqrt {a}\, \sqrt {a \,x^{4}+b \,x^{3}+c \,x^{2}+b x +a}+b x +2 a}{x \sqrt {a}}\right ) b x +\ln \left (2\right ) b x +2 \sqrt {a}\, \sqrt {a \,x^{4}+b \,x^{3}+c \,x^{2}+b x +a}}{2 a^{\frac {3}{2}} x}\) | \(94\) |
pseudoelliptic | \(\frac {\ln \left (\frac {2 a \,x^{2}+2 \sqrt {a}\, \sqrt {a \,x^{4}+b \,x^{3}+c \,x^{2}+b x +a}+b x +2 a}{x \sqrt {a}}\right ) b x -\ln \left (2\right ) b x -2 \sqrt {a}\, \sqrt {a \,x^{4}+b \,x^{3}+c \,x^{2}+b x +a}}{2 a^{\frac {3}{2}} x}\) | \(94\) |
elliptic | \(\text {Expression too large to display}\) | \(3402\) |
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Time = 0.82 (sec) , antiderivative size = 216, normalized size of antiderivative = 2.14 \[ \int \frac {1-x^4}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx=\left [\frac {\sqrt {a} b x \log \left (\frac {8 \, a^{2} x^{4} + 8 \, a b x^{3} + 8 \, a b x + {\left (8 \, a^{2} + b^{2} + 4 \, a c\right )} x^{2} + 4 \, \sqrt {a x^{4} + b x^{3} + c x^{2} + b x + a} {\left (2 \, a x^{2} + b x + 2 \, a\right )} \sqrt {a} + 8 \, a^{2}}{x^{2}}\right ) - 4 \, \sqrt {a x^{4} + b x^{3} + c x^{2} + b x + a} a}{4 \, a^{2} x}, -\frac {\sqrt {-a} b x \arctan \left (\frac {2 \, \sqrt {a x^{4} + b x^{3} + c x^{2} + b x + a} \sqrt {-a}}{2 \, a x^{2} + b x + 2 \, a}\right ) + 2 \, \sqrt {a x^{4} + b x^{3} + c x^{2} + b x + a} a}{2 \, a^{2} x}\right ] \]
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\[ \int \frac {1-x^4}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx=- \int \left (- \frac {1}{x^{2} \sqrt {a x^{4} + a + b x^{3} + b x + c x^{2}}}\right )\, dx - \int \frac {x^{2}}{\sqrt {a x^{4} + a + b x^{3} + b x + c x^{2}}}\, dx \]
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\[ \int \frac {1-x^4}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx=\int { -\frac {x^{4} - 1}{\sqrt {a x^{4} + b x^{3} + c x^{2} + b x + a} x^{2}} \,d x } \]
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\[ \int \frac {1-x^4}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx=\int { -\frac {x^{4} - 1}{\sqrt {a x^{4} + b x^{3} + c x^{2} + b x + a} x^{2}} \,d x } \]
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Timed out. \[ \int \frac {1-x^4}{x^2 \sqrt {a+b x+c x^2+b x^3+a x^4}} \, dx=-\int \frac {x^4-1}{x^2\,\sqrt {a\,x^4+b\,x^3+c\,x^2+b\,x+a}} \,d x \]
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