Integrand size = 25, antiderivative size = 104 \[ \int \frac {b+a x^3}{x^3 \sqrt [4]{-b x+a x^4}} \, dx=\frac {4 \left (-b x+a x^4\right )^{3/4}}{9 x^3}+\frac {2}{3} a^{3/4} \arctan \left (\frac {\sqrt [4]{a} \left (-b x+a x^4\right )^{3/4}}{-b+a x^3}\right )+\frac {2}{3} a^{3/4} \text {arctanh}\left (\frac {\sqrt [4]{a} \left (-b x+a x^4\right )^{3/4}}{-b+a x^3}\right ) \]
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Time = 0.10 (sec) , antiderivative size = 154, normalized size of antiderivative = 1.48, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.320, Rules used = {2063, 2036, 335, 281, 246, 218, 212, 209} \[ \int \frac {b+a x^3}{x^3 \sqrt [4]{-b x+a x^4}} \, dx=\frac {2 a^{3/4} \sqrt [4]{x} \sqrt [4]{a x^3-b} \arctan \left (\frac {\sqrt [4]{a} x^{3/4}}{\sqrt [4]{a x^3-b}}\right )}{3 \sqrt [4]{a x^4-b x}}+\frac {2 a^{3/4} \sqrt [4]{x} \sqrt [4]{a x^3-b} \text {arctanh}\left (\frac {\sqrt [4]{a} x^{3/4}}{\sqrt [4]{a x^3-b}}\right )}{3 \sqrt [4]{a x^4-b x}}+\frac {4 \left (a x^4-b x\right )^{3/4}}{9 x^3} \]
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Rule 209
Rule 212
Rule 218
Rule 246
Rule 281
Rule 335
Rule 2036
Rule 2063
Rubi steps \begin{align*} \text {integral}& = \frac {4 \left (-b x+a x^4\right )^{3/4}}{9 x^3}+a \int \frac {1}{\sqrt [4]{-b x+a x^4}} \, dx \\ & = \frac {4 \left (-b x+a x^4\right )^{3/4}}{9 x^3}+\frac {\left (a \sqrt [4]{x} \sqrt [4]{-b+a x^3}\right ) \int \frac {1}{\sqrt [4]{x} \sqrt [4]{-b+a x^3}} \, dx}{\sqrt [4]{-b x+a x^4}} \\ & = \frac {4 \left (-b x+a x^4\right )^{3/4}}{9 x^3}+\frac {\left (4 a \sqrt [4]{x} \sqrt [4]{-b+a x^3}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt [4]{-b+a x^{12}}} \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{-b x+a x^4}} \\ & = \frac {4 \left (-b x+a x^4\right )^{3/4}}{9 x^3}+\frac {\left (4 a \sqrt [4]{x} \sqrt [4]{-b+a x^3}\right ) \text {Subst}\left (\int \frac {1}{\sqrt [4]{-b+a x^4}} \, dx,x,x^{3/4}\right )}{3 \sqrt [4]{-b x+a x^4}} \\ & = \frac {4 \left (-b x+a x^4\right )^{3/4}}{9 x^3}+\frac {\left (4 a \sqrt [4]{x} \sqrt [4]{-b+a x^3}\right ) \text {Subst}\left (\int \frac {1}{1-a x^4} \, dx,x,\frac {x^{3/4}}{\sqrt [4]{-b+a x^3}}\right )}{3 \sqrt [4]{-b x+a x^4}} \\ & = \frac {4 \left (-b x+a x^4\right )^{3/4}}{9 x^3}+\frac {\left (2 a \sqrt [4]{x} \sqrt [4]{-b+a x^3}\right ) \text {Subst}\left (\int \frac {1}{1-\sqrt {a} x^2} \, dx,x,\frac {x^{3/4}}{\sqrt [4]{-b+a x^3}}\right )}{3 \sqrt [4]{-b x+a x^4}}+\frac {\left (2 a \sqrt [4]{x} \sqrt [4]{-b+a x^3}\right ) \text {Subst}\left (\int \frac {1}{1+\sqrt {a} x^2} \, dx,x,\frac {x^{3/4}}{\sqrt [4]{-b+a x^3}}\right )}{3 \sqrt [4]{-b x+a x^4}} \\ & = \frac {4 \left (-b x+a x^4\right )^{3/4}}{9 x^3}+\frac {2 a^{3/4} \sqrt [4]{x} \sqrt [4]{-b+a x^3} \arctan \left (\frac {\sqrt [4]{a} x^{3/4}}{\sqrt [4]{-b+a x^3}}\right )}{3 \sqrt [4]{-b x+a x^4}}+\frac {2 a^{3/4} \sqrt [4]{x} \sqrt [4]{-b+a x^3} \text {arctanh}\left (\frac {\sqrt [4]{a} x^{3/4}}{\sqrt [4]{-b+a x^3}}\right )}{3 \sqrt [4]{-b x+a x^4}} \\ \end{align*}
Time = 9.69 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.26 \[ \int \frac {b+a x^3}{x^3 \sqrt [4]{-b x+a x^4}} \, dx=\frac {-4 b+4 a x^3+6 a^{3/4} x^{9/4} \sqrt [4]{-b+a x^3} \arctan \left (\frac {\sqrt [4]{a} x^{3/4}}{\sqrt [4]{-b+a x^3}}\right )+6 a^{3/4} x^{9/4} \sqrt [4]{-b+a x^3} \text {arctanh}\left (\frac {\sqrt [4]{a} x^{3/4}}{\sqrt [4]{-b+a x^3}}\right )}{9 x^2 \sqrt [4]{-b x+a x^4}} \]
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Time = 0.28 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.98
method | result | size |
pseudoelliptic | \(\frac {-6 \arctan \left (\frac {{\left (x \left (a \,x^{3}-b \right )\right )}^{\frac {1}{4}}}{x \,a^{\frac {1}{4}}}\right ) a^{\frac {3}{4}} x^{3}+3 \ln \left (\frac {a^{\frac {1}{4}} x +{\left (x \left (a \,x^{3}-b \right )\right )}^{\frac {1}{4}}}{-a^{\frac {1}{4}} x +{\left (x \left (a \,x^{3}-b \right )\right )}^{\frac {1}{4}}}\right ) a^{\frac {3}{4}} x^{3}+4 {\left (x \left (a \,x^{3}-b \right )\right )}^{\frac {3}{4}}}{9 x^{3}}\) | \(102\) |
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Timed out. \[ \int \frac {b+a x^3}{x^3 \sqrt [4]{-b x+a x^4}} \, dx=\text {Timed out} \]
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\[ \int \frac {b+a x^3}{x^3 \sqrt [4]{-b x+a x^4}} \, dx=\int \frac {a x^{3} + b}{x^{3} \sqrt [4]{x \left (a x^{3} - b\right )}}\, dx \]
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\[ \int \frac {b+a x^3}{x^3 \sqrt [4]{-b x+a x^4}} \, dx=\int { \frac {a x^{3} + b}{{\left (a x^{4} - b x\right )}^{\frac {1}{4}} x^{3}} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 192 vs. \(2 (84) = 168\).
Time = 0.30 (sec) , antiderivative size = 192, normalized size of antiderivative = 1.85 \[ \int \frac {b+a x^3}{x^3 \sqrt [4]{-b x+a x^4}} \, dx=\frac {1}{3} \, \sqrt {2} \left (-a\right )^{\frac {3}{4}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} + 2 \, {\left (a - \frac {b}{x^{3}}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right ) + \frac {1}{3} \, \sqrt {2} \left (-a\right )^{\frac {3}{4}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} - 2 \, {\left (a - \frac {b}{x^{3}}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right ) - \frac {1}{6} \, \sqrt {2} \left (-a\right )^{\frac {3}{4}} \log \left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} {\left (a - \frac {b}{x^{3}}\right )}^{\frac {1}{4}} + \sqrt {-a} + \sqrt {a - \frac {b}{x^{3}}}\right ) + \frac {1}{6} \, \sqrt {2} \left (-a\right )^{\frac {3}{4}} \log \left (-\sqrt {2} \left (-a\right )^{\frac {1}{4}} {\left (a - \frac {b}{x^{3}}\right )}^{\frac {1}{4}} + \sqrt {-a} + \sqrt {a - \frac {b}{x^{3}}}\right ) + \frac {4}{9} \, {\left (a - \frac {b}{x^{3}}\right )}^{\frac {3}{4}} \]
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Time = 6.66 (sec) , antiderivative size = 60, normalized size of antiderivative = 0.58 \[ \int \frac {b+a x^3}{x^3 \sqrt [4]{-b x+a x^4}} \, dx=\frac {4\,{\left (a\,x^4-b\,x\right )}^{3/4}}{9\,x^3}+\frac {4\,a\,x\,{\left (1-\frac {a\,x^3}{b}\right )}^{1/4}\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{4},\frac {1}{4};\ \frac {5}{4};\ \frac {a\,x^3}{b}\right )}{3\,{\left (a\,x^4-b\,x\right )}^{1/4}} \]
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