Integrand size = 42, antiderivative size = 104 \[ \int \frac {x^4 \left (4 b+a x^5\right )}{\left (-b+a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx=\frac {x \left (-b+c x^4+a x^5\right )^{3/4}}{c \left (b-a x^5\right )}+\frac {\arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{-b+c x^4+a x^5}}\right )}{2 c^{5/4}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{-b+c x^4+a x^5}}\right )}{2 c^{5/4}} \]
[Out]
\[ \int \frac {x^4 \left (4 b+a x^5\right )}{\left (-b+a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx=\int \frac {x^4 \left (4 b+a x^5\right )}{\left (-b+a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {5 b x^4}{\left (b-a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}}+\frac {x^4}{\left (-b+a x^5\right ) \sqrt [4]{-b+c x^4+a x^5}}\right ) \, dx \\ & = (5 b) \int \frac {x^4}{\left (b-a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx+\int \frac {x^4}{\left (-b+a x^5\right ) \sqrt [4]{-b+c x^4+a x^5}} \, dx \\ & = (5 b) \int \frac {x^4}{\left (b-a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx+\int \left (-\frac {1}{5 a^{4/5} \left (\sqrt [5]{b}-\sqrt [5]{a} x\right ) \sqrt [4]{-b+c x^4+a x^5}}-\frac {1}{5 a^{4/5} \left (-\sqrt [5]{-1} \sqrt [5]{b}-\sqrt [5]{a} x\right ) \sqrt [4]{-b+c x^4+a x^5}}-\frac {1}{5 a^{4/5} \left ((-1)^{2/5} \sqrt [5]{b}-\sqrt [5]{a} x\right ) \sqrt [4]{-b+c x^4+a x^5}}-\frac {1}{5 a^{4/5} \left (-(-1)^{3/5} \sqrt [5]{b}-\sqrt [5]{a} x\right ) \sqrt [4]{-b+c x^4+a x^5}}-\frac {1}{5 a^{4/5} \left ((-1)^{4/5} \sqrt [5]{b}-\sqrt [5]{a} x\right ) \sqrt [4]{-b+c x^4+a x^5}}\right ) \, dx \\ & = -\frac {\int \frac {1}{\left (\sqrt [5]{b}-\sqrt [5]{a} x\right ) \sqrt [4]{-b+c x^4+a x^5}} \, dx}{5 a^{4/5}}-\frac {\int \frac {1}{\left (-\sqrt [5]{-1} \sqrt [5]{b}-\sqrt [5]{a} x\right ) \sqrt [4]{-b+c x^4+a x^5}} \, dx}{5 a^{4/5}}-\frac {\int \frac {1}{\left ((-1)^{2/5} \sqrt [5]{b}-\sqrt [5]{a} x\right ) \sqrt [4]{-b+c x^4+a x^5}} \, dx}{5 a^{4/5}}-\frac {\int \frac {1}{\left (-(-1)^{3/5} \sqrt [5]{b}-\sqrt [5]{a} x\right ) \sqrt [4]{-b+c x^4+a x^5}} \, dx}{5 a^{4/5}}-\frac {\int \frac {1}{\left ((-1)^{4/5} \sqrt [5]{b}-\sqrt [5]{a} x\right ) \sqrt [4]{-b+c x^4+a x^5}} \, dx}{5 a^{4/5}}+(5 b) \int \frac {x^4}{\left (b-a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx \\ \end{align*}
Time = 1.86 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.91 \[ \int \frac {x^4 \left (4 b+a x^5\right )}{\left (-b+a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx=\frac {\frac {2 \sqrt [4]{c} x \left (-b+x^4 (c+a x)\right )^{3/4}}{b-a x^5}+\arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{-b+x^4 (c+a x)}}\right )+\text {arctanh}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{-b+x^4 (c+a x)}}\right )}{2 c^{5/4}} \]
[In]
[Out]
Time = 1.06 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.26
method | result | size |
pseudoelliptic | \(-\frac {2 \left (2 \left (a \,x^{5}+c \,x^{4}-b \right )^{\frac {3}{4}} x \,c^{\frac {1}{4}}+\left (\arctan \left (\frac {\left (a \,x^{5}+c \,x^{4}-b \right )^{\frac {1}{4}}}{c^{\frac {1}{4}} x}\right )-\frac {\ln \left (\frac {-c^{\frac {1}{4}} x -\left (a \,x^{5}+c \,x^{4}-b \right )^{\frac {1}{4}}}{c^{\frac {1}{4}} x -\left (a \,x^{5}+c \,x^{4}-b \right )^{\frac {1}{4}}}\right )}{2}\right ) \left (a \,x^{5}-b \right )\right )}{c^{\frac {5}{4}} \left (4 a \,x^{5}-4 b \right )}\) | \(131\) |
[In]
[Out]
Timed out. \[ \int \frac {x^4 \left (4 b+a x^5\right )}{\left (-b+a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx=\text {Timed out} \]
[In]
[Out]
Timed out. \[ \int \frac {x^4 \left (4 b+a x^5\right )}{\left (-b+a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx=\text {Timed out} \]
[In]
[Out]
\[ \int \frac {x^4 \left (4 b+a x^5\right )}{\left (-b+a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx=\int { \frac {{\left (a x^{5} + 4 \, b\right )} x^{4}}{{\left (a x^{5} + c x^{4} - b\right )}^{\frac {1}{4}} {\left (a x^{5} - b\right )}^{2}} \,d x } \]
[In]
[Out]
\[ \int \frac {x^4 \left (4 b+a x^5\right )}{\left (-b+a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx=\int { \frac {{\left (a x^{5} + 4 \, b\right )} x^{4}}{{\left (a x^{5} + c x^{4} - b\right )}^{\frac {1}{4}} {\left (a x^{5} - b\right )}^{2}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {x^4 \left (4 b+a x^5\right )}{\left (-b+a x^5\right )^2 \sqrt [4]{-b+c x^4+a x^5}} \, dx=\int \frac {x^4\,\left (a\,x^5+4\,b\right )}{{\left (b-a\,x^5\right )}^2\,{\left (a\,x^5+c\,x^4-b\right )}^{1/4}} \,d x \]
[In]
[Out]