Integrand size = 27, antiderivative size = 105 \[ \int \frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x^2} \, dx=-\frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x}+\frac {\sqrt {a} \log \left (i a x^2+i \sqrt {b+a^2 x^4}+i \sqrt {2} \sqrt {a} x \sqrt {a x^2+\sqrt {b+a^2 x^4}}\right )}{\sqrt {2}} \]
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\[ \int \frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x^2} \, dx=\int \frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x^2} \, dx \\ \end{align*}
Time = 0.50 (sec) , antiderivative size = 99, normalized size of antiderivative = 0.94 \[ \int \frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x^2} \, dx=-\frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x}+\frac {\sqrt {a} \log \left (i \left (a x^2+\sqrt {b+a^2 x^4}+\sqrt {2} \sqrt {a} x \sqrt {a x^2+\sqrt {b+a^2 x^4}}\right )\right )}{\sqrt {2}} \]
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\[\int \frac {\sqrt {a \,x^{2}+\sqrt {a^{2} x^{4}+b}}}{x^{2}}d x\]
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Timed out. \[ \int \frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x^2} \, dx=\text {Timed out} \]
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\[ \int \frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x^2} \, dx=\int \frac {\sqrt {a x^{2} + \sqrt {a^{2} x^{4} + b}}}{x^{2}}\, dx \]
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\[ \int \frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x^2} \, dx=\int { \frac {\sqrt {a x^{2} + \sqrt {a^{2} x^{4} + b}}}{x^{2}} \,d x } \]
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\[ \int \frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x^2} \, dx=\int { \frac {\sqrt {a x^{2} + \sqrt {a^{2} x^{4} + b}}}{x^{2}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {a x^2+\sqrt {b+a^2 x^4}}}{x^2} \, dx=\int \frac {\sqrt {\sqrt {a^2\,x^4+b}+a\,x^2}}{x^2} \,d x \]
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