Integrand size = 24, antiderivative size = 110 \[ \int \frac {x^3 \sqrt {x+x^4}}{-b+a x^3} \, dx=\frac {x \sqrt {x+x^4}}{3 a}+\frac {2 \sqrt {-a-b} \sqrt {b} \arctan \left (\frac {\sqrt {-a-b} x \sqrt {x+x^4}}{\sqrt {b} (1+x) \left (1-x+x^2\right )}\right )}{3 a^2}+\frac {(a+2 b) \text {arctanh}\left (\frac {x^2}{\sqrt {x+x^4}}\right )}{3 a^2} \]
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Time = 0.15 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.17, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2067, 477, 476, 489, 537, 221, 385, 214} \[ \int \frac {x^3 \sqrt {x+x^4}}{-b+a x^3} \, dx=\frac {\sqrt {x^4+x} (a+2 b) \text {arcsinh}\left (x^{3/2}\right )}{3 a^2 \sqrt {x^3+1} \sqrt {x}}-\frac {2 \sqrt {b} \sqrt {x^4+x} \sqrt {a+b} \text {arctanh}\left (\frac {x^{3/2} \sqrt {a+b}}{\sqrt {b} \sqrt {x^3+1}}\right )}{3 a^2 \sqrt {x^3+1} \sqrt {x}}+\frac {\sqrt {x^4+x} x}{3 a} \]
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Rule 214
Rule 221
Rule 385
Rule 476
Rule 477
Rule 489
Rule 537
Rule 2067
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {x+x^4} \int \frac {x^{7/2} \sqrt {1+x^3}}{-b+a x^3} \, dx}{\sqrt {x} \sqrt {1+x^3}} \\ & = \frac {\left (2 \sqrt {x+x^4}\right ) \text {Subst}\left (\int \frac {x^8 \sqrt {1+x^6}}{-b+a x^6} \, dx,x,\sqrt {x}\right )}{\sqrt {x} \sqrt {1+x^3}} \\ & = \frac {\left (2 \sqrt {x+x^4}\right ) \text {Subst}\left (\int \frac {x^2 \sqrt {1+x^2}}{-b+a x^2} \, dx,x,x^{3/2}\right )}{3 \sqrt {x} \sqrt {1+x^3}} \\ & = \frac {x \sqrt {x+x^4}}{3 a}-\frac {\sqrt {x+x^4} \text {Subst}\left (\int \frac {-b+(-a-2 b) x^2}{\sqrt {1+x^2} \left (-b+a x^2\right )} \, dx,x,x^{3/2}\right )}{3 a \sqrt {x} \sqrt {1+x^3}} \\ & = \frac {x \sqrt {x+x^4}}{3 a}-\frac {\left ((-a-2 b) \sqrt {x+x^4}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+x^2}} \, dx,x,x^{3/2}\right )}{3 a^2 \sqrt {x} \sqrt {1+x^3}}+\frac {\left (2 b (a+b) \sqrt {x+x^4}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+x^2} \left (-b+a x^2\right )} \, dx,x,x^{3/2}\right )}{3 a^2 \sqrt {x} \sqrt {1+x^3}} \\ & = \frac {x \sqrt {x+x^4}}{3 a}+\frac {(a+2 b) \sqrt {x+x^4} \text {arcsinh}\left (x^{3/2}\right )}{3 a^2 \sqrt {x} \sqrt {1+x^3}}+\frac {\left (2 b (a+b) \sqrt {x+x^4}\right ) \text {Subst}\left (\int \frac {1}{-b-(-a-b) x^2} \, dx,x,\frac {x^{3/2}}{\sqrt {1+x^3}}\right )}{3 a^2 \sqrt {x} \sqrt {1+x^3}} \\ & = \frac {x \sqrt {x+x^4}}{3 a}+\frac {(a+2 b) \sqrt {x+x^4} \text {arcsinh}\left (x^{3/2}\right )}{3 a^2 \sqrt {x} \sqrt {1+x^3}}-\frac {2 \sqrt {b} \sqrt {a+b} \sqrt {x+x^4} \text {arctanh}\left (\frac {\sqrt {a+b} x^{3/2}}{\sqrt {b} \sqrt {1+x^3}}\right )}{3 a^2 \sqrt {x} \sqrt {1+x^3}} \\ \end{align*}
Time = 0.57 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.11 \[ \int \frac {x^3 \sqrt {x+x^4}}{-b+a x^3} \, dx=\frac {\sqrt {x+x^4} \left (a x^{3/2} \sqrt {1+x^3}+2 \sqrt {b} \sqrt {a+b} \text {arctanh}\left (\frac {b-a x^{3/2} \left (x^{3/2}+\sqrt {1+x^3}\right )}{\sqrt {b} \sqrt {a+b}}\right )+(a+2 b) \log \left (x^{3/2}+\sqrt {1+x^3}\right )\right )}{3 a^2 \sqrt {x} \sqrt {1+x^3}} \]
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Time = 1.26 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.85
method | result | size |
risch | \(\frac {x^{2} \left (x^{3}+1\right )}{3 a \sqrt {x \left (x^{3}+1\right )}}+\frac {-\frac {\left (a +2 b \right ) \ln \left (2 x^{3}-2 x \sqrt {x^{4}+x}+1\right )}{3 a}-\frac {4 \left (a +b \right ) b \,\operatorname {arctanh}\left (\frac {\sqrt {x^{4}+x}\, b}{x^{2} \sqrt {\left (a +b \right ) b}}\right )}{3 a \sqrt {\left (a +b \right ) b}}}{2 a}\) | \(94\) |
pseudoelliptic | \(-\frac {-2 \sqrt {\left (a +b \right ) b}\, \sqrt {x^{4}+x}\, a x +\left (\ln \left (\frac {-x^{2}+\sqrt {x^{4}+x}}{x^{2}}\right )-\ln \left (\frac {x^{2}+\sqrt {x^{4}+x}}{x^{2}}\right )\right ) \left (a +2 b \right ) \sqrt {\left (a +b \right ) b}+4 \left (a +b \right ) b \,\operatorname {arctanh}\left (\frac {\sqrt {x^{4}+x}\, b}{x^{2} \sqrt {\left (a +b \right ) b}}\right )}{6 \sqrt {\left (a +b \right ) b}\, a^{2}}\) | \(108\) |
default | \(\frac {\frac {x \sqrt {x^{4}+x}}{3}+\frac {\ln \left (\frac {x^{2}+\sqrt {x^{4}+x}}{x^{2}}\right )}{6}-\frac {\ln \left (\frac {-x^{2}+\sqrt {x^{4}+x}}{x^{2}}\right )}{6}}{a}+\frac {b \left (\ln \left (\frac {x^{2}+\sqrt {x \left (x^{3}+1\right )}}{x^{2}}\right )-\frac {2 \left (a +b \right ) \operatorname {arctanh}\left (\frac {\sqrt {x \left (x^{3}+1\right )}\, b}{x^{2} \sqrt {\left (a +b \right ) b}}\right )}{\sqrt {\left (a +b \right ) b}}-\ln \left (\frac {-x^{2}+\sqrt {x \left (x^{3}+1\right )}}{x^{2}}\right )\right )}{3 a^{2}}\) | \(136\) |
elliptic | \(\text {Expression too large to display}\) | \(665\) |
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Time = 1.04 (sec) , antiderivative size = 233, normalized size of antiderivative = 2.12 \[ \int \frac {x^3 \sqrt {x+x^4}}{-b+a x^3} \, dx=\left [\frac {2 \, \sqrt {x^{4} + x} a x + {\left (a + 2 \, b\right )} \log \left (-2 \, x^{3} - 2 \, \sqrt {x^{4} + x} x - 1\right ) + \sqrt {a b + b^{2}} \log \left (-\frac {{\left (a^{2} + 8 \, a b + 8 \, b^{2}\right )} x^{6} + 2 \, {\left (3 \, a b + 4 \, b^{2}\right )} x^{3} - 4 \, {\left ({\left (a + 2 \, b\right )} x^{4} + b x\right )} \sqrt {x^{4} + x} \sqrt {a b + b^{2}} + b^{2}}{a^{2} x^{6} - 2 \, a b x^{3} + b^{2}}\right )}{6 \, a^{2}}, \frac {2 \, \sqrt {x^{4} + x} a x + {\left (a + 2 \, b\right )} \log \left (-2 \, x^{3} - 2 \, \sqrt {x^{4} + x} x - 1\right ) + 2 \, \sqrt {-a b - b^{2}} \arctan \left (\frac {2 \, \sqrt {x^{4} + x} \sqrt {-a b - b^{2}} x}{{\left (a + 2 \, b\right )} x^{3} + b}\right )}{6 \, a^{2}}\right ] \]
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\[ \int \frac {x^3 \sqrt {x+x^4}}{-b+a x^3} \, dx=\int \frac {x^{3} \sqrt {x \left (x + 1\right ) \left (x^{2} - x + 1\right )}}{a x^{3} - b}\, dx \]
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\[ \int \frac {x^3 \sqrt {x+x^4}}{-b+a x^3} \, dx=\int { \frac {\sqrt {x^{4} + x} x^{3}}{a x^{3} - b} \,d x } \]
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Time = 0.36 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.92 \[ \int \frac {x^3 \sqrt {x+x^4}}{-b+a x^3} \, dx=\frac {\sqrt {x^{4} + x} x}{3 \, a} + \frac {{\left (a + 2 \, b\right )} \log \left (\sqrt {\frac {1}{x^{3}} + 1} + 1\right )}{6 \, a^{2}} - \frac {{\left (a + 2 \, b\right )} \log \left ({\left | \sqrt {\frac {1}{x^{3}} + 1} - 1 \right |}\right )}{6 \, a^{2}} + \frac {2 \, {\left (a b + b^{2}\right )} \arctan \left (\frac {b \sqrt {\frac {1}{x^{3}} + 1}}{\sqrt {-a b - b^{2}}}\right )}{3 \, \sqrt {-a b - b^{2}} a^{2}} \]
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Timed out. \[ \int \frac {x^3 \sqrt {x+x^4}}{-b+a x^3} \, dx=-\int \frac {x^3\,\sqrt {x^4+x}}{b-a\,x^3} \,d x \]
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