Integrand size = 39, antiderivative size = 110 \[ \int \frac {-3 b+2 a x^5}{\left (2 b+x^3+2 a x^5\right ) \sqrt [4]{b x+a x^6}} \, dx=-\frac {\arctan \left (\frac {2^{3/4} x \sqrt [4]{b x+a x^6}}{-x^2+\sqrt {2} \sqrt {b x+a x^6}}\right )}{\sqrt [4]{2}}-\frac {\text {arctanh}\left (\frac {\frac {x^2}{2^{3/4}}+\frac {\sqrt {b x+a x^6}}{\sqrt [4]{2}}}{x \sqrt [4]{b x+a x^6}}\right )}{\sqrt [4]{2}} \]
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\[ \int \frac {-3 b+2 a x^5}{\left (2 b+x^3+2 a x^5\right ) \sqrt [4]{b x+a x^6}} \, dx=\int \frac {-3 b+2 a x^5}{\left (2 b+x^3+2 a x^5\right ) \sqrt [4]{b x+a x^6}} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {\left (\sqrt [4]{x} \sqrt [4]{b+a x^5}\right ) \int \frac {-3 b+2 a x^5}{\sqrt [4]{x} \sqrt [4]{b+a x^5} \left (2 b+x^3+2 a x^5\right )} \, dx}{\sqrt [4]{b x+a x^6}} \\ & = \frac {\left (4 \sqrt [4]{x} \sqrt [4]{b+a x^5}\right ) \text {Subst}\left (\int \frac {x^2 \left (-3 b+2 a x^{20}\right )}{\sqrt [4]{b+a x^{20}} \left (2 b+x^{12}+2 a x^{20}\right )} \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{b x+a x^6}} \\ & = \frac {\left (4 \sqrt [4]{x} \sqrt [4]{b+a x^5}\right ) \text {Subst}\left (\int \left (\frac {x^2}{\sqrt [4]{b+a x^{20}}}+\frac {x^2 \left (-5 b-x^{12}\right )}{\sqrt [4]{b+a x^{20}} \left (2 b+x^{12}+2 a x^{20}\right )}\right ) \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{b x+a x^6}} \\ & = \frac {\left (4 \sqrt [4]{x} \sqrt [4]{b+a x^5}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt [4]{b+a x^{20}}} \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{b x+a x^6}}+\frac {\left (4 \sqrt [4]{x} \sqrt [4]{b+a x^5}\right ) \text {Subst}\left (\int \frac {x^2 \left (-5 b-x^{12}\right )}{\sqrt [4]{b+a x^{20}} \left (2 b+x^{12}+2 a x^{20}\right )} \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{b x+a x^6}} \\ & = \frac {\left (4 \sqrt [4]{x} \sqrt [4]{b+a x^5}\right ) \text {Subst}\left (\int \left (-\frac {5 b x^2}{\sqrt [4]{b+a x^{20}} \left (2 b+x^{12}+2 a x^{20}\right )}-\frac {x^{14}}{\sqrt [4]{b+a x^{20}} \left (2 b+x^{12}+2 a x^{20}\right )}\right ) \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{b x+a x^6}}+\frac {\left (4 \sqrt [4]{x} \sqrt [4]{1+\frac {a x^5}{b}}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt [4]{1+\frac {a x^{20}}{b}}} \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{b x+a x^6}} \\ & = \frac {4 x \sqrt [4]{1+\frac {a x^5}{b}} \operatorname {Hypergeometric2F1}\left (\frac {3}{20},\frac {1}{4},\frac {23}{20},-\frac {a x^5}{b}\right )}{3 \sqrt [4]{b x+a x^6}}-\frac {\left (4 \sqrt [4]{x} \sqrt [4]{b+a x^5}\right ) \text {Subst}\left (\int \frac {x^{14}}{\sqrt [4]{b+a x^{20}} \left (2 b+x^{12}+2 a x^{20}\right )} \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{b x+a x^6}}-\frac {\left (20 b \sqrt [4]{x} \sqrt [4]{b+a x^5}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt [4]{b+a x^{20}} \left (2 b+x^{12}+2 a x^{20}\right )} \, dx,x,\sqrt [4]{x}\right )}{\sqrt [4]{b x+a x^6}} \\ \end{align*}
\[ \int \frac {-3 b+2 a x^5}{\left (2 b+x^3+2 a x^5\right ) \sqrt [4]{b x+a x^6}} \, dx=\int \frac {-3 b+2 a x^5}{\left (2 b+x^3+2 a x^5\right ) \sqrt [4]{b x+a x^6}} \, dx \]
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Time = 1.09 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.25
method | result | size |
pseudoelliptic | \(\frac {2^{\frac {3}{4}} \left (\ln \left (\frac {-2 \,2^{\frac {1}{4}} {\left (x \left (a \,x^{5}+b \right )\right )}^{\frac {1}{4}} x +\sqrt {2}\, x^{2}+2 \sqrt {x \left (a \,x^{5}+b \right )}}{2 \,2^{\frac {1}{4}} {\left (x \left (a \,x^{5}+b \right )\right )}^{\frac {1}{4}} x +\sqrt {2}\, x^{2}+2 \sqrt {x \left (a \,x^{5}+b \right )}}\right )+2 \arctan \left (\frac {{\left (x \left (a \,x^{5}+b \right )\right )}^{\frac {1}{4}} 2^{\frac {3}{4}}+x}{x}\right )+2 \arctan \left (\frac {{\left (x \left (a \,x^{5}+b \right )\right )}^{\frac {1}{4}} 2^{\frac {3}{4}}-x}{x}\right )\right )}{4}\) | \(137\) |
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Timed out. \[ \int \frac {-3 b+2 a x^5}{\left (2 b+x^3+2 a x^5\right ) \sqrt [4]{b x+a x^6}} \, dx=\text {Timed out} \]
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\[ \int \frac {-3 b+2 a x^5}{\left (2 b+x^3+2 a x^5\right ) \sqrt [4]{b x+a x^6}} \, dx=\int \frac {2 a x^{5} - 3 b}{\sqrt [4]{x \left (a x^{5} + b\right )} \left (2 a x^{5} + 2 b + x^{3}\right )}\, dx \]
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\[ \int \frac {-3 b+2 a x^5}{\left (2 b+x^3+2 a x^5\right ) \sqrt [4]{b x+a x^6}} \, dx=\int { \frac {2 \, a x^{5} - 3 \, b}{{\left (a x^{6} + b x\right )}^{\frac {1}{4}} {\left (2 \, a x^{5} + x^{3} + 2 \, b\right )}} \,d x } \]
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\[ \int \frac {-3 b+2 a x^5}{\left (2 b+x^3+2 a x^5\right ) \sqrt [4]{b x+a x^6}} \, dx=\int { \frac {2 \, a x^{5} - 3 \, b}{{\left (a x^{6} + b x\right )}^{\frac {1}{4}} {\left (2 \, a x^{5} + x^{3} + 2 \, b\right )}} \,d x } \]
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Timed out. \[ \int \frac {-3 b+2 a x^5}{\left (2 b+x^3+2 a x^5\right ) \sqrt [4]{b x+a x^6}} \, dx=\int -\frac {3\,b-2\,a\,x^5}{{\left (a\,x^6+b\,x\right )}^{1/4}\,\left (2\,a\,x^5+x^3+2\,b\right )} \,d x \]
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