Integrand size = 45, antiderivative size = 119 \[ \int \frac {\left (-q+p x^2\right ) \sqrt {q^2+p^2 x^4} \left (b x^3+a \left (q+p x^2\right )^3\right )}{x^6} \, dx=\frac {\sqrt {q^2+p^2 x^4} \left (6 a q^4+20 a p q^3 x^2+15 b q x^3+12 a p^2 q^2 x^4+15 b p x^5+20 a p^3 q x^6+6 a p^4 x^8\right )}{30 x^5}+b p q \log (x)-b p q \log \left (q+p x^2+\sqrt {q^2+p^2 x^4}\right ) \]
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Time = 0.29 (sec) , antiderivative size = 163, normalized size of antiderivative = 1.37, number of steps used = 16, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.289, Rules used = {1847, 1598, 1266, 827, 858, 223, 212, 272, 65, 214, 1849, 1600, 460} \[ \int \frac {\left (-q+p x^2\right ) \sqrt {q^2+p^2 x^4} \left (b x^3+a \left (q+p x^2\right )^3\right )}{x^6} \, dx=\frac {a p^2 \left (p^2 x^4+q^2\right )^{3/2}}{5 x}+\frac {a q^2 \left (p^2 x^4+q^2\right )^{3/2}}{5 x^5}+\frac {2 a p q \left (p^2 x^4+q^2\right )^{3/2}}{3 x^3}-\frac {1}{2} b p q \text {arctanh}\left (\frac {\sqrt {p^2 x^4+q^2}}{q}\right )-\frac {1}{2} b p q \text {arctanh}\left (\frac {p x^2}{\sqrt {p^2 x^4+q^2}}\right )+\frac {b \left (p x^2+q\right ) \sqrt {p^2 x^4+q^2}}{2 x^2} \]
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Rule 65
Rule 212
Rule 214
Rule 223
Rule 272
Rule 460
Rule 827
Rule 858
Rule 1266
Rule 1598
Rule 1600
Rule 1847
Rule 1849
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\left (-b q x^2+b p x^4\right ) \sqrt {q^2+p^2 x^4}}{x^5}+\frac {\sqrt {q^2+p^2 x^4} \left (-a q^4-2 a p q^3 x^2+2 a p^3 q x^6+a p^4 x^8\right )}{x^6}\right ) \, dx \\ & = \int \frac {\left (-b q x^2+b p x^4\right ) \sqrt {q^2+p^2 x^4}}{x^5} \, dx+\int \frac {\sqrt {q^2+p^2 x^4} \left (-a q^4-2 a p q^3 x^2+2 a p^3 q x^6+a p^4 x^8\right )}{x^6} \, dx \\ & = \frac {a q^2 \left (q^2+p^2 x^4\right )^{3/2}}{5 x^5}-\frac {\int \frac {\sqrt {q^2+p^2 x^4} \left (20 a p q^5 x+2 a p^2 q^4 x^3-20 a p^3 q^3 x^5-10 a p^4 q^2 x^7\right )}{x^5} \, dx}{10 q^2}+\int \frac {\left (-b q+b p x^2\right ) \sqrt {q^2+p^2 x^4}}{x^3} \, dx \\ & = \frac {a q^2 \left (q^2+p^2 x^4\right )^{3/2}}{5 x^5}+\frac {1}{2} \text {Subst}\left (\int \frac {(-b q+b p x) \sqrt {q^2+p^2 x^2}}{x^2} \, dx,x,x^2\right )-\frac {\int \frac {\sqrt {q^2+p^2 x^4} \left (20 a p q^5+2 a p^2 q^4 x^2-20 a p^3 q^3 x^4-10 a p^4 q^2 x^6\right )}{x^4} \, dx}{10 q^2} \\ & = \frac {b \left (q+p x^2\right ) \sqrt {q^2+p^2 x^4}}{2 x^2}+\frac {a q^2 \left (q^2+p^2 x^4\right )^{3/2}}{5 x^5}+\frac {2 a p q \left (q^2+p^2 x^4\right )^{3/2}}{3 x^3}-\frac {1}{4} \text {Subst}\left (\int \frac {-2 b p q^2+2 b p^2 q x}{x \sqrt {q^2+p^2 x^2}} \, dx,x,x^2\right )+\frac {\int \frac {\sqrt {q^2+p^2 x^4} \left (-12 a p^2 q^6 x+60 a p^4 q^4 x^5\right )}{x^3} \, dx}{60 q^4} \\ & = \frac {b \left (q+p x^2\right ) \sqrt {q^2+p^2 x^4}}{2 x^2}+\frac {a q^2 \left (q^2+p^2 x^4\right )^{3/2}}{5 x^5}+\frac {2 a p q \left (q^2+p^2 x^4\right )^{3/2}}{3 x^3}+\frac {\int \frac {\sqrt {q^2+p^2 x^4} \left (-12 a p^2 q^6+60 a p^4 q^4 x^4\right )}{x^2} \, dx}{60 q^4}-\frac {1}{2} \left (b p^2 q\right ) \text {Subst}\left (\int \frac {1}{\sqrt {q^2+p^2 x^2}} \, dx,x,x^2\right )+\frac {1}{2} \left (b p q^2\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {q^2+p^2 x^2}} \, dx,x,x^2\right ) \\ & = \frac {b \left (q+p x^2\right ) \sqrt {q^2+p^2 x^4}}{2 x^2}+\frac {a q^2 \left (q^2+p^2 x^4\right )^{3/2}}{5 x^5}+\frac {2 a p q \left (q^2+p^2 x^4\right )^{3/2}}{3 x^3}+\frac {a p^2 \left (q^2+p^2 x^4\right )^{3/2}}{5 x}-\frac {1}{2} \left (b p^2 q\right ) \text {Subst}\left (\int \frac {1}{1-p^2 x^2} \, dx,x,\frac {x^2}{\sqrt {q^2+p^2 x^4}}\right )+\frac {1}{4} \left (b p q^2\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {q^2+p^2 x}} \, dx,x,x^4\right ) \\ & = \frac {b \left (q+p x^2\right ) \sqrt {q^2+p^2 x^4}}{2 x^2}+\frac {a q^2 \left (q^2+p^2 x^4\right )^{3/2}}{5 x^5}+\frac {2 a p q \left (q^2+p^2 x^4\right )^{3/2}}{3 x^3}+\frac {a p^2 \left (q^2+p^2 x^4\right )^{3/2}}{5 x}-\frac {1}{2} b p q \text {arctanh}\left (\frac {p x^2}{\sqrt {q^2+p^2 x^4}}\right )+\frac {\left (b q^2\right ) \text {Subst}\left (\int \frac {1}{-\frac {q^2}{p^2}+\frac {x^2}{p^2}} \, dx,x,\sqrt {q^2+p^2 x^4}\right )}{2 p} \\ & = \frac {b \left (q+p x^2\right ) \sqrt {q^2+p^2 x^4}}{2 x^2}+\frac {a q^2 \left (q^2+p^2 x^4\right )^{3/2}}{5 x^5}+\frac {2 a p q \left (q^2+p^2 x^4\right )^{3/2}}{3 x^3}+\frac {a p^2 \left (q^2+p^2 x^4\right )^{3/2}}{5 x}-\frac {1}{2} b p q \text {arctanh}\left (\frac {p x^2}{\sqrt {q^2+p^2 x^4}}\right )-\frac {1}{2} b p q \text {arctanh}\left (\frac {\sqrt {q^2+p^2 x^4}}{q}\right ) \\ \end{align*}
Time = 2.35 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.00 \[ \int \frac {\left (-q+p x^2\right ) \sqrt {q^2+p^2 x^4} \left (b x^3+a \left (q+p x^2\right )^3\right )}{x^6} \, dx=\frac {\sqrt {q^2+p^2 x^4} \left (6 a q^4+20 a p q^3 x^2+15 b q x^3+12 a p^2 q^2 x^4+15 b p x^5+20 a p^3 q x^6+6 a p^4 x^8\right )}{30 x^5}+b p q \log (x)-b p q \log \left (q+p x^2+\sqrt {q^2+p^2 x^4}\right ) \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 3.86 (sec) , antiderivative size = 120, normalized size of antiderivative = 1.01
method | result | size |
pseudoelliptic | \(\frac {-5 b p q \ln \left (\frac {\sqrt {p^{2} x^{4}+q^{2}}+\left (p \,x^{2}+q \right ) \operatorname {csgn}\left (p \right )}{x}\right ) \operatorname {csgn}\left (p \right ) x^{5}+\sqrt {p^{2} x^{4}+q^{2}}\, \left (a \,p^{4} x^{8}+\frac {10}{3} a \,p^{3} q \,x^{6}+2 a \,p^{2} q^{2} x^{4}+\frac {10}{3} a p \,q^{3} x^{2}+\frac {5}{2} b p \,x^{5}+a \,q^{4}+\frac {5}{2} b q \,x^{3}\right )}{5 x^{5}}\) | \(120\) |
elliptic | \(\frac {b \left (p \sqrt {p^{2} x^{4}+q^{2}}-\frac {p^{2} q \ln \left (\frac {p^{2} x^{2}}{\sqrt {p^{2}}}+\sqrt {p^{2} x^{4}+q^{2}}\right )}{\sqrt {p^{2}}}+\frac {q \sqrt {p^{2} x^{4}+q^{2}}}{x^{2}}-\frac {p \,q^{2} \ln \left (\frac {2 q^{2}+2 \sqrt {q^{2}}\, \sqrt {p^{2} x^{4}+q^{2}}}{x^{2}}\right )}{\sqrt {q^{2}}}\right )}{2}+4 a \left (\frac {p q \left (p^{2} x^{4}+q^{2}\right )^{\frac {3}{2}} \sqrt {2}}{12 x^{3}}+\frac {\left (p^{2} x^{4}+q^{2}\right )^{\frac {5}{2}} \sqrt {2}}{40 x^{5}}\right ) \sqrt {2}\) | \(170\) |
risch | \(\frac {q \sqrt {p^{2} x^{4}+q^{2}}\, \left (12 a \,p^{2} q \,x^{4}+20 a p \,q^{2} x^{2}+6 a \,q^{3}+15 b \,x^{3}\right )}{30 x^{5}}+\frac {a \,p^{4} x^{3} \sqrt {p^{2} x^{4}+q^{2}}}{5}+\frac {p b \sqrt {p^{2} x^{4}+q^{2}}}{2}-\frac {p b \,q^{2} \ln \left (\frac {2 q^{2}+2 \sqrt {q^{2}}\, \sqrt {p^{2} x^{4}+q^{2}}}{x^{2}}\right )}{2 \sqrt {q^{2}}}+\frac {2 a \,p^{3} q x \sqrt {p^{2} x^{4}+q^{2}}}{3}-\frac {q b \,p^{2} \ln \left (\frac {p^{2} x^{2}}{\sqrt {p^{2}}}+\sqrt {p^{2} x^{4}+q^{2}}\right )}{2 \sqrt {p^{2}}}\) | \(196\) |
default | \(a \,p^{4} \left (\frac {x^{3} \sqrt {p^{2} x^{4}+q^{2}}}{5}+\frac {2 i q^{3} \sqrt {1-\frac {i p \,x^{2}}{q}}\, \sqrt {1+\frac {i p \,x^{2}}{q}}\, \left (\operatorname {EllipticF}\left (x \sqrt {\frac {i p}{q}}, i\right )-\operatorname {EllipticE}\left (x \sqrt {\frac {i p}{q}}, i\right )\right )}{5 \sqrt {\frac {i p}{q}}\, \sqrt {p^{2} x^{4}+q^{2}}\, p}\right )+p b \left (\frac {\sqrt {p^{2} x^{4}+q^{2}}}{2}-\frac {q^{2} \ln \left (\frac {2 q^{2}+2 \sqrt {q^{2}}\, \sqrt {p^{2} x^{4}+q^{2}}}{x^{2}}\right )}{2 \sqrt {q^{2}}}\right )+2 q a \,p^{3} \left (\frac {x \sqrt {p^{2} x^{4}+q^{2}}}{3}+\frac {2 q^{2} \sqrt {1-\frac {i p \,x^{2}}{q}}\, \sqrt {1+\frac {i p \,x^{2}}{q}}\, \operatorname {EllipticF}\left (x \sqrt {\frac {i p}{q}}, i\right )}{3 \sqrt {\frac {i p}{q}}\, \sqrt {p^{2} x^{4}+q^{2}}}\right )-q b \left (-\frac {\left (p^{2} x^{4}+q^{2}\right )^{\frac {3}{2}}}{2 q^{2} x^{2}}+\frac {p^{2} x^{2} \sqrt {p^{2} x^{4}+q^{2}}}{2 q^{2}}+\frac {p^{2} \ln \left (\frac {p^{2} x^{2}}{\sqrt {p^{2}}}+\sqrt {p^{2} x^{4}+q^{2}}\right )}{2 \sqrt {p^{2}}}\right )-a \,q^{4} \left (-\frac {\sqrt {p^{2} x^{4}+q^{2}}}{5 x^{5}}-\frac {2 p^{2} \sqrt {p^{2} x^{4}+q^{2}}}{5 q^{2} x}+\frac {2 i p^{3} \sqrt {1-\frac {i p \,x^{2}}{q}}\, \sqrt {1+\frac {i p \,x^{2}}{q}}\, \left (\operatorname {EllipticF}\left (x \sqrt {\frac {i p}{q}}, i\right )-\operatorname {EllipticE}\left (x \sqrt {\frac {i p}{q}}, i\right )\right )}{5 q \sqrt {\frac {i p}{q}}\, \sqrt {p^{2} x^{4}+q^{2}}}\right )-2 q^{3} a p \left (-\frac {\sqrt {p^{2} x^{4}+q^{2}}}{3 x^{3}}+\frac {2 p^{2} \sqrt {1-\frac {i p \,x^{2}}{q}}\, \sqrt {1+\frac {i p \,x^{2}}{q}}\, \operatorname {EllipticF}\left (x \sqrt {\frac {i p}{q}}, i\right )}{3 \sqrt {\frac {i p}{q}}\, \sqrt {p^{2} x^{4}+q^{2}}}\right )\) | \(590\) |
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Time = 0.43 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.98 \[ \int \frac {\left (-q+p x^2\right ) \sqrt {q^2+p^2 x^4} \left (b x^3+a \left (q+p x^2\right )^3\right )}{x^6} \, dx=\frac {30 \, b p q x^{5} \log \left (\frac {p x^{2} + q - \sqrt {p^{2} x^{4} + q^{2}}}{x}\right ) + {\left (6 \, a p^{4} x^{8} + 20 \, a p^{3} q x^{6} + 12 \, a p^{2} q^{2} x^{4} + 20 \, a p q^{3} x^{2} + 15 \, b p x^{5} + 6 \, a q^{4} + 15 \, b q x^{3}\right )} \sqrt {p^{2} x^{4} + q^{2}}}{30 \, x^{5}} \]
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Result contains complex when optimal does not.
Time = 3.76 (sec) , antiderivative size = 323, normalized size of antiderivative = 2.71 \[ \int \frac {\left (-q+p x^2\right ) \sqrt {q^2+p^2 x^4} \left (b x^3+a \left (q+p x^2\right )^3\right )}{x^6} \, dx=\frac {a p^{4} q x^{3} \Gamma \left (\frac {3}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {3}{4} \\ \frac {7}{4} \end {matrix}\middle | {\frac {p^{2} x^{4} e^{i \pi }}{q^{2}}} \right )}}{4 \Gamma \left (\frac {7}{4}\right )} + \frac {a p^{3} q^{2} x \Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {1}{4} \\ \frac {5}{4} \end {matrix}\middle | {\frac {p^{2} x^{4} e^{i \pi }}{q^{2}}} \right )}}{2 \Gamma \left (\frac {5}{4}\right )} - \frac {a p q^{4} \Gamma \left (- \frac {3}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {3}{4}, - \frac {1}{2} \\ \frac {1}{4} \end {matrix}\middle | {\frac {p^{2} x^{4} e^{i \pi }}{q^{2}}} \right )}}{2 x^{3} \Gamma \left (\frac {1}{4}\right )} - \frac {a q^{5} \Gamma \left (- \frac {5}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {5}{4}, - \frac {1}{2} \\ - \frac {1}{4} \end {matrix}\middle | {\frac {p^{2} x^{4} e^{i \pi }}{q^{2}}} \right )}}{4 x^{5} \Gamma \left (- \frac {1}{4}\right )} + \frac {b p^{2} x^{2}}{2 \sqrt {\frac {p^{2} x^{4}}{q^{2}} + 1}} + \frac {b p^{2} x^{2}}{2 \sqrt {1 + \frac {q^{2}}{p^{2} x^{4}}}} - \frac {b p q \operatorname {asinh}{\left (\frac {q}{p x^{2}} \right )}}{2} - \frac {b p q \operatorname {asinh}{\left (\frac {p x^{2}}{q} \right )}}{2} + \frac {b q^{2}}{2 x^{2} \sqrt {\frac {p^{2} x^{4}}{q^{2}} + 1}} + \frac {b q^{2}}{2 x^{2} \sqrt {1 + \frac {q^{2}}{p^{2} x^{4}}}} \]
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\[ \int \frac {\left (-q+p x^2\right ) \sqrt {q^2+p^2 x^4} \left (b x^3+a \left (q+p x^2\right )^3\right )}{x^6} \, dx=\int { \frac {\sqrt {p^{2} x^{4} + q^{2}} {\left ({\left (p x^{2} + q\right )}^{3} a + b x^{3}\right )} {\left (p x^{2} - q\right )}}{x^{6}} \,d x } \]
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\[ \int \frac {\left (-q+p x^2\right ) \sqrt {q^2+p^2 x^4} \left (b x^3+a \left (q+p x^2\right )^3\right )}{x^6} \, dx=\int { \frac {\sqrt {p^{2} x^{4} + q^{2}} {\left ({\left (p x^{2} + q\right )}^{3} a + b x^{3}\right )} {\left (p x^{2} - q\right )}}{x^{6}} \,d x } \]
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Timed out. \[ \int \frac {\left (-q+p x^2\right ) \sqrt {q^2+p^2 x^4} \left (b x^3+a \left (q+p x^2\right )^3\right )}{x^6} \, dx=-\int \frac {\sqrt {p^2\,x^4+q^2}\,\left (q-p\,x^2\right )\,\left (a\,{\left (p\,x^2+q\right )}^3+b\,x^3\right )}{x^6} \,d x \]
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