Integrand size = 18, antiderivative size = 125 \[ \int \frac {1}{(-1+x) \sqrt [3]{-3-2 x+x^2}} \, dx=-\frac {\sqrt {3} \arctan \left (\frac {1}{\sqrt {3}}-\frac {\sqrt [3]{2} \sqrt [3]{-3-2 x+x^2}}{\sqrt {3}}\right )}{2\ 2^{2/3}}-\frac {\log \left (2+\sqrt [3]{2} \sqrt [3]{-3-2 x+x^2}\right )}{2\ 2^{2/3}}+\frac {\log \left (4-2 \sqrt [3]{2} \sqrt [3]{-3-2 x+x^2}+2^{2/3} \left (-3-2 x+x^2\right )^{2/3}\right )}{4\ 2^{2/3}} \]
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Time = 0.04 (sec) , antiderivative size = 84, normalized size of antiderivative = 0.67, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {708, 272, 58, 631, 210, 31} \[ \int \frac {1}{(-1+x) \sqrt [3]{-3-2 x+x^2}} \, dx=-\frac {\sqrt {3} \arctan \left (\frac {1-\sqrt [3]{2} \sqrt [3]{(x-1)^2-4}}{\sqrt {3}}\right )}{2\ 2^{2/3}}-\frac {3 \log \left (\sqrt [3]{(x-1)^2-4}+2^{2/3}\right )}{4\ 2^{2/3}}+\frac {\log (1-x)}{2\ 2^{2/3}} \]
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Rule 31
Rule 58
Rule 210
Rule 272
Rule 631
Rule 708
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {1}{x \sqrt [3]{-4+x^2}} \, dx,x,-1+x\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \frac {1}{\sqrt [3]{-4+x} x} \, dx,x,(-1+x)^2\right ) \\ & = \frac {\log (1-x)}{2\ 2^{2/3}}+\frac {3}{4} \text {Subst}\left (\int \frac {1}{2 \sqrt [3]{2}-2^{2/3} x+x^2} \, dx,x,\sqrt [3]{-4+(-1+x)^2}\right )-\frac {3 \text {Subst}\left (\int \frac {1}{2^{2/3}+x} \, dx,x,\sqrt [3]{-4+(-1+x)^2}\right )}{4\ 2^{2/3}} \\ & = -\frac {3 \log \left (2^{2/3}+\sqrt [3]{-4+(-1+x)^2}\right )}{4\ 2^{2/3}}+\frac {\log (1-x)}{2\ 2^{2/3}}+\frac {3 \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1-\sqrt [3]{2} \sqrt [3]{-4+(-1+x)^2}\right )}{2\ 2^{2/3}} \\ & = -\frac {\sqrt {3} \arctan \left (\frac {1-\sqrt [3]{2} \sqrt [3]{-4+(-1+x)^2}}{\sqrt {3}}\right )}{2\ 2^{2/3}}-\frac {3 \log \left (2^{2/3}+\sqrt [3]{-4+(-1+x)^2}\right )}{4\ 2^{2/3}}+\frac {\log (1-x)}{2\ 2^{2/3}} \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.86 \[ \int \frac {1}{(-1+x) \sqrt [3]{-3-2 x+x^2}} \, dx=\frac {-2 \sqrt {3} \arctan \left (\frac {1-\sqrt [3]{2} \sqrt [3]{-3-2 x+x^2}}{\sqrt {3}}\right )-2 \log \left (2+\sqrt [3]{2} \sqrt [3]{-3-2 x+x^2}\right )+\log \left (4-2 \sqrt [3]{2} \sqrt [3]{-3-2 x+x^2}+2^{2/3} \left (-3-2 x+x^2\right )^{2/3}\right )}{4\ 2^{2/3}} \]
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Time = 6.25 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.66
method | result | size |
pseudoelliptic | \(\frac {2^{\frac {1}{3}} \left (2 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (2^{\frac {1}{3}} \left (x^{2}-2 x -3\right )^{\frac {1}{3}}-1\right )}{3}\right )-2 \ln \left (\left (x^{2}-2 x -3\right )^{\frac {1}{3}}+2^{\frac {2}{3}}\right )+\ln \left (\left (x^{2}-2 x -3\right )^{\frac {2}{3}}-2^{\frac {2}{3}} \left (x^{2}-2 x -3\right )^{\frac {1}{3}}+2 \,2^{\frac {1}{3}}\right )\right )}{8}\) | \(83\) |
trager | \(\text {Expression too large to display}\) | \(1199\) |
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Time = 0.26 (sec) , antiderivative size = 113, normalized size of antiderivative = 0.90 \[ \int \frac {1}{(-1+x) \sqrt [3]{-3-2 x+x^2}} \, dx=\frac {1}{4} \cdot 4^{\frac {1}{6}} \sqrt {3} \left (-1\right )^{\frac {1}{3}} \arctan \left (\frac {1}{6} \cdot 4^{\frac {1}{6}} \sqrt {3} {\left (2 \, \left (-1\right )^{\frac {1}{3}} {\left (x^{2} - 2 \, x - 3\right )}^{\frac {1}{3}} + 4^{\frac {1}{3}}\right )}\right ) - \frac {1}{16} \cdot 4^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} \log \left (-4^{\frac {1}{3}} \left (-1\right )^{\frac {2}{3}} {\left (x^{2} - 2 \, x - 3\right )}^{\frac {1}{3}} - 4^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} + {\left (x^{2} - 2 \, x - 3\right )}^{\frac {2}{3}}\right ) + \frac {1}{8} \cdot 4^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} \log \left (4^{\frac {1}{3}} \left (-1\right )^{\frac {2}{3}} + {\left (x^{2} - 2 \, x - 3\right )}^{\frac {1}{3}}\right ) \]
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\[ \int \frac {1}{(-1+x) \sqrt [3]{-3-2 x+x^2}} \, dx=\int \frac {1}{\sqrt [3]{\left (x - 3\right ) \left (x + 1\right )} \left (x - 1\right )}\, dx \]
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\[ \int \frac {1}{(-1+x) \sqrt [3]{-3-2 x+x^2}} \, dx=\int { \frac {1}{{\left (x^{2} - 2 \, x - 3\right )}^{\frac {1}{3}} {\left (x - 1\right )}} \,d x } \]
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\[ \int \frac {1}{(-1+x) \sqrt [3]{-3-2 x+x^2}} \, dx=\int { \frac {1}{{\left (x^{2} - 2 \, x - 3\right )}^{\frac {1}{3}} {\left (x - 1\right )}} \,d x } \]
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Timed out. \[ \int \frac {1}{(-1+x) \sqrt [3]{-3-2 x+x^2}} \, dx=\int \frac {1}{\left (x-1\right )\,{\left (x^2-2\,x-3\right )}^{1/3}} \,d x \]
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