Integrand size = 23, antiderivative size = 125 \[ \int \frac {1-2 x+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx=\frac {2}{3} \left (-1+x^4\right )^{3/4}+\arctan \left (\frac {\sqrt [4]{-1+x^4}}{x}\right )+\frac {\arctan \left (\frac {-\frac {1}{\sqrt {2}}+\frac {\sqrt {-1+x^4}}{\sqrt {2}}}{\sqrt [4]{-1+x^4}}\right )}{2 \sqrt {2}}-\text {arctanh}\left (\frac {\sqrt [4]{-1+x^4}}{x}\right )-\frac {\text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{-1+x^4}}{1+\sqrt {-1+x^4}}\right )}{2 \sqrt {2}} \]
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Time = 0.09 (sec) , antiderivative size = 170, normalized size of antiderivative = 1.36, number of steps used = 18, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.609, Rules used = {1847, 246, 218, 212, 209, 457, 81, 65, 303, 1176, 631, 210, 1179, 642} \[ \int \frac {1-2 x+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx=-\arctan \left (\frac {x}{\sqrt [4]{x^4-1}}\right )-\frac {\arctan \left (1-\sqrt {2} \sqrt [4]{x^4-1}\right )}{2 \sqrt {2}}+\frac {\arctan \left (\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{2 \sqrt {2}}-\text {arctanh}\left (\frac {x}{\sqrt [4]{x^4-1}}\right )+\frac {2}{3} \left (x^4-1\right )^{3/4}+\frac {\log \left (\sqrt {x^4-1}-\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{4 \sqrt {2}}-\frac {\log \left (\sqrt {x^4-1}+\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{4 \sqrt {2}} \]
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Rule 65
Rule 81
Rule 209
Rule 210
Rule 212
Rule 218
Rule 246
Rule 303
Rule 457
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 1847
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {2}{\sqrt [4]{-1+x^4}}+\frac {1+2 x^4}{x \sqrt [4]{-1+x^4}}\right ) \, dx \\ & = -\left (2 \int \frac {1}{\sqrt [4]{-1+x^4}} \, dx\right )+\int \frac {1+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx \\ & = \frac {1}{4} \text {Subst}\left (\int \frac {1+2 x}{\sqrt [4]{-1+x} x} \, dx,x,x^4\right )-2 \text {Subst}\left (\int \frac {1}{1-x^4} \, dx,x,\frac {x}{\sqrt [4]{-1+x^4}}\right ) \\ & = \frac {2}{3} \left (-1+x^4\right )^{3/4}+\frac {1}{4} \text {Subst}\left (\int \frac {1}{\sqrt [4]{-1+x} x} \, dx,x,x^4\right )-\text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {x}{\sqrt [4]{-1+x^4}}\right )-\text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {x}{\sqrt [4]{-1+x^4}}\right ) \\ & = \frac {2}{3} \left (-1+x^4\right )^{3/4}-\arctan \left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\text {arctanh}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )+\text {Subst}\left (\int \frac {x^2}{1+x^4} \, dx,x,\sqrt [4]{-1+x^4}\right ) \\ & = \frac {2}{3} \left (-1+x^4\right )^{3/4}-\arctan \left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\text {arctanh}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\frac {1}{2} \text {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,\sqrt [4]{-1+x^4}\right )+\frac {1}{2} \text {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,\sqrt [4]{-1+x^4}\right ) \\ & = \frac {2}{3} \left (-1+x^4\right )^{3/4}-\arctan \left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\text {arctanh}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )+\frac {1}{4} \text {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\sqrt [4]{-1+x^4}\right )+\frac {1}{4} \text {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\sqrt [4]{-1+x^4}\right )+\frac {\text {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\sqrt [4]{-1+x^4}\right )}{4 \sqrt {2}}+\frac {\text {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\sqrt [4]{-1+x^4}\right )}{4 \sqrt {2}} \\ & = \frac {2}{3} \left (-1+x^4\right )^{3/4}-\arctan \left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\text {arctanh}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )+\frac {\log \left (1-\sqrt {2} \sqrt [4]{-1+x^4}+\sqrt {-1+x^4}\right )}{4 \sqrt {2}}-\frac {\log \left (1+\sqrt {2} \sqrt [4]{-1+x^4}+\sqrt {-1+x^4}\right )}{4 \sqrt {2}}+\frac {\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\sqrt {2} \sqrt [4]{-1+x^4}\right )}{2 \sqrt {2}}-\frac {\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\sqrt {2} \sqrt [4]{-1+x^4}\right )}{2 \sqrt {2}} \\ & = \frac {2}{3} \left (-1+x^4\right )^{3/4}-\arctan \left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\frac {\arctan \left (1-\sqrt {2} \sqrt [4]{-1+x^4}\right )}{2 \sqrt {2}}+\frac {\arctan \left (1+\sqrt {2} \sqrt [4]{-1+x^4}\right )}{2 \sqrt {2}}-\text {arctanh}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )+\frac {\log \left (1-\sqrt {2} \sqrt [4]{-1+x^4}+\sqrt {-1+x^4}\right )}{4 \sqrt {2}}-\frac {\log \left (1+\sqrt {2} \sqrt [4]{-1+x^4}+\sqrt {-1+x^4}\right )}{4 \sqrt {2}} \\ \end{align*}
Time = 5.64 (sec) , antiderivative size = 120, normalized size of antiderivative = 0.96 \[ \int \frac {1-2 x+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx=\frac {2}{3} \left (-1+x^4\right )^{3/4}+\arctan \left (\frac {\sqrt [4]{-1+x^4}}{x}\right )-\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{-1+x^4}}{-1+\sqrt {-1+x^4}}\right )}{2 \sqrt {2}}-\text {arctanh}\left (\frac {\sqrt [4]{-1+x^4}}{x}\right )-\frac {\text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{-1+x^4}}{1+\sqrt {-1+x^4}}\right )}{2 \sqrt {2}} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 10.21 (sec) , antiderivative size = 142, normalized size of antiderivative = 1.14
method | result | size |
meijerg | \(\frac {\sqrt {2}\, \Gamma \left (\frac {3}{4}\right ) {\left (-\operatorname {signum}\left (x^{4}-1\right )\right )}^{\frac {1}{4}} \left (\frac {\pi \sqrt {2}\, x^{4} \operatorname {hypergeom}\left (\left [1, 1, \frac {5}{4}\right ], \left [2, 2\right ], x^{4}\right )}{4 \Gamma \left (\frac {3}{4}\right )}+\frac {\left (-3 \ln \left (2\right )-\frac {\pi }{2}+4 \ln \left (x \right )+i \pi \right ) \pi \sqrt {2}}{\Gamma \left (\frac {3}{4}\right )}\right )}{8 \pi \operatorname {signum}\left (x^{4}-1\right )^{\frac {1}{4}}}+\frac {{\left (-\operatorname {signum}\left (x^{4}-1\right )\right )}^{\frac {1}{4}} x^{4} \operatorname {hypergeom}\left (\left [\frac {1}{4}, 1\right ], \left [2\right ], x^{4}\right )}{2 \operatorname {signum}\left (x^{4}-1\right )^{\frac {1}{4}}}-\frac {2 {\left (-\operatorname {signum}\left (x^{4}-1\right )\right )}^{\frac {1}{4}} x \operatorname {hypergeom}\left (\left [\frac {1}{4}, \frac {1}{4}\right ], \left [\frac {5}{4}\right ], x^{4}\right )}{\operatorname {signum}\left (x^{4}-1\right )^{\frac {1}{4}}}\) | \(142\) |
trager | \(\frac {2 \left (x^{4}-1\right )^{\frac {3}{4}}}{3}+\frac {\ln \left (2 \left (x^{4}-1\right )^{\frac {3}{4}} x -2 x^{2} \sqrt {x^{4}-1}+2 x^{3} \left (x^{4}-1\right )^{\frac {1}{4}}-2 x^{4}+1\right )}{2}+\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \ln \left (2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \sqrt {x^{4}-1}\, x^{2}-2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{4}+2 \left (x^{4}-1\right )^{\frac {3}{4}} x -2 x^{3} \left (x^{4}-1\right )^{\frac {1}{4}}+\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )\right )}{2}+\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )\right ) \ln \left (\frac {-\operatorname {RootOf}\left (\textit {\_Z}^{2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )\right ) x^{4}+2 \operatorname {RootOf}\left (\textit {\_Z}^{2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )\right ) \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \sqrt {x^{4}-1}+2 \left (x^{4}-1\right )^{\frac {3}{4}}-2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \left (x^{4}-1\right )^{\frac {1}{4}}+2 \operatorname {RootOf}\left (\textit {\_Z}^{2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )\right )}{x^{4}}\right )}{4}-\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \operatorname {RootOf}\left (\textit {\_Z}^{2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )\right ) \ln \left (\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )\right ) \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{4}+2 \left (x^{4}-1\right )^{\frac {3}{4}}-2 \sqrt {x^{4}-1}\, \operatorname {RootOf}\left (\textit {\_Z}^{2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )\right )+2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \left (x^{4}-1\right )^{\frac {1}{4}}-2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \operatorname {RootOf}\left (\textit {\_Z}^{2}-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )\right )}{x^{4}}\right )}{4}\) | \(345\) |
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Result contains complex when optimal does not.
Time = 11.53 (sec) , antiderivative size = 288, normalized size of antiderivative = 2.30 \[ \int \frac {1-2 x+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx=-\left (\frac {1}{16} i + \frac {1}{16}\right ) \, \sqrt {2} \log \left (\frac {\sqrt {2} {\left (\left (i + 1\right ) \, x^{4} - 2 i - 2\right )} - \left (2 i - 2\right ) \, \sqrt {2} \sqrt {x^{4} - 1} + 4 \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} - 4 i \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}}{x^{4}}\right ) + \left (\frac {1}{16} i - \frac {1}{16}\right ) \, \sqrt {2} \log \left (\frac {\sqrt {2} {\left (-\left (i - 1\right ) \, x^{4} + 2 i - 2\right )} + \left (2 i + 2\right ) \, \sqrt {2} \sqrt {x^{4} - 1} + 4 \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} + 4 i \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}}{x^{4}}\right ) - \left (\frac {1}{16} i - \frac {1}{16}\right ) \, \sqrt {2} \log \left (\frac {\sqrt {2} {\left (\left (i - 1\right ) \, x^{4} - 2 i + 2\right )} - \left (2 i + 2\right ) \, \sqrt {2} \sqrt {x^{4} - 1} + 4 \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} + 4 i \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}}{x^{4}}\right ) + \left (\frac {1}{16} i + \frac {1}{16}\right ) \, \sqrt {2} \log \left (\frac {\sqrt {2} {\left (-\left (i + 1\right ) \, x^{4} + 2 i + 2\right )} + \left (2 i - 2\right ) \, \sqrt {2} \sqrt {x^{4} - 1} + 4 \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} - 4 i \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}}{x^{4}}\right ) + \frac {2}{3} \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} + \frac {1}{2} \, \arctan \left (2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}} x^{3} + 2 \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} x\right ) + \frac {1}{2} \, \log \left (-2 \, x^{4} + 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}} x^{3} - 2 \, \sqrt {x^{4} - 1} x^{2} + 2 \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} x + 1\right ) \]
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Result contains complex when optimal does not.
Time = 1.44 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.57 \[ \int \frac {1-2 x+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx=- \frac {x e^{- \frac {i \pi }{4}} \Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {1}{4} \\ \frac {5}{4} \end {matrix}\middle | {x^{4}} \right )}}{2 \Gamma \left (\frac {5}{4}\right )} + \frac {2 \left (x^{4} - 1\right )^{\frac {3}{4}}}{3} - \frac {\Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {1}{4} \\ \frac {5}{4} \end {matrix}\middle | {\frac {e^{2 i \pi }}{x^{4}}} \right )}}{4 x \Gamma \left (\frac {5}{4}\right )} \]
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none
Time = 0.30 (sec) , antiderivative size = 155, normalized size of antiderivative = 1.24 \[ \int \frac {1-2 x+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx=\frac {1}{4} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right )}\right ) + \frac {1}{4} \, \sqrt {2} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right )}\right ) - \frac {1}{8} \, \sqrt {2} \log \left (\sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + \sqrt {x^{4} - 1} + 1\right ) + \frac {1}{8} \, \sqrt {2} \log \left (-\sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + \sqrt {x^{4} - 1} + 1\right ) + \frac {2}{3} \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} + \arctan \left (\frac {{\left (x^{4} - 1\right )}^{\frac {1}{4}}}{x}\right ) - \frac {1}{2} \, \log \left (\frac {{\left (x^{4} - 1\right )}^{\frac {1}{4}}}{x} + 1\right ) + \frac {1}{2} \, \log \left (\frac {{\left (x^{4} - 1\right )}^{\frac {1}{4}}}{x} - 1\right ) \]
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\[ \int \frac {1-2 x+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx=\int { \frac {2 \, x^{4} - 2 \, x + 1}{{\left (x^{4} - 1\right )}^{\frac {1}{4}} x} \,d x } \]
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Time = 8.99 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.65 \[ \int \frac {1-2 x+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx=\frac {2\,{\left (x^4-1\right )}^{3/4}}{3}-\frac {2\,x\,{\left (1-x^4\right )}^{1/4}\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{4},\frac {1}{4};\ \frac {5}{4};\ x^4\right )}{{\left (x^4-1\right )}^{1/4}}+\sqrt {2}\,\mathrm {atan}\left (\sqrt {2}\,{\left (x^4-1\right )}^{1/4}\,\left (\frac {1}{2}-\frac {1}{2}{}\mathrm {i}\right )\right )\,\left (\frac {1}{4}-\frac {1}{4}{}\mathrm {i}\right )+\sqrt {2}\,\mathrm {atan}\left (\sqrt {2}\,{\left (x^4-1\right )}^{1/4}\,\left (\frac {1}{2}+\frac {1}{2}{}\mathrm {i}\right )\right )\,\left (\frac {1}{4}+\frac {1}{4}{}\mathrm {i}\right ) \]
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