Integrand size = 17, antiderivative size = 127 \[ \int \frac {\sqrt {x+\sqrt {1+x}}}{x^2} \, dx=-\frac {\sqrt {x+\sqrt {1+x}}}{x}-\frac {1}{4} \arctan \left (\frac {1+2 x-2 \sqrt {x+\sqrt {1+x}}+\sqrt {1+x} \left (3-2 \sqrt {x+\sqrt {1+x}}\right )}{2+2 \sqrt {1+x}-2 \sqrt {x+\sqrt {1+x}}}\right )-\frac {3}{2} \text {arctanh}\left (1-\sqrt {1+x}+\sqrt {x+\sqrt {1+x}}\right ) \]
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Time = 0.09 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.65, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.294, Rules used = {1028, 1047, 738, 212, 210} \[ \int \frac {\sqrt {x+\sqrt {1+x}}}{x^2} \, dx=-\frac {1}{4} \arctan \left (\frac {\sqrt {x+1}+3}{2 \sqrt {x+\sqrt {x+1}}}\right )+\frac {3}{4} \text {arctanh}\left (\frac {1-3 \sqrt {x+1}}{2 \sqrt {x+\sqrt {x+1}}}\right )-\frac {\sqrt {x+\sqrt {x+1}}}{x} \]
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Rule 210
Rule 212
Rule 738
Rule 1028
Rule 1047
Rubi steps \begin{align*} \text {integral}& = 2 \text {Subst}\left (\int \frac {x \sqrt {-1+x+x^2}}{\left (-1+x^2\right )^2} \, dx,x,\sqrt {1+x}\right ) \\ & = -\frac {\sqrt {x+\sqrt {1+x}}}{x}+\text {Subst}\left (\int \frac {\frac {1}{2}+x}{\left (-1+x^2\right ) \sqrt {-1+x+x^2}} \, dx,x,\sqrt {1+x}\right ) \\ & = -\frac {\sqrt {x+\sqrt {1+x}}}{x}+\frac {1}{4} \text {Subst}\left (\int \frac {1}{(1+x) \sqrt {-1+x+x^2}} \, dx,x,\sqrt {1+x}\right )+\frac {3}{4} \text {Subst}\left (\int \frac {1}{(-1+x) \sqrt {-1+x+x^2}} \, dx,x,\sqrt {1+x}\right ) \\ & = -\frac {\sqrt {x+\sqrt {1+x}}}{x}-\frac {1}{2} \text {Subst}\left (\int \frac {1}{-4-x^2} \, dx,x,\frac {-3-\sqrt {1+x}}{\sqrt {x+\sqrt {1+x}}}\right )-\frac {3}{2} \text {Subst}\left (\int \frac {1}{4-x^2} \, dx,x,\frac {-1+3 \sqrt {1+x}}{\sqrt {x+\sqrt {1+x}}}\right ) \\ & = -\frac {\sqrt {x+\sqrt {1+x}}}{x}-\frac {1}{4} \arctan \left (\frac {3+\sqrt {1+x}}{2 \sqrt {x+\sqrt {1+x}}}\right )+\frac {3}{4} \text {arctanh}\left (\frac {1-3 \sqrt {1+x}}{2 \sqrt {x+\sqrt {1+x}}}\right ) \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.61 \[ \int \frac {\sqrt {x+\sqrt {1+x}}}{x^2} \, dx=-\frac {\sqrt {x+\sqrt {1+x}}}{x}-\frac {1}{2} \arctan \left (1+\sqrt {1+x}-\sqrt {x+\sqrt {1+x}}\right )-\frac {3}{2} \text {arctanh}\left (1-\sqrt {1+x}+\sqrt {x+\sqrt {1+x}}\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. \(297\) vs. \(2(97)=194\).
Time = 0.05 (sec) , antiderivative size = 298, normalized size of antiderivative = 2.35
method | result | size |
derivativedivides | \(-\frac {\left (\left (-1+\sqrt {1+x}\right )^{2}+3 \sqrt {1+x}-2\right )^{\frac {3}{2}}}{2 \left (-1+\sqrt {1+x}\right )}+\frac {3 \sqrt {\left (-1+\sqrt {1+x}\right )^{2}+3 \sqrt {1+x}-2}}{4}+\frac {\ln \left (\frac {1}{2}+\sqrt {1+x}+\sqrt {\left (-1+\sqrt {1+x}\right )^{2}+3 \sqrt {1+x}-2}\right )}{2}-\frac {3 \,\operatorname {arctanh}\left (\frac {-1+3 \sqrt {1+x}}{2 \sqrt {\left (-1+\sqrt {1+x}\right )^{2}+3 \sqrt {1+x}-2}}\right )}{4}+\frac {\left (2 \sqrt {1+x}+1\right ) \sqrt {\left (-1+\sqrt {1+x}\right )^{2}+3 \sqrt {1+x}-2}}{4}-\frac {\left (\left (1+\sqrt {1+x}\right )^{2}-\sqrt {1+x}-2\right )^{\frac {3}{2}}}{2 \left (1+\sqrt {1+x}\right )}-\frac {\sqrt {\left (1+\sqrt {1+x}\right )^{2}-\sqrt {1+x}-2}}{4}-\frac {\ln \left (\frac {1}{2}+\sqrt {1+x}+\sqrt {\left (1+\sqrt {1+x}\right )^{2}-\sqrt {1+x}-2}\right )}{2}+\frac {\arctan \left (\frac {-3-\sqrt {1+x}}{2 \sqrt {\left (1+\sqrt {1+x}\right )^{2}-\sqrt {1+x}-2}}\right )}{4}+\frac {\left (2 \sqrt {1+x}+1\right ) \sqrt {\left (1+\sqrt {1+x}\right )^{2}-\sqrt {1+x}-2}}{4}\) | \(298\) |
default | \(-\frac {\left (\left (-1+\sqrt {1+x}\right )^{2}+3 \sqrt {1+x}-2\right )^{\frac {3}{2}}}{2 \left (-1+\sqrt {1+x}\right )}+\frac {3 \sqrt {\left (-1+\sqrt {1+x}\right )^{2}+3 \sqrt {1+x}-2}}{4}+\frac {\ln \left (\frac {1}{2}+\sqrt {1+x}+\sqrt {\left (-1+\sqrt {1+x}\right )^{2}+3 \sqrt {1+x}-2}\right )}{2}-\frac {3 \,\operatorname {arctanh}\left (\frac {-1+3 \sqrt {1+x}}{2 \sqrt {\left (-1+\sqrt {1+x}\right )^{2}+3 \sqrt {1+x}-2}}\right )}{4}+\frac {\left (2 \sqrt {1+x}+1\right ) \sqrt {\left (-1+\sqrt {1+x}\right )^{2}+3 \sqrt {1+x}-2}}{4}-\frac {\left (\left (1+\sqrt {1+x}\right )^{2}-\sqrt {1+x}-2\right )^{\frac {3}{2}}}{2 \left (1+\sqrt {1+x}\right )}-\frac {\sqrt {\left (1+\sqrt {1+x}\right )^{2}-\sqrt {1+x}-2}}{4}-\frac {\ln \left (\frac {1}{2}+\sqrt {1+x}+\sqrt {\left (1+\sqrt {1+x}\right )^{2}-\sqrt {1+x}-2}\right )}{2}+\frac {\arctan \left (\frac {-3-\sqrt {1+x}}{2 \sqrt {\left (1+\sqrt {1+x}\right )^{2}-\sqrt {1+x}-2}}\right )}{4}+\frac {\left (2 \sqrt {1+x}+1\right ) \sqrt {\left (1+\sqrt {1+x}\right )^{2}-\sqrt {1+x}-2}}{4}\) | \(298\) |
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Time = 1.93 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.64 \[ \int \frac {\sqrt {x+\sqrt {1+x}}}{x^2} \, dx=\frac {x \arctan \left (\frac {2 \, \sqrt {x + \sqrt {x + 1}} {\left (\sqrt {x + 1} - 3\right )}}{x - 8}\right ) + 3 \, x \log \left (\frac {2 \, \sqrt {x + \sqrt {x + 1}} {\left (\sqrt {x + 1} + 1\right )} - 3 \, x - 2 \, \sqrt {x + 1} - 2}{x}\right ) - 4 \, \sqrt {x + \sqrt {x + 1}}}{4 \, x} \]
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\[ \int \frac {\sqrt {x+\sqrt {1+x}}}{x^2} \, dx=\int \frac {\sqrt {x + \sqrt {x + 1}}}{x^{2}}\, dx \]
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\[ \int \frac {\sqrt {x+\sqrt {1+x}}}{x^2} \, dx=\int { \frac {\sqrt {x + \sqrt {x + 1}}}{x^{2}} \,d x } \]
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Time = 0.48 (sec) , antiderivative size = 188, normalized size of antiderivative = 1.48 \[ \int \frac {\sqrt {x+\sqrt {1+x}}}{x^2} \, dx=-\frac {2 \, {\left (\sqrt {x + \sqrt {x + 1}} - \sqrt {x + 1}\right )}^{3} - 3 \, {\left (\sqrt {x + \sqrt {x + 1}} - \sqrt {x + 1}\right )}^{2} - \sqrt {x + \sqrt {x + 1}} + \sqrt {x + 1} + 1}{{\left (\sqrt {x + \sqrt {x + 1}} - \sqrt {x + 1}\right )}^{4} - 2 \, {\left (\sqrt {x + \sqrt {x + 1}} - \sqrt {x + 1}\right )}^{2} + 4 \, \sqrt {x + \sqrt {x + 1}} - 4 \, \sqrt {x + 1}} + \frac {1}{2} \, \arctan \left (\sqrt {x + \sqrt {x + 1}} - \sqrt {x + 1} - 1\right ) - \frac {3}{4} \, \log \left ({\left | \sqrt {x + \sqrt {x + 1}} - \sqrt {x + 1} + 2 \right |}\right ) + \frac {3}{4} \, \log \left ({\left | \sqrt {x + \sqrt {x + 1}} - \sqrt {x + 1} \right |}\right ) \]
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Timed out. \[ \int \frac {\sqrt {x+\sqrt {1+x}}}{x^2} \, dx=\int \frac {\sqrt {x+\sqrt {x+1}}}{x^2} \,d x \]
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