Integrand size = 35, antiderivative size = 131 \[ \int \frac {-2+a x^4}{\sqrt [4]{b+a x^4} \left (-b+a x^4+2 x^8\right )} \, dx=-\frac {\text {RootSum}\left [2 a^2-2 b-3 a \text {$\#$1}^4+\text {$\#$1}^8\&,\frac {-2 a \log (x)-a b \log (x)+2 a \log \left (\sqrt [4]{b+a x^4}-x \text {$\#$1}\right )+a b \log \left (\sqrt [4]{b+a x^4}-x \text {$\#$1}\right )+2 \log (x) \text {$\#$1}^4-2 \log \left (\sqrt [4]{b+a x^4}-x \text {$\#$1}\right ) \text {$\#$1}^4}{3 a \text {$\#$1}-2 \text {$\#$1}^5}\&\right ]}{4 b} \]
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Leaf count is larger than twice the leaf count of optimal. \(491\) vs. \(2(131)=262\).
Time = 0.80 (sec) , antiderivative size = 491, normalized size of antiderivative = 3.75, number of steps used = 10, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {6860, 385, 218, 214, 211} \[ \int \frac {-2+a x^4}{\sqrt [4]{b+a x^4} \left (-b+a x^4+2 x^8\right )} \, dx=\frac {\left (a-\frac {a^2+8}{\sqrt {a^2+8 b}}\right ) \arctan \left (\frac {x \sqrt [4]{-a \sqrt {a^2+8 b}+a^2-4 b}}{\sqrt [4]{a-\sqrt {a^2+8 b}} \sqrt [4]{a x^4+b}}\right )}{2 \left (a-\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{-a \sqrt {a^2+8 b}+a^2-4 b}}+\frac {\left (\frac {a^2+8}{\sqrt {a^2+8 b}}+a\right ) \arctan \left (\frac {x \sqrt [4]{a \sqrt {a^2+8 b}+a^2-4 b}}{\sqrt [4]{\sqrt {a^2+8 b}+a} \sqrt [4]{a x^4+b}}\right )}{2 \left (\sqrt {a^2+8 b}+a\right )^{3/4} \sqrt [4]{a \sqrt {a^2+8 b}+a^2-4 b}}+\frac {\left (a-\frac {a^2+8}{\sqrt {a^2+8 b}}\right ) \text {arctanh}\left (\frac {x \sqrt [4]{-a \sqrt {a^2+8 b}+a^2-4 b}}{\sqrt [4]{a-\sqrt {a^2+8 b}} \sqrt [4]{a x^4+b}}\right )}{2 \left (a-\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{-a \sqrt {a^2+8 b}+a^2-4 b}}+\frac {\left (\frac {a^2+8}{\sqrt {a^2+8 b}}+a\right ) \text {arctanh}\left (\frac {x \sqrt [4]{a \sqrt {a^2+8 b}+a^2-4 b}}{\sqrt [4]{\sqrt {a^2+8 b}+a} \sqrt [4]{a x^4+b}}\right )}{2 \left (\sqrt {a^2+8 b}+a\right )^{3/4} \sqrt [4]{a \sqrt {a^2+8 b}+a^2-4 b}} \]
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Rule 211
Rule 214
Rule 218
Rule 385
Rule 6860
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a+\frac {-8-a^2}{\sqrt {a^2+8 b}}}{\left (a-\sqrt {a^2+8 b}+4 x^4\right ) \sqrt [4]{b+a x^4}}+\frac {a-\frac {-8-a^2}{\sqrt {a^2+8 b}}}{\left (a+\sqrt {a^2+8 b}+4 x^4\right ) \sqrt [4]{b+a x^4}}\right ) \, dx \\ & = \left (a-\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \int \frac {1}{\left (a-\sqrt {a^2+8 b}+4 x^4\right ) \sqrt [4]{b+a x^4}} \, dx+\left (a+\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \int \frac {1}{\left (a+\sqrt {a^2+8 b}+4 x^4\right ) \sqrt [4]{b+a x^4}} \, dx \\ & = \left (a-\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \text {Subst}\left (\int \frac {1}{a-\sqrt {a^2+8 b}-\left (-4 b+a \left (a-\sqrt {a^2+8 b}\right )\right ) x^4} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )+\left (a+\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \text {Subst}\left (\int \frac {1}{a+\sqrt {a^2+8 b}-\left (-4 b+a \left (a+\sqrt {a^2+8 b}\right )\right ) x^4} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right ) \\ & = \frac {\left (a-\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a-\sqrt {a^2+8 b}}-\sqrt {a^2-4 b-a \sqrt {a^2+8 b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {a-\sqrt {a^2+8 b}}}+\frac {\left (a-\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a-\sqrt {a^2+8 b}}+\sqrt {a^2-4 b-a \sqrt {a^2+8 b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {a-\sqrt {a^2+8 b}}}+\frac {\left (a+\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+\sqrt {a^2+8 b}}-\sqrt {a^2-4 b+a \sqrt {a^2+8 b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {a+\sqrt {a^2+8 b}}}+\frac {\left (a+\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+\sqrt {a^2+8 b}}+\sqrt {a^2-4 b+a \sqrt {a^2+8 b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {a+\sqrt {a^2+8 b}}} \\ & = \frac {\left (a-\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \arctan \left (\frac {\sqrt [4]{a^2-4 b-a \sqrt {a^2+8 b}} x}{\sqrt [4]{a-\sqrt {a^2+8 b}} \sqrt [4]{b+a x^4}}\right )}{2 \left (a-\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{a^2-4 b-a \sqrt {a^2+8 b}}}+\frac {\left (a+\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \arctan \left (\frac {\sqrt [4]{a^2-4 b+a \sqrt {a^2+8 b}} x}{\sqrt [4]{a+\sqrt {a^2+8 b}} \sqrt [4]{b+a x^4}}\right )}{2 \left (a+\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{a^2-4 b+a \sqrt {a^2+8 b}}}+\frac {\left (a-\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \text {arctanh}\left (\frac {\sqrt [4]{a^2-4 b-a \sqrt {a^2+8 b}} x}{\sqrt [4]{a-\sqrt {a^2+8 b}} \sqrt [4]{b+a x^4}}\right )}{2 \left (a-\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{a^2-4 b-a \sqrt {a^2+8 b}}}+\frac {\left (a+\frac {8+a^2}{\sqrt {a^2+8 b}}\right ) \text {arctanh}\left (\frac {\sqrt [4]{a^2-4 b+a \sqrt {a^2+8 b}} x}{\sqrt [4]{a+\sqrt {a^2+8 b}} \sqrt [4]{b+a x^4}}\right )}{2 \left (a+\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{a^2-4 b+a \sqrt {a^2+8 b}}} \\ \end{align*}
Time = 1.24 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.00 \[ \int \frac {-2+a x^4}{\sqrt [4]{b+a x^4} \left (-b+a x^4+2 x^8\right )} \, dx=-\frac {\text {RootSum}\left [2 a^2-2 b-3 a \text {$\#$1}^4+\text {$\#$1}^8\&,\frac {2 a \log (x)+a b \log (x)-2 a \log \left (\sqrt [4]{b+a x^4}-x \text {$\#$1}\right )-a b \log \left (\sqrt [4]{b+a x^4}-x \text {$\#$1}\right )-2 \log (x) \text {$\#$1}^4+2 \log \left (\sqrt [4]{b+a x^4}-x \text {$\#$1}\right ) \text {$\#$1}^4}{-3 a \text {$\#$1}+2 \text {$\#$1}^5}\&\right ]}{4 b} \]
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Time = 0.32 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.54
method | result | size |
pseudoelliptic | \(-\frac {\munderset {\textit {\_R} =\operatorname {RootOf}\left (\textit {\_Z}^{8}-3 a \,\textit {\_Z}^{4}+2 a^{2}-2 b \right )}{\sum }\frac {\left (-2 \textit {\_R}^{4}+a \left (2+b \right )\right ) \ln \left (\frac {-\textit {\_R} x +\left (a \,x^{4}+b \right )^{\frac {1}{4}}}{x}\right )}{-2 \textit {\_R}^{5}+3 \textit {\_R} a}}{4 b}\) | \(71\) |
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Timed out. \[ \int \frac {-2+a x^4}{\sqrt [4]{b+a x^4} \left (-b+a x^4+2 x^8\right )} \, dx=\text {Timed out} \]
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Not integrable
Time = 58.73 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.22 \[ \int \frac {-2+a x^4}{\sqrt [4]{b+a x^4} \left (-b+a x^4+2 x^8\right )} \, dx=\int \frac {a x^{4} - 2}{\sqrt [4]{a x^{4} + b} \left (a x^{4} - b + 2 x^{8}\right )}\, dx \]
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Not integrable
Time = 0.22 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.27 \[ \int \frac {-2+a x^4}{\sqrt [4]{b+a x^4} \left (-b+a x^4+2 x^8\right )} \, dx=\int { \frac {a x^{4} - 2}{{\left (2 \, x^{8} + a x^{4} - b\right )} {\left (a x^{4} + b\right )}^{\frac {1}{4}}} \,d x } \]
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Not integrable
Time = 1.67 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.27 \[ \int \frac {-2+a x^4}{\sqrt [4]{b+a x^4} \left (-b+a x^4+2 x^8\right )} \, dx=\int { \frac {a x^{4} - 2}{{\left (2 \, x^{8} + a x^{4} - b\right )} {\left (a x^{4} + b\right )}^{\frac {1}{4}}} \,d x } \]
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Not integrable
Time = 5.58 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.27 \[ \int \frac {-2+a x^4}{\sqrt [4]{b+a x^4} \left (-b+a x^4+2 x^8\right )} \, dx=\int \frac {a\,x^4-2}{{\left (a\,x^4+b\right )}^{1/4}\,\left (2\,x^8+a\,x^4-b\right )} \,d x \]
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