Integrand size = 30, antiderivative size = 134 \[ \int \frac {\left (-3+x^4\right ) \left (1+x^4\right )^{2/3}}{x^3 \left (2+x^3+2 x^4\right )} \, dx=\frac {3 \left (1+x^4\right )^{2/3}}{4 x^2}+\frac {\sqrt {3} \arctan \left (\frac {\sqrt {3} x}{-x+2 \sqrt [3]{2} \sqrt [3]{1+x^4}}\right )}{2\ 2^{2/3}}+\frac {\log \left (x+\sqrt [3]{2} \sqrt [3]{1+x^4}\right )}{2\ 2^{2/3}}-\frac {\log \left (x^2-\sqrt [3]{2} x \sqrt [3]{1+x^4}+2^{2/3} \left (1+x^4\right )^{2/3}\right )}{4\ 2^{2/3}} \]
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\[ \int \frac {\left (-3+x^4\right ) \left (1+x^4\right )^{2/3}}{x^3 \left (2+x^3+2 x^4\right )} \, dx=\int \frac {\left (-3+x^4\right ) \left (1+x^4\right )^{2/3}}{x^3 \left (2+x^3+2 x^4\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {3 \left (1+x^4\right )^{2/3}}{2 x^3}+\frac {(3+8 x) \left (1+x^4\right )^{2/3}}{2 \left (2+x^3+2 x^4\right )}\right ) \, dx \\ & = \frac {1}{2} \int \frac {(3+8 x) \left (1+x^4\right )^{2/3}}{2+x^3+2 x^4} \, dx-\frac {3}{2} \int \frac {\left (1+x^4\right )^{2/3}}{x^3} \, dx \\ & = \frac {1}{2} \int \left (\frac {3 \left (1+x^4\right )^{2/3}}{2+x^3+2 x^4}+\frac {8 x \left (1+x^4\right )^{2/3}}{2+x^3+2 x^4}\right ) \, dx-\frac {3}{4} \text {Subst}\left (\int \frac {\left (1+x^2\right )^{2/3}}{x^2} \, dx,x,x^2\right ) \\ & = \frac {3 \left (1+x^4\right )^{2/3}}{4 x^2}+\frac {3}{2} \int \frac {\left (1+x^4\right )^{2/3}}{2+x^3+2 x^4} \, dx+4 \int \frac {x \left (1+x^4\right )^{2/3}}{2+x^3+2 x^4} \, dx-\text {Subst}\left (\int \frac {1}{\sqrt [3]{1+x^2}} \, dx,x,x^2\right ) \\ & = \frac {3 \left (1+x^4\right )^{2/3}}{4 x^2}+\frac {3}{2} \int \frac {\left (1+x^4\right )^{2/3}}{2+x^3+2 x^4} \, dx+4 \int \frac {x \left (1+x^4\right )^{2/3}}{2+x^3+2 x^4} \, dx-\frac {\left (3 \sqrt {x^4}\right ) \text {Subst}\left (\int \frac {x}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1+x^4}\right )}{2 x^2} \\ & = \frac {3 \left (1+x^4\right )^{2/3}}{4 x^2}+\frac {3}{2} \int \frac {\left (1+x^4\right )^{2/3}}{2+x^3+2 x^4} \, dx+4 \int \frac {x \left (1+x^4\right )^{2/3}}{2+x^3+2 x^4} \, dx+\frac {\left (3 \sqrt {x^4}\right ) \text {Subst}\left (\int \frac {1+\sqrt {3}-x}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1+x^4}\right )}{2 x^2}-\frac {\left (3 \left (1+\sqrt {3}\right ) \sqrt {x^4}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1+x^4}\right )}{2 x^2} \\ & = \frac {3 \left (1+x^4\right )^{2/3}}{4 x^2}+\frac {3 x^2}{1-\sqrt {3}-\sqrt [3]{1+x^4}}-\frac {3 \sqrt [4]{3} \sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{1+x^4}\right ) \sqrt {\frac {1+\sqrt [3]{1+x^4}+\left (1+x^4\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1+x^4}\right )^2}} E\left (\arcsin \left (\frac {1+\sqrt {3}-\sqrt [3]{1+x^4}}{1-\sqrt {3}-\sqrt [3]{1+x^4}}\right )|-7+4 \sqrt {3}\right )}{2 x^2 \sqrt {-\frac {1-\sqrt [3]{1+x^4}}{\left (1-\sqrt {3}-\sqrt [3]{1+x^4}\right )^2}}}+\frac {\sqrt {2} 3^{3/4} \left (1-\sqrt [3]{1+x^4}\right ) \sqrt {\frac {1+\sqrt [3]{1+x^4}+\left (1+x^4\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1+x^4}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {1+\sqrt {3}-\sqrt [3]{1+x^4}}{1-\sqrt {3}-\sqrt [3]{1+x^4}}\right ),-7+4 \sqrt {3}\right )}{x^2 \sqrt {-\frac {1-\sqrt [3]{1+x^4}}{\left (1-\sqrt {3}-\sqrt [3]{1+x^4}\right )^2}}}+\frac {3}{2} \int \frac {\left (1+x^4\right )^{2/3}}{2+x^3+2 x^4} \, dx+4 \int \frac {x \left (1+x^4\right )^{2/3}}{2+x^3+2 x^4} \, dx \\ \end{align*}
Time = 1.25 (sec) , antiderivative size = 128, normalized size of antiderivative = 0.96 \[ \int \frac {\left (-3+x^4\right ) \left (1+x^4\right )^{2/3}}{x^3 \left (2+x^3+2 x^4\right )} \, dx=\frac {1}{8} \left (\frac {6 \left (1+x^4\right )^{2/3}}{x^2}-2 \sqrt [3]{2} \sqrt {3} \arctan \left (\frac {\sqrt {3} x}{x-2 \sqrt [3]{2} \sqrt [3]{1+x^4}}\right )+2 \sqrt [3]{2} \log \left (x+\sqrt [3]{2} \sqrt [3]{1+x^4}\right )-\sqrt [3]{2} \log \left (x^2-\sqrt [3]{2} x \sqrt [3]{1+x^4}+2^{2/3} \left (1+x^4\right )^{2/3}\right )\right ) \]
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Time = 74.04 (sec) , antiderivative size = 118, normalized size of antiderivative = 0.88
method | result | size |
pseudoelliptic | \(\frac {2 \,2^{\frac {1}{3}} x^{2} \ln \left (\frac {2^{\frac {2}{3}} x +2 \left (x^{4}+1\right )^{\frac {1}{3}}}{x}\right )+6 \left (x^{4}+1\right )^{\frac {2}{3}}-2^{\frac {1}{3}} x^{2} \left (-2 \arctan \left (\frac {\sqrt {3}\, \left (x -2 \,2^{\frac {1}{3}} \left (x^{4}+1\right )^{\frac {1}{3}}\right )}{3 x}\right ) \sqrt {3}+\ln \left (\frac {-2^{\frac {2}{3}} x \left (x^{4}+1\right )^{\frac {1}{3}}+2^{\frac {1}{3}} x^{2}+2 \left (x^{4}+1\right )^{\frac {2}{3}}}{x^{2}}\right )+\ln \left (2\right )\right )}{8 x^{2}}\) | \(118\) |
risch | \(\text {Expression too large to display}\) | \(645\) |
trager | \(\text {Expression too large to display}\) | \(1469\) |
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Leaf count of result is larger than twice the leaf count of optimal. 391 vs. \(2 (97) = 194\).
Time = 64.75 (sec) , antiderivative size = 391, normalized size of antiderivative = 2.92 \[ \int \frac {\left (-3+x^4\right ) \left (1+x^4\right )^{2/3}}{x^3 \left (2+x^3+2 x^4\right )} \, dx=\frac {4 \cdot 4^{\frac {1}{6}} \sqrt {3} x^{2} \arctan \left (\frac {4^{\frac {1}{6}} \sqrt {3} {\left (12 \cdot 4^{\frac {2}{3}} {\left (2 \, x^{9} - x^{8} - x^{7} + 4 \, x^{5} - x^{4} + 2 \, x\right )} {\left (x^{4} + 1\right )}^{\frac {2}{3}} - 4^{\frac {1}{3}} {\left (8 \, x^{12} - 60 \, x^{11} + 24 \, x^{10} + x^{9} + 24 \, x^{8} - 120 \, x^{7} + 24 \, x^{6} + 24 \, x^{4} - 60 \, x^{3} + 8\right )} - 12 \, {\left (4 \, x^{10} - 14 \, x^{9} + x^{8} + 8 \, x^{6} - 14 \, x^{5} + 4 \, x^{2}\right )} {\left (x^{4} + 1\right )}^{\frac {1}{3}}\right )}}{6 \, {\left (8 \, x^{12} + 12 \, x^{11} - 48 \, x^{10} + x^{9} + 24 \, x^{8} + 24 \, x^{7} - 48 \, x^{6} + 24 \, x^{4} + 12 \, x^{3} + 8\right )}}\right ) + 2 \cdot 4^{\frac {2}{3}} x^{2} \log \left (-\frac {6 \cdot 4^{\frac {1}{3}} {\left (x^{4} + 1\right )}^{\frac {1}{3}} x^{2} + 4^{\frac {2}{3}} {\left (2 \, x^{4} + x^{3} + 2\right )} + 12 \, {\left (x^{4} + 1\right )}^{\frac {2}{3}} x}{2 \, x^{4} + x^{3} + 2}\right ) - 4^{\frac {2}{3}} x^{2} \log \left (-\frac {6 \cdot 4^{\frac {2}{3}} {\left (x^{5} - x^{4} + x\right )} {\left (x^{4} + 1\right )}^{\frac {2}{3}} - 4^{\frac {1}{3}} {\left (4 \, x^{8} - 14 \, x^{7} + x^{6} + 8 \, x^{4} - 14 \, x^{3} + 4\right )} - 6 \, {\left (4 \, x^{6} - x^{5} + 4 \, x^{2}\right )} {\left (x^{4} + 1\right )}^{\frac {1}{3}}}{4 \, x^{8} + 4 \, x^{7} + x^{6} + 8 \, x^{4} + 4 \, x^{3} + 4}\right ) + 36 \, {\left (x^{4} + 1\right )}^{\frac {2}{3}}}{48 \, x^{2}} \]
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Timed out. \[ \int \frac {\left (-3+x^4\right ) \left (1+x^4\right )^{2/3}}{x^3 \left (2+x^3+2 x^4\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {\left (-3+x^4\right ) \left (1+x^4\right )^{2/3}}{x^3 \left (2+x^3+2 x^4\right )} \, dx=\int { \frac {{\left (x^{4} + 1\right )}^{\frac {2}{3}} {\left (x^{4} - 3\right )}}{{\left (2 \, x^{4} + x^{3} + 2\right )} x^{3}} \,d x } \]
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\[ \int \frac {\left (-3+x^4\right ) \left (1+x^4\right )^{2/3}}{x^3 \left (2+x^3+2 x^4\right )} \, dx=\int { \frac {{\left (x^{4} + 1\right )}^{\frac {2}{3}} {\left (x^{4} - 3\right )}}{{\left (2 \, x^{4} + x^{3} + 2\right )} x^{3}} \,d x } \]
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Timed out. \[ \int \frac {\left (-3+x^4\right ) \left (1+x^4\right )^{2/3}}{x^3 \left (2+x^3+2 x^4\right )} \, dx=\int \frac {{\left (x^4+1\right )}^{2/3}\,\left (x^4-3\right )}{x^3\,\left (2\,x^4+x^3+2\right )} \,d x \]
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